\(\dfrac{22}{5}\times\dfrac{6}{121}\times\dfrac{11}{4}\times\dfrac{3}{5}\times\dfrac{1}{3}\times\dfrac{5}{4}\)

\(=\left(\dfrac{22}{5}\times\dfrac{5}{4}\right)\times\left(\dfrac{6}{121}\times\dfrac{11}{4}\right)\times\left(\dfrac{3}{5}\times\dfrac{1}{3}\right)\)

\(=\dfrac{11}{2}\times\dfrac{3}{22}\times\dfrac{1}{5}\)

\(=\dfrac{3}{20}\)

\(=\dfrac{22\times6\times11\times3\times1\times5}{5\times121\times4\times5\times3\times4}=\dfrac{11\times2\times6\times11\times1}{11\times11\times4\times5\times4}=\dfrac{2\times6\times1}{4\times5\times4}=\dfrac{18}{100}=\dfrac{9}{50}\)

\(\left(x-12,5\right):\frac{3}{4}=\frac{8}{5}\)

\(x-12,5=\frac{8}{5}.\frac{3}{4}\)

\(x-12,5=\frac{6}{5}\)

\(x=\frac{6}{5}+12,5\)

\(x=\frac{137}{10}\)

\(\left(x-\frac{2}{5}\right)\times\frac{5}{11}=\frac{75}{22}\)

\(x-\frac{2}{5}=\frac{75}{22}:\frac{5}{11}\)

\(x-\frac{2}{5}=\frac{15}{2}\)

\(x=\frac{15}{2}+\frac{2}{5}\)

\(x=\frac{79}{10}\)

A= \(11\frac{3}{13}-\left(2\frac{4}{7}+5\frac{3}{13}\right)\)

  = \(11\frac{3}{13}-2\frac{4}{7}-5\frac{3}{13}\)

 = \(\left(11\frac{3}{13}-5\frac{3}{13}\right)-2\frac{4}{7}\)

= \(6-2\frac{4}{7}\)

= \(3\frac{3}{7}\)

B= \(\left(96\frac{4}{9}+3\frac{7}{11}\right)-4\frac{4}{9}\)

  = \(96\frac{4}{9}+3\frac{7}{11}-4\frac{4}{9}\)

 =  \(\left(96\frac{4}{9}-4\frac{4}{9}\right)+3\frac{7}{11}\)

 = \(92+3\frac{7}{11}\)

 = \(95\frac{7}{11}\)

C= \(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+1\frac{5}{7}\)

  = \(\frac{-5}{7}.\left(\frac{2}{11}+\frac{9}{11}\right)+1\frac{5}{7}\)

  = \(\frac{-5}{7}.1+1\frac{5}{7}\)

  = \(\frac{-5}{7}+1\frac{5}{7}\)

  = 1

(ý D bn tự làm ha)

mình  vieetts ra thì dài lám 

nếu bạn đã chác chăn về kiến thức thì hãy phân tích rồi tìm cách lam

còn ngược lại ban hãy tính máy tính rồi đoán cách làm cũng được

a: Ta có: \(\left(-\frac57-\frac79+\frac{9}{11}-\frac{11}{13}\right)\cdot\left(3-\frac34\right)\)

\(=\left(-\frac{6435}{9009}-\frac{7007}{9009}+\frac{7371}{9009}-\frac{7623}{9009}\right)\cdot\frac94\)

\(=-\frac{13694}{9009}\cdot\frac94=\frac{-6847}{2}\cdot\frac{1}{1001}=\frac{-6847}{2002}\)

b: \(\left(\frac{10}{21}+\frac{14}{27}-\frac{6}{11}+\frac{22}{39}\right):\left(2-\frac23\right)\)

\(=\left(\frac{12870}{27027}+\frac{14014}{27027}-\frac{14742}{27027}+\frac{15246}{27027}\right):\frac43\)

\(=\frac{27388}{27027}\cdot\frac34=\frac{6847}{9009}\)

\(\dfrac{37\cdot5^4}{25^2}=\dfrac{37\cdot5^4}{5^4}=37\\ \dfrac{2^4\cdot2^6\cdot3^8\cdot9^2}{4^4\cdot3^{11}}=\dfrac{2^{10}\cdot3^8\cdot3^4}{2^8\cdot3^{11}}=2^2\cdot3=12\\ \dfrac{3\cdot9^4\cdot9^3}{3^2\cdot9}=\dfrac{3\cdot3^8\cdot3^6}{3^2\cdot3^2}=3^{11}\\ \dfrac{125\cdot5\cdot64-25^3\cdot10\cdot4}{5^7\cdot8}=\dfrac{5^3\cdot5\cdot2^6-5^6\cdot2\cdot5\cdot2^2}{5^7\cdot2^3}=\dfrac{5^4\cdot2^3\left(2^3-5^3\right)}{5^7\cdot2^3}=\dfrac{8-125}{5^3}=\dfrac{-117}{125}\)

quá đỉnh luôn 

z là gì vậy bn

?

\(=\dfrac{3}{9}\cdot\dfrac{9}{11}\cdot\dfrac{22}{25}\cdot\dfrac{5}{7}\cdot\dfrac{7}{10}=\dfrac{3}{11}\cdot\dfrac{22}{25}\cdot\dfrac{5}{10}=3\cdot2\cdot\dfrac{1}{2}\cdot\dfrac{1}{5}=\dfrac{3}{5}\)

\(=\dfrac{3x4x9x11x2x5x7}{4x9x11x5x5x10}=\dfrac{3x2x7}{10}=\dfrac{42}{10}=\dfrac{21}{5}\)

Bài 2:

a: 2/6x5/3=10/18=5/9

b: 11/9x5/10=55/90=11/18

c: 3/9x6/8=1/3x3/4=1/4

d: 4/9x12/16=48/144=1/3

e: 25/15x6/7=5/3x6/7=30/21=10/7

f: 6/10x15/20=90/200=9/20

Bài 1

4/5 x 6/7= 24/35

2/9 x 1/2= 2/18= 1/9

1/2 x 8/3= 8/6= 4/3

7/9 x 6/5= 42/45= 14/15

8/7 x 5/9= 40/63

10/11 x 22/15= 220/165= 4/3

Bài 2

2/6 x 5/3= 1/3 x 5/3=5/9

11/9 x 5/10= 11/9 x 1/2= 11/18

3/9 x 6/8= 1/3 x 3/4 =3/12= 1/4

4/9 x 12/16= 4/9 x 3/4= 12/36= 1/3

25/15 x 6/7= 5/3 x 6/7= 30/21= 10/7

6/10 x 15/20= 3/5 x 3/4= 9/20

\(=\dfrac{8}{22}\cdot\dfrac{7}{9}+\dfrac{5}{9}\cdot\dfrac{8}{11}-\dfrac{8}{9}\cdot\dfrac{4}{11}\)

\(=\dfrac{8}{9}\left(\dfrac{7}{22}+\dfrac{5}{11}-\dfrac{4}{11}\right)=\dfrac{8}{9}\cdot\dfrac{9}{22}=\dfrac{4}{11}\)

= \(\dfrac{4}{11}\)