\(77^2+23^2+77\cdot46\)

\(=77^2+2\cdot77\cdot23+23^2\)

\(=\left(77+23\right)^2\)

\(=100^2\)

\(=10000\)

\(\text{77^2+23^2+77.46}=77^2+2.77.23+23^2=\left(77+23\right)^2=100^2=10000\)

a: \(101^2=\left(100+1\right)^2\)

\(=100^2+2\cdot100\cdot1+1^2=10000+200+1\)

=10201

b: \(97\cdot103=\left(100-3\right)\left(100+3\right)\)

\(=100^2-3^2=10000-9=9991\)

c: \(77^2+23^2+77\cdot46\)

\(=77^2+2\cdot77\cdot23+23^2\)

\(=\left(77+23\right)^2=100^2=10000\)

d: \(105^5-5^2=\left(105-5\right)\left(105+5\right)=100\cdot110=11000\)

e: \(A=\left(x-y\right)\left(x^2+xy+y^2\right)+2y^3\)

\(=x^3-y^3+2y^3=x^3+y^3\)

\(=\left(\frac23\right)^3+\left(\frac13\right)^3=\frac{8}{27}+\frac{1}{27}=\frac{9}{27}=\frac13\)

có lộn đề ko bn ơi 

c). 1081.46

d). 1000

e. P=(x−y)(x2+xy+y2)−2y3=x3−y3−2y3=x3−3y3=(12)3−3.(23)3=−5572

mik k biết nữa

a) 23²+77²+46.77

=23²+ 2.23.77+77²

=(23+77)²= 100²=10000

b) 31²+169²+62.169

=31²+2.1.169+169²

=(31+169)²=200²=40000

c) 103²-9

=103²-3²

= (103-3)(103+3)

= 100.106=10600

d) 45²-15²

=(45-15)(45+15)= 30.60=1800

10000

=77(77+46)+23²

=77.123+529

=10 000

a) \(101^2=\left(100+1\right)^2=100^2+2\cdot100\cdot1+1^2=10000+200+1=10201\)

b) \(97\cdot103=\left(100-3\right)\left(100+3\right)=100^2-3^2=10000-9=9991\)

c) \(77^2+23^2+77\cdot46\)

\(=77^2+2\cdot77\cdot23+23^2\)

\(=\left(77+23\right)^2=100^2=10000\)

d) \(105^2-5^2=\left(105-5\right)\left(105+5\right)=100\cdot110=11000\)

198 + 232 - 98 -  32 = (232 - 32) + (198 - 98) = 300

\(A=248-242+240-234+232-226+...+216-210\)

\(=4+4+4+...4\)

Số số 4 là \(\left(248-216\right):8+1=5\)

\(\Rightarrow A=5.4=20\)

Bằng 20 bạn nhé