a) (-124) + 24 = -100
b) 37. 78 + 37. 22
=  37 . ( 78 + 22 )
=  37 . 100
= 3700

tk cho mik nha

\(=64\cdot\dfrac{-1}{8}+100\cdot\dfrac{1}{100}\)

=-8+1

=-7

\(A=-\dfrac{1}{6}-\left[\dfrac{9}{16}-\dfrac{9}{8}+\dfrac{3}{4}\right]\)

\(=\dfrac{-1}{6}-\dfrac{9-18+12}{16}=\dfrac{-1}{6}-\dfrac{3}{16}\)

\(=\dfrac{-8}{48}-\dfrac{9}{48}=-\dfrac{17}{48}\)

\(B=\left(-\dfrac{3}{4}+\dfrac{3}{4}\right)^2+\dfrac{3}{4}\cdot\dfrac{-5}{9}+7^3\)

=-15/36+343

=343-5/12=4111/12

e: =5/7(5/11+2/11-14/11)

=5/7(-7/11)=-5/11

f: =-5/4(2/11+9/11)+1+3/4

=-5/4+7/4

=2/4=1/2

g: =-5/7(3/13+10/13)+1+5/7

=-5/7+1+5/7

=1

h: =7/4(29/5-9/5)+41/13

=-7+41/13=-50/13

a: \(5\cdot\frac{5}{27}+\frac{7}{23}+0,5\cdot\frac57+\frac{16}{23}+\frac12\)

\(=5\cdot\frac{5}{27}+\left(\frac{7}{23}+\frac{16}{23}\right)+0,5\left(\frac57+1\right)\)

\(=\frac{25}{27}+1+0,5\cdot\frac{12}{7}=\frac{25}{27}+1+\frac67=\frac{25}{27}+\frac{13}{7}=\frac{526}{27\cdot7}=\frac{526}{189}\)

b: \(25\frac16:\frac{-4}{5}-45\frac16:\frac{-4}{5}\)

\(=\left(25+\frac16-45-\frac16\right):\frac{-4}{5}\)

\(=-20\cdot\frac{-5}{4}=25\)

c: \(25\cdot\left(-\frac15\right)^3+\frac15-2\cdot\left(-\frac12\right)^2-\frac12\)

\(=25\cdot\frac{-1}{125}+\frac15-2\cdot\frac14-\frac12\)

\(=-\frac15+\frac15-\frac12-\frac12=-1\)

a: \(-\left(251\cdot3+281\right)+3\cdot251-\left(1-281\right)\)

\(=-251\cdot3-281+3\cdot251-1+281\)

=-1

b: \(\left(0,75-\frac14\right):\left(-5\right)+\frac{1}{15}-\left(-\frac15\right):\left(-3\right)\)

\(=\left(0,75-0,25\right):\left(-5\right)+\frac{1}{15}-\frac{1}{15}\)

=0,5:(-5)

=-1

c: \(\sqrt{\frac{4}{81}}:\sqrt{\frac{25}{81}}-1\frac25\)

\(=\frac29:\frac59-\frac75\)

\(=\frac25-\frac75=-\frac55=-1\)

a: \(-\left(251\cdot3+281\right)+3\cdot251-\left(1-281\right)\)

\(=-251\cdot3-281+3\cdot251-1+281\)

=-1

b: \(\left(0,75-\frac14\right):\left(-5\right)+\frac{1}{15}-\left(-\frac15\right):\left(-3\right)\)

\(=\left(0,75-0,25\right):\left(-5\right)+\frac{1}{15}-\frac{1}{15}\)

=0,5:(-5)

=-1

c: \(\sqrt{\frac{4}{81}}:\sqrt{\frac{25}{81}}-1\frac25\)

\(=\frac29:\frac59-\frac75\)

\(=\frac25-\frac75=-\frac55=-1\)

a: \(5\cdot\frac{5}{27}+\frac{7}{23}+0,5\cdot\frac57+\frac{16}{23}+\frac12\)

\(=5\cdot\frac{5}{27}+\left(\frac{7}{23}+\frac{16}{23}\right)+0,5\left(\frac57+1\right)\)

\(=\frac{25}{27}+1+0,5\cdot\frac{12}{7}=\frac{25}{27}+1+\frac67=\frac{25}{27}+\frac{13}{7}=\frac{526}{27\cdot7}=\frac{526}{189}\)

b: \(25\frac16:\frac{-4}{5}-45\frac16:\frac{-4}{5}\)

\(=\left(25+\frac16-45-\frac16\right):\frac{-4}{5}\)

\(=-20\cdot\frac{-5}{4}=25\)

c: \(25\cdot\left(-\frac15\right)^3+\frac15-2\cdot\left(-\frac12\right)^2-\frac12\)

\(=25\cdot\frac{-1}{125}+\frac15-2\cdot\frac14-\frac12\)

\(=-\frac15+\frac15-\frac12-\frac12=-1\)