b: 23/48<24/48=1/2

1/2=46/92<47/92

=>23/48<47/92

b, \(\dfrac{7}{13}\) và \(\dfrac{17}{23}\) 

\(\dfrac{7}{13}\) <  \(\dfrac{7+10}{13+10}\) = \(\dfrac{17}{23}\)

Vậy \(\dfrac{7}{13}\) < \(\dfrac{17}{23}\) 

\(\dfrac{12}{48}\) =  \(\dfrac{12:12}{48:12}\)  = \(\dfrac{1}{4}\) 

\(\dfrac{13}{47}\) > \(\dfrac{13}{52}\) = \(\dfrac{13:13}{52:13}\) = \(\dfrac{1}{4}\) 

Vậy  \(\dfrac{12}{48}\) < \(\dfrac{13}{47}\) 

a) có 12/48 < 13/48, 13/48 < 13/47 => 12/48 < 13/47 b) có 415/395 > 1 , 572/581 <1 => 415/395 > 572/581

a) có 12/48 < 13/48, 13/48 < 13/47
=> 12/48 < 13/47
b) có 415/395 > 1 , 572/581 <1
=> 415/395 > 572/581

a: \(\frac{23}{35}<\frac{23,1}{35}=0,66\)

\(0,66=\frac{20,46}{31}<\frac{21}{31}\)

Do đó: \(\frac{23}{35}<\frac{21}{31}\)

b: \(\frac{-17}{24}<\frac{-16}{24}=\frac{-2}{3}\)

\(\frac{-2}{3}=\frac{-13}{19,5}<\frac{-13}{28}\)

Do đó: \(-\frac{17}{24}<-\frac{13}{28}\)

c: \(\frac{9}{16}>\frac{8}{16}=\frac12;\frac12=\frac{12}{24}>\frac{11}{24}\)

Do đó: \(\frac{9}{16}>\frac{11}{24}\)

Dựa theo quy tắc so sánh ta thấy

* Tử số : \(23< 32\)

* Mẫu số : \(37< 45\)

\(\Rightarrow\frac{23}{37}< \frac{32}{45}\)

Chọn C hoặc A