Sửa đề: \(\frac{2022}{2}:\frac43:\frac{2022}{9}:\frac{18}{24}\)

\(=\frac{2022}{2}\times\frac34\times\frac{9}{2022}\times\frac{24}{18}\)

\(=\frac34\times\frac92\times\frac43=\frac92\)

A=1−2−3+4−5−6+7−8−9+....+2020−2021−2022D=1-2-3+4-5-6+7-8-9+....+2020-2021-2022

A =(1−2−3)+(4−5−6)+(7−8−9)+....+(2020−2021−2022)D=(1-2-3)+(4-5-6)+(7-8-9)+....+(2020-2021-2022)

A=(−4)+(−7)+(−10)+.....+(−2023)D=(-4)+(-7)+(-10)+.....+(-2023)

A=[(2023−4):3+1].[(−2023−4):2]D=[(2023-4):3+1].[(-2023-4):2]

A=674.(−1013,5)D=674.(-1013,5)

A=−683099

A=1−2−3+4−5−6+7−8−9+....+2020−2021−2022D=1-2-3+4-5-6+7-8-9+....+2020-2021-2022

A =(1−2−3)+(4−5−6)+(7−8−9)+....+(2020−2021−2022)D=(1-2-3)+(4-5-6)+(7-8-9)+....+(2020-2021-2022)

A=(−4)+(−7)+(−10)+.....+(−2023)D=(-4)+(-7)+(-10)+.....+(-2023)

A=[(2023−4):3+1].[(−2023−4):2]D=[(2023-4):3+1].[(-2023-4):2]

A=674.(−1013,5)D=674.(-1013,5)

A=−683099

`2022+2022:1/3+2022+2022:1/5`

`=2022+2022xx3+2022+2022xx5`

`=2022xx(1+3+1+5)`

`=2022xx10=20220`

20220

a: \(\dfrac{4}{9}=\dfrac{4\cdot2}{9\cdot2}=\dfrac{8}{18}< \dfrac{13}{18}\)

b: 34/-4=-8,5

Ta có: 8,5<8,6

=>-8,5>-8,6

=>\(\dfrac{34}{-4}>-8,6\)

c: \(\dfrac{2021}{2022}=1-\dfrac{1}{2022}\)

\(\dfrac{2022}{2023}=1-\dfrac{1}{2023}\)

Ta có: 2022<2023

=>\(\dfrac{1}{2022}>\dfrac{1}{2023}\)

=>\(-\dfrac{1}{2022}< -\dfrac{1}{2023}\)

=>\(-\dfrac{1}{2022}+1< -\dfrac{1}{2023}+1\)

=>\(\dfrac{2021}{2022}< \dfrac{2022}{2023}\)

34/-4=-8,5 là sao v

Đặt \(A=1+3^2+3^4+\cdots+3^{2022}\)

=>\(9A=3^2+3^4+3^6+\cdots+3^{2024}\)

=>\(9A-A=3^2+3^4+3^6+\cdots+3^{2024}-1-3^2-\cdots-3^{2022}\)

=>\(8A=3^{2024}-1\)

=>\(A=\frac{3^{2024}-1}{8}\)

hôm nay tôi mới thi

chờ tí

đâu đúng mà 

TA có: \(3a-b=\frac12\left(a+b\right)\)

=>2(3a-b)=a+b

=>6a-2b=a+b

=>5a=3b

=>a=0,6b

\(C=\frac{a^{2022}+3^{2022}}{b^{2022}+5^{2022}}\)

\(=\frac{\left(0,6b\right)^{2022}+3^{2022}}{b^{2022}+5^{2022}}\)

\(=\frac{\left(0,6\right)^{2022}\left(b^{2022}+5^{2022}\right)}{b^{2022}+5^{2022}}=\left(0,6\right)^{2022}=\left(\frac35\right)^{2022}\)

\(=\dfrac{1}{2}+\dfrac{5}{6}-\dfrac{1}{2}-\dfrac{5}{6}+2022=2022\)

2022

A = ( 2022 x 0,75 + 2022 : 4) - ( 2021 : 0,1 : 10)

= (2022 x 0,75 + 2022 x 0,25) - ( 2021 : 1/10 : 10)

= 2022 x(0,75+0,25) - 2021x 10 : 10

= 2022x 1 - 2021

= 2022 - 2021

=1