Ta có: \(\frac{2x-3}{4}-\frac{4x-5}{3}=\frac{5-x}{6}\)

=>\(\frac{3\left(2x-3\right)-4\left(4x-5\right)}{12}=\frac{2\left(5-x\right)}{12}\)

=>3(2x-3)-4(4x-5)=2(5-x)

=>6x-9-16x+20=10-2x

=>-7x+11=10-2x

=>-5x=-1

=>x=1/5(nhận)

Bạn viết đề bằng công thức toán mọi người sẽ hỗ trợ tốt hơn chứ viết thế này khó hiểu quá.

y – 2/3 = 5/6 x 4/5

y – 2/3 = 2/3

y= 2/3 + 2/3

y = 4/3

\(\left(y-\dfrac{2}{3}\right):\dfrac{4}{5}=\dfrac{5}{6}\)

\(y-\dfrac{2}{3}=\dfrac{5}{6}\times\dfrac{4}{5}\)

\(y-\dfrac{2}{3}=\dfrac{2}{3}\)

\(y=\dfrac{2}{3}+\dfrac{2}{3}\)

\(y=\dfrac{4}{3}\)

\(\dfrac{x-1}{5}=\dfrac{y-2}{3}=\dfrac{z-2}{2}=\dfrac{2y-4}{6}=\dfrac{x-1+2y-4-z+2}{5+6-2}=\dfrac{6-5}{9}=\dfrac{1}{9}\)

\(\Rightarrow\left\{{}\begin{matrix}9x-9=5\\9y-18=3\\9z-18=2\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{14}{9}\\y=\dfrac{7}{3}\\z=\dfrac{20}{9}\end{matrix}\right.\)

Bn giỏi thế, làm giáo viên của mik ko

a) 11 - 3(2x - 1) = -8x + 5

⇔ 11 - 6x + 3 = -8x + 5

⇔ -6x + 8x = 5 - 11 - 3

⇔ 2x = -9

⇔ x = -9/2

Vậy S = {-9/2}

b) (x - 3)/5 + (1 + 2x)/3 = 6

⇔ 3(x - 3) + 5(1 + 2x) = 6.15

⇔ 3x - 9 + 5 + 10x = 90

⇔ 13x = 90 + 9 - 5

⇔ 13x = 94

⇔ x = 94/13

Vậy S = {94/13}

a, \(\dfrac{4x}{7}=\dfrac{1}{5}+\dfrac{2}{3}=\dfrac{3+10}{15}=\dfrac{13}{15}\Rightarrow60x=91\Leftrightarrow x=\dfrac{91}{60}\)

b, \(\dfrac{5}{7}:x=\dfrac{1}{6}+\dfrac{4}{5}=\dfrac{5+24}{30}=\dfrac{29}{30}\Leftrightarrow x=\dfrac{5}{7}:\dfrac{29}{30}=\dfrac{150}{203}\)

\(a,\dfrac{3}{4}:\dfrac{6}{x}=\dfrac{5}{4}\\ \dfrac{6}{x}=\dfrac{3}{4}:\dfrac{5}{4}\\ \dfrac{6}{x}=\dfrac{3}{5}\\ x=6:\dfrac{3}{5}\\ x=10\\ b,\left(x+\dfrac{7}{4}\right)\times\dfrac{2}{3}=6\\ x+\dfrac{7}{4}=6:\dfrac{2}{3}\\x+\dfrac{7}{4}=9\\ x=9-\dfrac{7}{4}\\ x=\dfrac{29}{4}\)

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