1, <=>33+x=45
    <=>    x  = 12
Vậy x=12
2, <=>x+73 =102
    <=>   x    =29
3,x=2
4, -23+x=25<=>x=2
6, x-8=20<=>x=28

\(a.\dfrac{12+x}{42}=\dfrac{35}{42}\Leftrightarrow12+x=35\Leftrightarrow x=23\)

\(b.\dfrac{25-x}{40}=\dfrac{3}{8}\Leftrightarrow\dfrac{25-x}{40}=\dfrac{15}{40}\Leftrightarrow25-x=15\Leftrightarrow x=10\)

\(c.\dfrac{13+x}{20}=\dfrac{3}{4}\Leftrightarrow\dfrac{13+x}{20}=\dfrac{15}{20}\Leftrightarrow13+x=15\Leftrightarrow x=2\)

\(d.\dfrac{23-x}{25}=\dfrac{20}{25}\Leftrightarrow23-x=20\Leftrightarrow x=3\)

Theo đề ra, ta có: \(\frac{x-1}{y+2}=\frac{3}{5}\)

\(\Rightarrow\frac{x-1}{3}=\frac{y+2}{5}=\frac{x-1+y+2}{8}=\frac{23-1+2}{8}=\frac{24}{8}=3\)

\(\frac{x-1}{3}=3\Rightarrow x=3.3+1=10\)

\(\frac{y+2}{5}=3\Rightarrow y=5.3-2=13\)

a)x=0+45

x=45

b)x=23:23=1

x=42-1

x=41

c)x=613+5=618

x=618:6

x=13

a)x=45

b)x=41

c)x=103

d)x=111

e)x=60

g)x=5

h)x=3^x=26

a. (5.x + 3) : 4 – 16 = 6

(5.x + 3) : 4  = 22 

(5.x + 3)  = 88 

5.x  = 85

x = 13

b. 7(23 – 3.x) : 2 – 35 = 35

 7(23 – 3.x) : 2 = 70 

7(23 – 3.x) = 35 

 7 . 3.x = 12

7.x = 4 

x = 4/7 

a.) (5.x + 3) : 4 – 16 = 6

=> (5.x + 3) : 4  = 22

=> 5.x + 3  = 88

=>   5x  = 85 

=>   x  =  17

b) 7(23 – 3.x) : 2 – 35 = 35

=>  7(23 – 3.x) : 2  = 70

=>7(23 – 3.x)  = 140

=>   23 – 3.x  =  20

=>    3x    =  3 

=>   x  =  1 

c)(x-4).(2x+6)=0

=>(x-4)=0 hoặc (2x+6)=0

với x-4 = 0

      x    =0+4

      x    =4

với 2x+6=0

      2x    =0-6

      2x    =-6

      x      =-6:2

      x      =-3

3x=(-7)+1

3x=(-6)

x=(-6):3

x=(-2)

a, 5(x – 7) = 0

x – 7 = 0

x = 7

b, 95 – 5(x+2) = 45

5(x+2) = 40

x+2 = 8

x = 6

c,  6 2 x + 2 3 + 40 = 100

6(2x+8) = 60

2x+8 = 10

x = 1

d, 3(3x+9)+6 = 96

3(3x+9) = 90

3x+9 = 30

3x = 27

x = 9

e,  2 6 + 5 + x = 3 4

5+x = 81–64

5+x = 17

x = 12