mình sẽ k cho 3 bạn làm nhanh nhất nhé , giúp mình nha các bạn. thanks các bạn nhé

a: \(B=\left(4\cdot2^5\right):\left(2^3\cdot\frac{1}{16}\right)\)

\(=\left(4\cdot32\right):\left(\frac{8}{16}\right)\)

\(=128:\frac12=128\cdot2=256\)

b: \(B=3^2\cdot\frac{1}{243}\cdot81^2\cdot\frac{1}{3^3}\)

\(=3^2\cdot\frac{1}{3^5}\cdot3^8\cdot\frac{1}{3^3}=\frac{3^8}{3^8}\cdot3^2=3^2=9\)

c: \(D=\left\lbrace\left(0,1\right)^2\right\rbrace^0+\left\lbrack\left(\frac17\right)^1\right\rbrack^2:\frac{1}{49}\cdot\left\lbrack\left(2^2\right)^3:2^5\right\rbrack\)

\(=1+\left(\frac17\right)^2\cdot49\cdot2^6:2^5\)

\(=1+49\cdot\frac{1}{49}\cdot2=1+2=3\)

d: \(C=\left(-0,5\right)^5:\left(-0,5\right)^3-\left(\frac{17}{2}\right)^7:\left(\frac{17}{2}\right)^6\)

\(=\left(-0,5\right)^{5-3}-\left(\frac{17}{2}\right)\)

\(=\left(-0,5\right)^2-\frac{17}{2}=0,25-\frac{17}{2}=\frac14-\frac{34}{4}=-\frac{33}{4}\)

\(3^2\cdot\frac{1}{243}\cdot81^2\cdot\frac{1}{3^3}\)

\(=\frac{3^2}{3^3}\cdot\frac{81\cdot81}{81\cdot3}\)

\(=\frac{1}{3}\cdot\frac{27}{1}\)

\(=9=\left(\pm3\right)^2\)

\(3^2.\frac{1}{243.81^2}.\frac{1}{3^2}=\frac{1}{3^5.\left(3^4\right)^2}.\frac{3^2}{3^2}=\frac{1}{3^5.3^8}.1=\frac{1}{3^{13}}\)

Bài làm

         \(3^2.\frac{1}{243}.81^2.\frac{1}{3^2}\)

\(=\left(3^2.\frac{1}{3^2}\right).\left(\frac{1}{243}.81^2\right)\)

\(=1.\left(\frac{1}{243}.6561\right)\)

\(=27\)

# Học tốt #

3 mũ 2.1/243.81 mũ 2.1/3 mũ 2

= 3 mũ 2.1/3 mũ 5.(3 mũ 4)mũ 2.1/3 mũ 2

= 3 mũ 2.1/3 mũ 5.3 mũ 8.1/3 mũ 2

= 3 mũ 2.1/3 mũ 13.1/3 mũ 2

= 3 mũ 2/3 mũ 13.1/3 mũ 2

= 1/3 mũ 13=1/1594323

a) \(\left[\frac{1}{3}\right]^{50}.\left(-9\right)^{25}-\frac{2}{3}:4\)

\(\Rightarrow\frac{1}{3^{50}}.\left(-9\right)^{25}-\frac{2}{3}.\frac{1}{4}\)

\(\Rightarrow\frac{\left(-9\right)}{9^{25}}-\frac{1}{6}\)

\(\Rightarrow1-\frac{1}{6}\)

\(\Rightarrow\frac{6}{6}-\frac{1}{6}=\frac{5}{6}\)

Vậy = 5/6

1.

a) \(3^2.\frac{1}{243}.81^2.\left(\frac{1}{3}\right)^2\)

\(=9.\frac{1}{243}.6561.\frac{1}{9}\)

\(=\frac{1}{27}.6561.\frac{1}{9}\)

\(=243.\frac{1}{9}\)

\(=27.\)

b) Sửa lại đề là \(\left(-0,125\right)^3.80^4\)

\(=\left(-0,125\right)^3.80^3.80\)

\(=\left(-0,125.80\right)^3.80\)

\(=\left(-10\right)^3.80\)

\(=\left(-1000\right).80\)

\(=-80000.\)

Chúc bạn học tốt!