$B=\dfrac{4^5\cdot10\cdot5^6+25^5\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}$

$=\dfrac{2^{10}\cdot2\cdot5\cdot5^6+5^{10}\cdot2^8}{2^8\cdot5^4+2^5\cdot5^7}$

$=\dfrac{2^{11}\cdot5^7+2^8\cdot5^{10}}{2^8\cdot5^4+2^5\cdot5^7}$

$=\dfrac{2^8\cdot5^7(2^3+5^3)}{2^5\cdot5^4(2^3+5^3)}$

$=2^{8-5}\cdot5^{7-4}$

$=2^3\cdot5^3$

$=8\cdot125$

$=1000.$

   234 - ( 56 + 24 : 4 )
=234 - ( 56 + 6 )
=234 - 62
=172
 

  100 : { 250 : [ 450 - ( 500 - 2² . 25) ] }
=100 : { 250 : [ 450 - ( 500 - 4 . 25) ] }
=100 : { 250 : [ 450 - ( 500 - 100) ] }
=100 : { 250 :  [ 450 - 400] }
=100 : { 250 : 50}
=100 : 5
=20

Câu 1:

1;   125 : 5²

   =   5³ : 5²

   =      5¹

2; 27⁵ : 81³

 = (3³)⁵ : (3⁴)³

 = 3¹⁵ : 3¹²

= 3³ 

3; 8⁴.16⁵.32

= (2³)⁴.(2⁴)⁵.2⁵

= 2¹².2²⁰.2⁵

= 2³⁷

Câu 1

4; 27⁴.81¹⁰

= (3³)⁴.(3⁴)¹⁰

= 3¹².3⁴⁰

= 3⁵²

\(P\left(x\right)=x^2+5x^4-3x^3+x^2+4x^4+3x^3-x+5\)

\(=\left(5x^4+4x^4\right)+\left(-3x^3+3x^3\right)+\left(x^2+x^2\right)-x+5\)

\(=9x^4+2x^2-x+5\)

\(Q\left(x\right)=x-5x_{}^3-x^2-x^4+4x^3-x^2+3x-1\)

\(=\left(-5x^4-x^4\right)+4x^3+\left(-x^2-x^2\right)+\left(x+3x\right)-1\)

\(=-6x^4+4x^3-2x^2+4x-1\)

P(x)+Q(x)

\(=9x^4+2x^2-x+5-6x^4+4x^3-2x^2+4x-1\)

\(=3x^4+4x^3+3x+4\)

Đặt P(x)+Q(x)=0

=>\(3x^4+4x^3+3x+4=0\)

=>\(x^3\left(3x+4\right)+\left(3x+4\right)=0\)

=>\(\left(3x+4\right)\left(x^3+1\right)=0\)

=>\(\left[\begin{array}{l}3x+4=0\\ x^3+1=0\end{array}\right.\Longrightarrow\left[\begin{array}{l}x=-\frac43\\ x=-1\end{array}\right.\)

Phép tính tám nhân năm mũ hai trừ một trăm tám chín chia ba mũ hai bằng bao nhiêu?

\(8\cdot5^2-189:3^2\\ =8\cdot25-189:9\\ =200-21\\ =179\)

HT

dễ, nhưng phai giai dc câu nay  60% nhan x cong 2 phan 3 = 1 phan 3 nhan 6va 1 phan 3

dễ mà

Ta có:

$H=\dfrac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}$

$=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}$

$=\dfrac{2^{12}\cdot3^{10}(1+5)}{2^{11}\cdot3^{11}(2\cdot3-1)}$

$=\dfrac{2^{12}\cdot3^{10}\cdot6}{2^{11}\cdot3^{11}\cdot5}$

$=\dfrac{2^2}{5}$

$=\dfrac45.$

Hbioghgjgh

$\textbf{a)}$

$2^n\cdot2^4=128$

$\Leftrightarrow2^{n+4}=2^7$

$\Leftrightarrow n+4=7$

$\Leftrightarrow n=3.$