(2¹⁷ + 17²) . (9¹⁵ - 3¹⁵) . (2⁴ - 4²)

= (2¹⁷ + 17²) . (9¹⁵ - 3¹⁵) . (16 - 16)

= (2¹⁷ + 17²) . (9¹⁵ - 3¹⁵) . 0

= 0

1) (-37) + 14 + 26 + 37

= [(-37) + 37] + 14 + 26

= 0 + 40

= 40

2) (-24) + 6 + 10 + 24

= [(-24) + 24] + 6 + 10

= 0 + 16

= 16

3) 15 + 23 + (-25) + (-23)

= 15 + (-25) + [(-23) + 23]

= -10 + 0

= -10

4) 60 + 33 + (-50) + (-33)

= 60 + (-50) + [(-33) + 33]

= 10 + 0

= 10

a) 5/16 > -9/24

b) 5/6>-1/2

c)-7/12<3/4

a, 5/16 > -9/24

 b, 5/6 > -1/2 

c, -7/12 < 3/4

Ta có: \(\left|x-8\right|+\left|6-x\right|\ge\left|x-8+6-x\right|=2\forall x\)

\(\left(y+3\right)^2\ge0\forall y\)

=>\(5\left(y+3\right)^2\ge0\forall y\)

=>\(5\left(y+3\right)^2+12\ge12\forall y\)

=>\(\frac{24}{5\left(y+3\right)^2+12}\le\frac{24}{12}=2\forall y\)

Ta có: \(\left|x-8\right|+\left|6-x\right|=\frac{24}{5\left(y+3\right)^2+12}\)

mà \(\left|x-8\right|+\left|6-x\right|\ge\left|x-8+6-x\right|=2\forall x\)

và \(\frac{24}{5\left(y+3\right)^2+12}\le2\forall y\)

nên dấu '=' xảy ra khi \(\begin{cases}\left(x-8\right)\left(6-x\right)\ge0\\ y+3=0\end{cases}\Rightarrow\begin{cases}\left(x-8\right)\left(x-6\right)\le0\\ y=-3\end{cases}\Rightarrow\begin{cases}6\le x\le8\\ y=-3\end{cases}\)

Đề bài yêu cầu gì?

25

23

tìm y nha các bn

9/2 x Y - 5/2 x Y = 3/2

(9/2-5/2) x Y =3/2

4/2 x Y = 3/2

Y = 3/2 :4/2

Y = 3/2 x 2/4

Y = 3/4 like cho mình vs nhé