tính hợp lý : A = 3/13.7/9+-4/9.3/13.-10/9=
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a) 13.7 + 7.7
= (13 + 7).7
= 20 . 7
= 140
b) 23 . 2016 . 52
= 8 . 2016 . 25
= 200 . 2016
= 403200
c) 32 . 15 - 5.9
= 9.15 - 5.9
= (15 - 5).9
= 10.9
= 90
d) 13 + 15 + ........... + 57 + 59
Áp dụng công thức tính dãy số ta có :
\(\frac{\left[\left(59-13\right):2+1\right].\left(59+13\right)}{2}=\frac{24.72}{2}=864\)
a) 13 . 7 + 7 . 7
= (13 + 7) . 7
= 20 . 7
= 140
b) 23 . 2016 . 52
= 8 . 2016 . 25
= ( 8 . 25 ) . 2016
= 200 . 2016
= 403200
c) 32 . 15 - 5 . 9
= 9 . 15 - 45
= 9 . 15 - 15 . 3
= ( 9 - 3 ) . 15
= 6 . 15
= 90
d) 13 + 15 + ........ + 57 + 59
Dãy số trên có số số hạng là:
( 59 - 13 ) : 2 + 1= 24 ( số hạng )
Tổng của dãy số trên là:
( 59 + 13 ) x 24 : 2 = 864
a, A = ( 1/3 + 12/67 + 13/41 ) - ( 79/67 - 28/41 )
A = (\(\frac13\) + \(\frac{12}{67}\) + \(\frac{13}{41}\)) - (\(\frac{79}{67}\) - \(\frac{28}{41}\))
A = \(\frac13\) + \(\frac{12}{67}\) + \(\frac{13}{41}\) - \(\frac{79}{67}\) + \(\frac{28}{41}\)
A = - (\(\frac{79}{67}-\frac{12}{67}\)) + (\(\frac{13}{41}\) + \(\frac{28}{41}\))
A = - 1 + 1 + \(\frac13\)
A = 0 + \(\frac13\)
A = \(\frac13\)
b, B = 3/4×7 + 3/7×10 + 3/10×13 + ......+ 3/73×76
B = \(\frac{3}{4\times7}\) + \(\frac{3}{7\times10}\) + \(\frac{3}{10\times13}\) + ... + \(\frac{3}{73\times76}\)
B = \(\frac14-\frac17\) + \(\frac17-\frac{1}{10}\) + ... + \(\frac{1}{73}-\frac{1}{76}\)
B = \(\frac14\) - \(\frac{1}{76}\)
B = \(\frac{19}{76}-\) \(\frac{1}{76}\)
B = \(\frac{18}{76}\)
B = \(\frac{9}{38}\)
`a: =(7/3-4/3)+11/5=16/5`
`b: =(18/13-5/13)+55/46=1+55/46=101/46`
`c: =27/25-4/9-2/25+5/9=(27/25-2/25)+(5/9-4/9)=1+1/9=10/9`
13 - 12 + 11 - 10 - 9 + 8 - 7 - 6 + 5 - 4 + 3 + 2 - 1
= ( 13 - 12 + 11 - 10 + 8 ) - ( 9 + 1 ) - ( 6 + 4) + ( 3 + 2 + 5 ) - 7
= 10 - 10 - 10 + 10 - 7
= ( 10 - 10 ) - ( 10 - 10 ) - 7
= 0 - 0 - 7
= - 7
a; - \(\dfrac{10}{13}\) + \(\dfrac{5}{17}\) - \(\dfrac{3}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{11}{20}\)
= - (\(\dfrac{10}{13}\) + \(\dfrac{3}{13}\)) + (\(\dfrac{5}{17}\) + \(\dfrac{12}{17}\)) - \(\dfrac{11}{20}\)
= - 1 + 1 - \(\dfrac{11}{20}\)
= 0 - \(\dfrac{11}{20}\)
= - \(\dfrac{11}{20}\)
b; \(\dfrac{3}{4}\) + \(\dfrac{-5}{6}\) - \(\dfrac{11}{-12}\)
= \(\dfrac{9}{12}\) - \(\dfrac{10}{12}\) + \(\dfrac{11}{12}\)
= \(\dfrac{10}{12}\)
= \(\dfrac{5}{6}\)
c; [13.\(\dfrac{4}{9}\) + 2.\(\dfrac{1}{9}\)] - 3.\(\dfrac{4}{9}\)
= [\(\dfrac{52}{9}\) + \(\dfrac{2}{9}\)] - \(\dfrac{4}{3}\)
= \(\dfrac{54}{9}\) - \(\dfrac{4}{3}\)
= \(\dfrac{14}{3}\)
Câu a:
A = 7 2/13 - (5 2/13 + 2 1/2)
A = 7 2/13 - 5 2/13 - 2 1/2
A = 2 - 2 1/2
A = 2 - 2 - 1/2
A = 0 - 1/2
A = -1/2
Câu b:
B = - 3/4 + 25% : (10 3/10 - 9 4/5) - (-1/2)^2
B = - 3/4 + 1/4 : (103/10 - 49/5) - 1/4
B = - 3/4 + 1/4 : (103/10 - 98/5) - 1/4
B = (-3/4 - 1/4) + 1/4 : (1/2)
B = -1 + 1/4 x 2/1
B = -1 + 1/2
B = - 1/2
Câu a:
A = 7 2/13 - (5 2/13 + 2 1/2)
A = 7 2/13 - 5 2/13 - 2 1/2
A = 2 - 2 1/2
A = 2 - 2 - 1/2
A = 0 - 1/2
A = -1/2
Câu b:
B = - 3/4 + 25% : (10 3/10 - 9 4/5) - (-1/2)^2
B = - 3/4 + 1/4 : (103/10 - 49/5) - 1/4
B = - 3/4 + 1/4 : (103/10 - 98/5) - 1/4
B = (-3/4 - 1/4) + 1/4 : (1/2)
B = -1 + 1/4 x 2/1
B = -1 + 1/2
B = - 1/2
\(=\dfrac{3}{13}\left(\dfrac{7}{9}-\dfrac{4}{9}\right)-\dfrac{10}{9}=\dfrac{3}{13}\cdot\dfrac{3}{9}-\dfrac{10}{9}=-\dfrac{121}{117}\)