a,3/1-3/4=21/4-3/4=18/4=9/4

d,217,46

a) 67845 – y = 29361

y = 678445 - 29361

y = 649034

 b) y : 208 = 317

y = 317 x 208

y = 65936

a) 67845 – y = 29361

                  y = 678445 - 29361

                  y = 649034

 b) y : 208 = 317

     y           = 317 x 208

     y           = 65936

help

8344935

a) y = 38 484

a) 67845 – y = 29361

y = 67845 – 29361

y = 38484

( x + 1259 ) x 5 = 67845

( x + 1259 )      = 67845 : 5

( x + 1259 )      = 13569

x                       = 13569 - 1259

x                       = 12310

Mình nghĩ đề bài sai bạn ạ

tk nhé

ai k mình mình k lại

\(2.3^{x+1}=10.3^{12}+8.3^{12}\\ \Rightarrow2.3^{x+1}=3^{12}\left(10+8\right)\\ \Rightarrow2.3^{x+1}=3^{12}.18\\ \Rightarrow3^{x+1}=9.3^{12}\\ \Rightarrow3^{x+1}=3^{14}\\ \Rightarrow x+1=14\\ \Rightarrow x=13\)

a: \(3^2\cdot\frac{1}{243}\cdot81^2\cdot\frac{1}{3^2}\)

\(=\frac{3^2}{3^5}\cdot\frac{3^8}{3^2}=\frac{1}{3^3}\cdot3^6=3^3=27\)

b: \(4^6\cdot256^2\cdot2^4=\left(2^2\right)^6\cdot\left(2^8\right)^2\cdot2^4\)

\(=2^{12}\cdot2^{16}\cdot2^4=2^{12}\cdot2^{20}=2^{32}\)

c: \(4^6\cdot9^5+6^9\cdot120\)

\(=2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5\)

\(=2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5\)

\(=2^{12}\cdot3^{10}\cdot6=2^{13}\cdot3^{11}\)

Ta có \(8^4\cdot3^{12}-6^{11}\)

\(=2^{12}\cdot3^{12}-2^{11}\cdot3^{11}\)

\(=2^{11}\cdot3^{11}\left(2\cdot3-1\right)=2^{11}\cdot3^{11}\cdot5\)

Ta có: \(A=\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)

\(=\frac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\cdot5}=\frac{2^2}{5}=\frac45\)

d: \(4^2\cdot25^2+32\cdot125\)

\(=2^4\cdot5^4+2^5\cdot5^3\)

\(=2^4\cdot5^3\left(5+2\right)=2^4\cdot5^3\cdot7\)

\(B=\frac{4^2\cdot25^2+32\cdot125}{2^3\cdot5^2}\)

\(=\frac{2^4\cdot5^3\cdot7}{2^3\cdot5^2}=2\cdot5\cdot7=70\)