(11 / 29 + 2 / 29 + 16 / 29 ) . 9 / 10

1 . 9/10 = 9/10

\(\dfrac{9}{10}\times\left(\dfrac{11}{29}+\dfrac{2}{29}+\dfrac{16}{29}\right)=\dfrac{9}{10}\times\dfrac{29}{29}=\dfrac{9}{10}\times1=\dfrac{9}{10}\)

200/2009

\(\frac{\frac{9}{11}+\frac{9}{29}-\frac{9}{2019}}{1+\frac{11}{29}-\frac{11}{2019}}\\ =\frac{9}{11}.\)

\(\frac{29}{9}.\frac{109}{7}-\frac{29}{9}.\frac{57}{7}+\frac{29}{9}.\frac{12}{7}-\frac{29}{9}.\frac{1}{7}\)

= \(\frac{29}{9}.\left(\frac{109}{7}-\frac{57}{7}+\frac{12}{7}-\frac{1}{7}\right)\)

= \(\frac{29}{9}.\frac{63}{7}\)

=\(\frac{29}{9}.9\)

=\(\frac{29.9}{9}\)

=\(\frac{261}{9}\)

= \(29\)

hứ 7 nộp rùi giải giúp mình à

Được cập nhật 10 giờ trước (09:01)

Toán lớp 6

Chau Nguyen Van 9 giờ trước (09:40)
 Báo cáo sai phạm

299 .1097 −299 .577 +299 .127 −299 .17 

= 299 .(1097 −577 +127 −17 )

= 299 .637 

=299 .9

=29.99 

=2619 

= 

Sửa đề: \(\dfrac{1}{1.9}\rightarrow\dfrac{9}{9.19}\)

Giải:

\(N=\dfrac{9}{9.19}+\dfrac{9}{19.29}+\dfrac{9}{29.39}+...+\dfrac{9}{2019.2029}\) 

\(N=\dfrac{9}{10}.\left(\dfrac{10}{9.19}+\dfrac{10}{19.29}+\dfrac{10}{29.39}+...+\dfrac{10}{2019.2029}\right)\) 

\(N=\dfrac{9}{10}.\left(\dfrac{1}{9}-\dfrac{1}{19}+\dfrac{1}{19}-\dfrac{1}{29}+\dfrac{1}{29}-\dfrac{1}{39}+...+\dfrac{1}{2019}-\dfrac{1}{2029}\right)\) 

\(N=\dfrac{9}{10}.\left(\dfrac{1}{9}-\dfrac{1}{2029}\right)\) 

\(N=\dfrac{9}{10}.\dfrac{2020}{18261}\) 

\(N=\dfrac{202}{2029}\)

là thứ tư

222222222222222222222

a) \(\left(\dfrac{3}{29}-\dfrac{1}{5}\right)\cdot\dfrac{29}{3}\)

\(=\dfrac{3}{29}\cdot\dfrac{29}{3}-\dfrac{1}{5}\cdot\dfrac{29}{3}\)

\(=1-\dfrac{29}{15}\)

\(=\dfrac{15-29}{15}\)

\(=-\dfrac{14}{15}\) 

b) \(\dfrac{3}{4}\cdot\dfrac{7}{9}+\dfrac{1}{4}\cdot\dfrac{7}{9}\)

\(=\dfrac{7}{9}\cdot\left(\dfrac{1}{4}+\dfrac{3}{4}\right)\)

\(=\dfrac{7}{9}\cdot1\)

\(=\dfrac{7}{9}\)

c) \(\dfrac{1}{7}\cdot\dfrac{5}{9}+\dfrac{5}{9}\cdot\dfrac{1}{7}+\dfrac{5}{9}\cdot\dfrac{3}{7}\) 

\(=\dfrac{5}{9}\cdot\left(\dfrac{1}{7}+\dfrac{1}{7}+\dfrac{3}{7}\right)\)

\(=\dfrac{5}{9}\cdot\dfrac{5}{7}\)

\(=\dfrac{25}{63}\)

d) \(4\cdot11\cdot\dfrac{3}{4}\cdot\dfrac{9}{121}\)

\(=\left(4\cdot\dfrac{3}{4}\right)\cdot\left(11\cdot\dfrac{9}{121}\right)\)

\(=3\cdot\dfrac{9}{11}\)

\(=\dfrac{27}{11}\)

a: =-9/11+2/3=-27/33+22/33=-5/33

b: =(16/29-13/29)+12/39-16/39

=3/29-4/39=1/1131

d: =(-111,82-8,18)+(13,3+16,7)=-120+30=-90

cảm ơn nha ^^

D=5/3.5+5/5.7+5/7.9+5/9.11+...+5/27.29+5/29.31

2D=10/3.5+10/5.7+10/7.9+10/9.11+...+10/27.29+10/29.31

2D=5/3-5/5+5/5-5/7+5/7-5/9+5/9-5/11+...+5/27-5/29+5/29-5/31

2D=5/3-5/31

2D=155/93-15/93

2D=140/93

D=140/93:2

D=70/93