So sánh phân số 60/72 và 24/36 -13/18 và -7/12 4/15 và 7/18 123/321 và -312/213 Giúp với ạ
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a: \(\frac{60}{72}=\frac{60:12}{72:12}=\frac56\)
\(\frac{24}{36}=\frac{24:12}{36:12}=\frac23=\frac{2\times2}{3\times2}=\frac46\)
mà 5>4
nên \(\frac{60}{72}>\frac{24}{36}\)
b: \(\frac{-13}{18}=\frac{-13\times2}{18\times2}=\frac{-26}{36}\)
\(\frac{-7}{12}=\frac{-7\times3}{12\times3}=\frac{-21}{36}\)
mà -26<-21
nên \(-\frac{13}{18}<-\frac{7}{12}\)
c: \(\frac{4}{15}=\frac{4\times6}{15\times6}=\frac{24}{90}\)
\(\frac{7}{18}=\frac{7\times5}{18\times5}=\frac{35}{90}\)
mà 24<35
nên \(\frac{4}{15}<\frac{7}{18}\)
d: \(\frac{123}{321}>0;0>-\frac{312}{213}\)
Do đó: \(\frac{123}{321}>-\frac{312}{213}\)
\(\dfrac{3}{17}\) .\(\dfrac{6}{29}\) - \(\dfrac{3}{17}\).\(\dfrac{35}{29}\) + 2022\(\dfrac{3}{17}\)
= (\(\dfrac{3}{17}\).\(\dfrac{6}{29}\) - \(\dfrac{3}{17}\).\(\dfrac{35}{29}\)) + 2022 + \(\dfrac{3}{17}\)
= \(\dfrac{3}{17}\).(\(\dfrac{6}{29}\) - \(\dfrac{35}{29}\)) + 2022 + \(\dfrac{3}{17}\)
= \(\dfrac{3}{17}\).(-1) + 2022 + \(\dfrac{3}{17}\)
= (- \(\dfrac{3}{17}\) + \(\dfrac{3}{17}\)) + 2022
= 0 + 2022
= 2022
b; \(\dfrac{5}{6}\) - (\(\dfrac{1}{3}\) + \(\dfrac{1}{2}\)).20%
= \(\dfrac{5}{6}\) - \(\dfrac{5}{6}\).\(\dfrac{1}{5}\)
= \(\dfrac{5}{6}-\dfrac{1}{6}\)
= \(\dfrac{4}{6}\)
= \(\dfrac{2}{3}\)
Bài 1:
\(\dfrac{-5}{18}=\dfrac{-20}{72};\dfrac{7}{-24}=\dfrac{-21}{72}.\)
\(\dfrac{-15}{-40}=\dfrac{3}{8}=\dfrac{9}{24};\dfrac{24}{-72}=\dfrac{-1}{3}=\dfrac{-8}{24}.\)
Bài 3:
a) \(\dfrac{2}{3}h=\dfrac{8}{12}h;\dfrac{3}{4}h=\dfrac{9}{12}h.\Rightarrow\dfrac{2}{3}h< \dfrac{3}{4}h.\)
b) \(\dfrac{4}{5}km/h=\dfrac{8}{10}km/h;\dfrac{9}{10}km/h.\Rightarrow\dfrac{4}{5}km/h< \dfrac{9}{10}km/h.\)
\(\dfrac{5}{7}\)>\(\dfrac{6}{21}\)
\(\dfrac{18}{24}\)>\(\dfrac{15}{25}\)
\(\dfrac{12}{13}\)=\(\dfrac{1212}{1313}\)
a. 18/72 = 1/4
15/20 = 3/4
vì 1/4<3/4 nên 18/72<15/20
b. 24/36 = 2/3
20/50 = 2/5
2/3>2/5 nên 24/36>20/50
a, \(\dfrac{18}{72}\) = \(\dfrac{18:18}{72:18}\) = \(\dfrac{1}{4}\); \(\dfrac{15}{20}\) = \(\dfrac{3}{4}\)
Vì \(\dfrac{1}{4}\) < \(\dfrac{3}{4}\) nên \(\dfrac{18}{72}\) < \(\dfrac{15}{20}\)
b, \(\dfrac{24}{36}\) = \(\dfrac{24:12}{36:12}\) = \(\dfrac{2}{3}\); \(\dfrac{20}{50}\) = \(\dfrac{20:10}{50:10}\) = \(\dfrac{2}{5}\)
Vì \(\dfrac{2}{3}\) > \(\dfrac{2}{5}\) nên \(\dfrac{24}{36}\) > \(\dfrac{20}{50}\)
Câu 1:
a; x/7 = - 9/14
x = - 9/14 x 7
x = - 9/2
Vậy x = -9/2
b; - 16/36 = - y/4
-4/9 = - y/4
y = -4/9 x (-4)
y = 16/9
Vậy y = 16/9
Câu 1c:
-5/12 = x/60
x = -5/12 x 60
x = - 25
Vậy x = - 25
d: -4/8 = x/-10 = -7/y
-4/8 = x/-10
x = -4/8 x (-10)
x = 5
-4/8 = -7/y
y = - 7 : (-4/8)
y = 7 x 8/4
y = 14
Vậy (x; y) = (5; 14)
a: \(\frac{60}{72}=\frac{60:12}{72:12}=\frac56\)
\(\frac{24}{36}=\frac{24:12}{36:12}=\frac23=\frac{2\times2}{3\times2}=\frac46\)
mà 5>4
nên \(\frac{60}{72}>\frac{24}{36}\)
b: \(\frac{-13}{18}=\frac{-13\times2}{18\times2}=\frac{-26}{36}\)
\(\frac{-7}{12}=\frac{-7\times3}{12\times3}=\frac{-21}{36}\)
mà -26<-21
nên \(-\frac{13}{18}<-\frac{7}{12}\)
c: \(\frac{4}{15}=\frac{4\times6}{15\times6}=\frac{24}{90}\)
\(\frac{7}{18}=\frac{7\times5}{18\times5}=\frac{35}{90}\)
mà 24<35
nên \(\frac{4}{15}<\frac{7}{18}\)
d: \(\frac{123}{321}>0;0>-\frac{312}{213}\)
Do đó: \(\frac{123}{321}>-\frac{312}{213}\)