1D 2A 3D 4C 5B 6B 7B 8A 9A 10B 11B 12C 13D 14A 15D 16C

D - A 
D - C 
B - B - B - A - A - B - B - C - D - D - D - C

alternatively

symbolizes

hiking

inexperienced

attendances

believable

28.alternatively

29.symbolizes

30.hiking

31.inexperienced

32.attendances

33.believable

A - A 
A - B 
B - C - C - A - C - B - D - A - B - C - A - C

1.A

2.A 
3.A

4.B 
5.B

6.C

7.C

8. A

9. C

10. B

11. D

12.A

13. B

14. C

15. A

16. C

C - A - D - B - A - C
she learnt Math as well as Hoa
eaten noodles for four years
after her mother very much
as good at chemistry as Susan

\(\left(-2023\right).2024-2023.\left(10-2024\right)\\ =-2023.2024-2023.10+2023.2024\\ =\left(2023.2024-2023.2024\right)-2023.10\\ =0-2023.10=-20230\\ ---\\ 198.246-246.\left(198-19\right)\\ =198.246-246.198+246.19\\ =0-246.19=-4674\\ ---\\ 297.\left(435-24\right)-435.\left(297-24\right)\\ =297.435-297.24-435.297+435.24\\ =\left(297.435-435.297\right)+\left(435.24-297.24\right)\\ =0+\left(435-297\right).24\\ =0+138.24=3312\\ ----\\ \left(-367\right).\left(19-198\right)+198.\left(19-367\right)\\ =-367.19+367.198+198.19-367.198\\ =\left(367.198-367.198\right)+\left(198.19-367.19\right)\\ =0+19.\left(198-367\right)=0+19.\left(-169\right)=-3211\)

1. B

2. C

3. C

4. B

5. A

6. D

7. C

8. C

9. A

10. B

1. B 2. C 3. C 4. B 5. A 6. D 7. C 8. C 9. A 10. B

Câu 4: \(\left(2x-x^2\right)\left(2x^2-3x-2\right)=0\)

=>\(\left(x^2-2x\right)\left(2x^2-4x+x-2\right)=0\)

=>\(x\left(x-2\right)\left(x-2\right)\left(2x+1\right)=0\)

=>x∈{0;2;-1/2}

=>A={0;2;-1/2}

Ta có: \(3

mà n∈N*

nên n∈{2;3;4;5}

=>B={2;3;4;5}

A\(\cap\) B={0;2;-1/2}\(\cap\) {2;3;4;5}

={2}

Câu 5: C

Câu 6: A={0;2}; B={0;1;2;3;4}

A\(\cup\)X=B

=>X={1;2;3;4;0}; X={1;2;3;4}; X={1;2;3;4;2}; X={1;2;3;4;0;2}

=>Có 4 tập hợp X thỏa mãn

Bài 8:

\(n_{Al}=\dfrac{2,7}{27}=0,1\left(mol\right)\)

\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)

0,1--->0,15------>0,05---------->0,15

a. \(V_{H_2SO_4}=\dfrac{0,15}{1}=0,15\left(l\right)=150\left(ml\right)\)

b. \(V'=0,15.22,4=3,36\left(l\right)\)

c. \(CM_{Al_2\left(SO_4\right)_3}=\dfrac{0,05}{0,15}=\dfrac{1}{3}M\)