B = 4 x 113 x 25 - 5 x 112 x 20

= 11300 - 11200

= 100

4 x 113 x 25 - 5 x 112 x 20

= < 4 x 25 > x 113 - < 5 x 20 > x 112

= 100 x 113 - 100 x 112

= 11300 - 11200

= 100

mình làm đúng 100% , k và kb với mình nha

4x113x25 - 5x112x20

= 4 x 25 x 113 - 5 x 20 x 112

= 100 x 113 - 100 x 112

= 100 x ( 113 - 112 )

= 100 x 1

= 100

(4x25)x113-(20x5)x112

100x113-100x112

100x(113-112)

100x1

100

=(4x25)x113-(5x20)x112

=100x113-100x112

=1130-11200

=1

Ta có: \(\left(145\times99+145\right)-\left(143\times101-143\right)\)

\(=145\times\left(99+1\right)-143\times\left(101-1\right)\)

\(=145\times100-143\times100=100\times2\)

Ta có: \(4\times113\times25-5\times112\times20\)

\(=100\times113-100\times112\)

\(=100\times\left(113-112\right)=100\times1=100\)

Ta có: \(\frac{\left(145\times99+145\right)-\left(143\times101-143\right)}{4\times113\times25-5\times112\times20}\)

\(=\frac{100\times2}{100}=2\)

huhu ai giúp mik ik

ai jup ik

a,=4x25x113-5x20x112

=100x113-100x112

=100x(113-112)=100x1=100

b,=113x(54+45+1)=113x100=11300

c,=(266x2x7-266x2x7)x(266x2x7+266)

=0x(266x2x7+266)=0

\(12,25+\left(-21,37\right)-\left(14,67-21,75\right)\)

\(=12,25-21,37-14,67+21,75\)

\(=12,25+21,75-21,37-14,63-0,04\)

\(=34-36-0,04\)

= -2-0,04=-2,04

120:{54-[50:2.(3^2-2.4)]}

= 120:{ 54-[25.(9-8)]}

= 120:{54-[25.1]}

= 120:{54-25}

= 120:29

=\(\dfrac{120}{29}\)

e: \(=\dfrac{2^{10}\cdot3^9-2^9\cdot3^8}{2^{10}\cdot3^8}=\dfrac{2^9\cdot3^8\left(2\cdot3-1\right)}{2^{10}\cdot3^8}=\dfrac{5}{2}\)

g: \(=125+\dfrac{3}{5}-97-\dfrac{2}{3}+97+\dfrac{2}{5}-125-\dfrac{1}{3}=0\)