Nhờ mn giải giúp e ạ e cảm ơn trc ạ 
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Bài 1:
\(54\left(\dfrac{km}{h}\right)=15\left(\dfrac{m}{s}\right);9\left(\dfrac{m}{s}\right)=32,4\left(\dfrac{km}{h}\right)\)
Baì 2:
\(t'=s':v'=5:\left(5.3,6\right)=\dfrac{5}{18}h\)
\(\Rightarrow v_{tb}=\dfrac{s'+s''}{t'+t''}=\dfrac{5+3,8}{\dfrac{5}{18}+\left(\dfrac{15}{60}\right)}\simeq16,67\left(\dfrac{km}{h}\right)\)
Câu 2:
\(\Leftrightarrow\left(x+2\right)\left(10x+3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=-\dfrac{3}{10}\end{matrix}\right.\)
16. He told Min that he would meet her the following day / the next day.
17. Tom asked Linda if he could sit beside her.
18. He told his mom that he wanted a big cake for his birthday.
19. He told us not to turn the light on.
20. I asked him how long he was going to stay.
21. She wanted to know if Hoa was going by bike.
22. She asked us not to use too much hot water.
23. She invited me to come to her party.
5.
1. going
2.lying/reading
3.likes/ being
4.collecting
5.watching / are going
6.doing
7.plays
8.have collected
9. will travel
10.will make
6.
1.beautiful
2. boring
3. decoration
4.widens
5. wonderful
8
\(a.720:\left(x-17\right)=12\)
\(x-17=60\)
\(x=77\)
\(b.\left(x-28\right):12=8\)
\(x-28=96\)
\(x=124\)
\(c.26+8x=6x+46\)
\(8x-6x=46-26\)
\(2x=20\)
\(x=10\)
\(d.3600:\left[\left(5x+335\right):x\right]=50\)
\(\left(5x+335\right):x=72\)
\(5+335:x=72\)
\(335:x=67\)
\(x=5\)
a) \(720:\left(x-17\right)=12\)
\(\Rightarrow x-17=\dfrac{720}{12}\)
\(\Rightarrow x-17=60\)
\(\Rightarrow x=60+17\)
\(\Rightarrow x=77\)
b) \(\left(x+28\right):12=8\)
\(\Rightarrow x+28=12\cdot8\)
\(\Rightarrow x+28=96\)
\(\Rightarrow x=96-28\)
\(\Rightarrow x=68\)
c) \(26+8x=6x+46\)
\(\Rightarrow8x-6x=46-26\)
\(\Rightarrow2x=20\)
\(\Rightarrow x=\dfrac{20}{2}\)
\(\Rightarrow x=10\)
d) \(3600:\left[\left(5x+335\right):x\right]=50\)
\(\Rightarrow\left(5x+335\right):x=\dfrac{3600}{50}\)
\(\Rightarrow\left(5x+335\right):x=72\)
\(\Rightarrow5x+335=72\cdot x\)
\(\Rightarrow72x-5x=335\)
\(\Rightarrow67x=335\)
\(\Rightarrow x=\dfrac{335}{67}\)
\(\Rightarrow x=5\)
a: AB⊥ AC
HE⊥AC
Do đó: HE//AB
b: TA có: ΔHAB vuông tại H
=>\(\hat{HAB}+\hat{HBA}=90^0\)
=>\(\hat{HAB}=90^0-60^0=30^0\)
BA//HE
=>\(\hat{HAB}=\hat{AHE}\) (hai góc so le trong)
=>\(\hat{AHE}=30^0\)
7. How often does he go to the library?
8. ....is the shortest student in his class.
9......is her address?
10... is shorter than Ba.














7B, 8A
Câu 9:
a. <=> 4x= 12
<=> x=3
S={3}
b. <=> (2x-6).(x+9)=0
<=> 2x-6=0 hoặc x+9=0
<=> x= 3 hoặc x=-9
S={3;-9}
c. <=> 5x=-20
<=> x= -4
S={-4}
d. <=> (2x-6).(3x+9)=0
<=> 2x-6=0 hoặc 3x+9=0
<=> 2x=6 hoặc 3x=-9
<=> x=3 hoặc x= -3
S={3;-3}
e. th1: 2x-3= 6x+5 nếu 2x-3>0 => x>\(\dfrac{3}{2}\)
2x-3=6x+5
<=>2x-6x= 5+3
<=>-4x=8
<=> x= -2 (loại)
th2: 2x-3= -6x+5 nếu 2x-3<0 => x<\(\dfrac{3}{2}\)
2x-3=-6x+5
<=>2x+6x= 5+3
<=>8x=8
<=>x=1 (chọn)
S={1}
f. <=> -12x>6
<=> x< -\(\dfrac{1}{2}\)
S={x/x<-\(\dfrac{1}{2}\)}
g. th1: 2x+3=4x+5 nếu 2x+3>0 => x>\(\dfrac{-3}{2}\)
2x+3=4x+5
2x-4x=5-3
-2x= 2
x= -1 (chọn)
th2: 2x+3=-4x+5 nếu 2x+3<0 => x<\(\dfrac{-3}{2}\)
2x+3=-4x+5
2x+4x= 5-3
6x=2
x= \(\dfrac{1}{3}\)(loại)
S={-1}
h. <=> -2x>-6
<=> x< 3
S={x/x<3}