15.2^24.3^14-4.3^15.2^24
2^24.3^14.1
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Ta có: \(7\cdot6^{10}\cdot2^{21}\cdot3^6-2^{19}\cdot6^{15}\)
\(=7\cdot3^{10}\cdot2^{10}\cdot2^{21}\cdot3^6-2^{19}\cdot3^{15}\cdot2^{15}\)
\(=7\cdot2^{31}\cdot3^{16}-2^{34}\cdot3^{15}\)
\(=2^{31}\cdot3^{15}\left(7\cdot3-2^3\right)=2^{31}\cdot3^{15}\cdot13\)
Ta có: \(9\cdot6^{15}\cdot2^{13}-4\cdot3^{15}\cdot2^{26}\)
\(=3^2\cdot3^{15}\cdot2^{15}\cdot2^{13}-2^2\cdot3^{15}\cdot2^{26}\)
\(=3^{17}\cdot2^{28}-3^{15}\cdot2^{28}=3^{15}\cdot2^{28}\left(3^2-1\right)=3^{15}\cdot2^{31}\)
Ta có: \(B=\frac{7\cdot6^{10}\cdot2^{21}\cdot3^6-2^{19}\cdot6^{15}}{9\cdot6^{15}\cdot2^{13}-4\cdot3^{15}\cdot2^{26}}\)
\(=\frac{2^{31}\cdot3^{15}\cdot13}{3^{15}\cdot2^{31}}=13\)
a: \(5^6:5^3+2^3:2^2\)
\(=5^3+2\)
=125+2
=127
b: \(3333:3+225:15\)
=1111+15
=1126
c: \(15\cdot2^3+4\cdot3^2-5\cdot7\)
\(=15\cdot8+4\cdot9-35\)
=120+36-35
=121
d: \(5\cdot4^2-18:3^2\)
\(=5\cdot16-18:9\)
=80-2=78
e: \(6^2:4\cdot3+2\cdot5^2\)
\(=36:4\cdot3+2\cdot25\)
=27+50
=77
f: \(80-\left(4\cdot5^2-3\cdot2^3\right)\)
=80-(100-24)
=80-76
=4
a) A = 110 - (-761) + 296 + 1454 - (-813 + 1077)
= 110 + 761 + 296 + 1454 - 264
= 871 + 1750 - 264
= 2631 - 264
= 2357
Ta có: \(\left(-\dfrac{3}{2}\right)^3+\dfrac{-49}{24}\cdot\dfrac{3}{14}-\left(\dfrac{5}{8}-\dfrac{27}{8}\right)\)
\(=\dfrac{-27}{8}+\dfrac{-7}{2}\cdot\dfrac{1}{8}-\dfrac{-22}{8}\)
\(=\dfrac{-27+22}{8}+\dfrac{-7}{16}\)
\(=\dfrac{-5}{8}+\dfrac{-7}{16}\)
\(=\dfrac{-10}{16}+\dfrac{-7}{16}\)
\(=\dfrac{-17}{16}\)
A = 15.23 + 4.32 - 5.7
=> A = 15.8 + 4.9 - 5.7
=> A = 120 + 36 - 35
=> A = 156 - 35
=> A = 121