nếu trả lời như bn mk ko cần

a)=1/2

b)=10

c)=7/4

trả lời cụ thể nhé

a) \(\frac{2.7.13}{26.35}=\frac{2.7.13}{2.13.7.5}=\frac{1}{5}\)

b) \(\frac{3.5.11.13}{33.35.37}=\frac{3.5.11.13}{3.11.7.5.37}=\frac{13}{259}\)

c) \(\frac{23.5-23}{4-27}=\frac{23.\left(5-1\right)}{-23}=\frac{4}{-1}=-4\)

d) \(\frac{1717-101}{2828+404}=\frac{101.17-101}{404.7+404}=\frac{101.\left(17-1\right)}{404.\left(7+1\right)}=\frac{101.16}{404.8}=\frac{101.2.8}{101.4.8}=\frac{1}{2}\)

1; \(\frac{1717-101}{2828+202}=\frac{101\cdot17-101\cdot1}{202\cdot14+202}=\frac{101\cdot\left(17-1\right)}{202\cdot\left(14+1\right)}\)

\(=\frac12\cdot\frac{16}{15}=\frac{8}{15}\)

2: \(\frac{-13\cdot6+12\cdot5}{6\cdot\left(-7\right)-\left(-4\right)\cdot6}=\frac{6\left(-13+2\cdot5\right)}{6\cdot\left(-7\right)+4\cdot6}=\frac{6\cdot\left(-13+10\right)}{6\left(-7+4\right)}\)

\(=\frac{-13+10}{-7+4}=\frac{-3}{-3}=1\)

3: \(\frac{3\cdot6+2\cdot9\cdot5-18\cdot\left(-4\right)}{7\cdot\left(-7\right)+12\cdot\left(-7\right)+7}=\frac{18+18\cdot5+18\cdot4}{\left(-7\right)\left(7+12-1\right)}\)

\(=\frac{18\cdot10}{-7\cdot18}=\frac{-10}{7}\)

a) \(\dfrac{2\cdot7\cdot13}{26\cdot35}=\dfrac{2\cdot7\cdot13}{2\cdot13\cdot5\cdot7}=\dfrac{1}{5}\)

b) \(\dfrac{31\cdot7-13}{4-35}=\dfrac{217-13}{-31}=\dfrac{-204}{31}\)

c) \(\dfrac{32\cdot7-32\cdot4}{38-35}=\dfrac{32\cdot\left(7-4\right)}{3}=\dfrac{32\cdot3}{3}=32\)

d) \(\dfrac{1717-101}{2828+202}=\dfrac{1616}{3030}=\dfrac{8}{15}\)

e) \(\dfrac{3\cdot6+2\cdot9\cdot5-18\cdot\left(-4\right)}{7\cdot\left(-7\right)+12\cdot\left(-7\right)+7}\)

\(=\dfrac{18+18\cdot5+18\cdot4}{7\cdot\left(-7\right)-12\cdot7+7}\)

\(=\dfrac{18\cdot\left(1+5+4\right)}{7\cdot\left(-7-12+1\right)}\)

\(=\dfrac{18\cdot10}{7\cdot\left(-18\right)}\)

\(=\dfrac{-10}{7}\)