Bài 1:

<=>7[3(-x)]-12(x-5)=-3(11x-20)

=>-3(11x-20)=5

=>-33x=-55

=>-11.3x=-11.5 (rút gọn -11)

=>3x=5

\(\Rightarrow x=\frac{5}{3}\)

Đã duyệt

bài 1:

<=>7[3(-x)]-12(x-5)=-3(11x-20)

=>-3(11x-20)=5

=>-33x=-55

=>-11.3x=-11.5 (rút gọn -11)

=>3x=5

=>x=\(\frac{5}{3}\)

bai toan nay kho

mk...

                                                              ... ko bít

1: 6(x-2)-y(2-x)=10

=>6(x-2)+y(x-2)=10

=>(x-2)(y+6)=10

=>(x-2;y+6)∈{(1;10);(10;1);(-1;-10);(-10;-1);(2;5);(5;2);(-2;-5);(-5;-2)}

=>(x;y)∈{(3;4);(12;-5);(1;-16);(-8;-7);(4;-1);(7;-4);(0;-11);(-3;-8)}

2: 3x-2xy+3y=6

=>x(3-2y)+3y-4,5=6-4,5

=>-x(2y-3)+1,5(2y-3)=1,5

=>(2y-3)(-x+1,5)=1,5

=>(2y-3)(-2x+3)=3

=>(2x-3)(2y-3)=-3

=>(2x-3;2y-3)∈{(1;-3);(-3;1);(-1;3);(3;-1)}

=>(x;y)∈{(2;0);(0;2);(1;3);(3;1)}

3: 6x-xy+2y=5

=>x(6-y)+2y-12=5-12=-7

=>-x(y-6)+2(y-6)=-7

=>(y-6)(-x+2)=-7

=>(x-2)(y-6)=7

=>(x-2;y-6)∈{(1;7);(7;1);(-1;-7);(-7;-1)}

=>(x;y)∈{(3;13);(9;7);(1;-1);(-5;5)}

\(\frac{x}{2}=\frac{2}{3}+\frac{-1}{5}\)

\(\Rightarrow\frac{x}{2}=\frac{2}{3}-\frac{1}{5}\)(quy tắc chuyển vế đổi dấu)

\(\Rightarrow\frac{x}{2}=\frac{7}{15}\)

\(\Rightarrow x:2=\frac{7}{15}\)

\(\Rightarrow x=\frac{7}{15}.2=\frac{14}{15}\)

Nếu bạn không chắc kết quả này là đúng thì thử lại đi 

\(\frac{x}{2}=\frac{2}{3}+\frac{-1}{5}\)

=>\(\frac{x}{2}=\frac{13}{15}\)

=>\(\frac{x.15}{30}=\frac{26}{30}\)

=>x.15=26=\(\frac{26}{15}\)

=>x=26:15=

\(C=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}.....\dfrac{48}{49}.\dfrac{49}{50}=\dfrac{1}{50}\)

k minh minh giai cho

Các câu a; b; c xem lạ đề bài

Câu d:

-12.(x - 5)+ 7.(x - 3) = 5

-12x + 60 + 7x - 21 = 5

-(12x - 7x) + (60 - 21) = 5

-5x + 39 = 5

5x = 39 - 5

5x = 34

x = 34/5

Vậy x = 34/5

a. \(3-\frac{2}{2x-1}=\frac{2}{3}+\frac{2}{6x-3}-\frac{3}{2}\)

    \(3+\frac{3}{2}-\frac{2}{3}=\frac{2}{6x-3}+\frac{2}{2x-1}\)

    \(\frac{23}{6}=\frac{2}{6x-3}+\frac{6}{6x-3}\)

     \(\frac{23}{6}=\frac{8}{6x-3}\)\(\Rightarrow23.\left(6x-3\right)=48\) 

                                                      \(6x-3=\frac{48}{23}\)

                                                      \(6x=\frac{48}{23}+3=\frac{117}{23}\)

                                                       \(x=\frac{117}{23}:6=\frac{117}{23}.\frac{1}{6}=\frac{39}{46}\)

b . \(\frac{1}{2x+3}+\frac{-2}{3}.\left(\frac{3}{4}-\frac{6}{5}\right)=\frac{5}{4x+6}\)

      \(\frac{1}{2x+3}+\frac{-2}{3}.\frac{-9}{20}=\frac{5}{4x+6}\)

       \(\frac{1}{2x+3}+\frac{3}{10}=\frac{5}{4x+6}\)

       \(\frac{3}{10}=\frac{5}{4x+6}-\frac{1}{2x+3}\)\(=\frac{5}{4x+6}-\frac{2}{4x+6}\)

        \(\frac{3}{10}=\frac{3}{4x+6}\)\(\Rightarrow3.\left(4x+6\right)=30\)

                                                      \(4x+6=30:3=10\)

                                                      \(4x=10-6=4\)

                                                          \(x=4:4=1\)

a,x- 2/3= -1/2

x= -1/2 + 2/3

x= 1/6

b,20%.x - x +1/5 =3/4

1/5.x - x +1/5 = 3/4

1/5.x-x =3/4 - 1/5

x.(1/5 - 1)=11/20

x.-4/5 =11/20

x=11/20 : -4/5=-11/16

a)  \(x-\frac{2}{3}=-\frac{1}{2}\)

\(\Leftrightarrow x=\frac{2}{3}-\frac{1}{2}\)

\(\Leftrightarrow x=\frac{1}{6}\)

b)  \(20\%x-x+\frac{1}{5}=\frac{3}{4}\)

\(\Leftrightarrow\frac{1}{5}x-x=\frac{3}{4}-\frac{1}{5}\)

\(\Leftrightarrow-\frac{4}{5}x=\frac{11}{5}\)

\(\Leftrightarrow x=\frac{11}{5}:\left(-\frac{4}{5}\right)\)

\(\Leftrightarrow x=-\frac{11}{4}\)

a) -5/2 - 1/2x = -19/5

1/2x=-5/2 - (-19/5)

1/2x=13/10

x=13/10:1/2

x=13/5

a)   

\(-2,5-0,5\cdot x=-3,8\)

\(0,5\cdot x=1,3\)

\(x=2,6\)

b) 

\(-5x-2^5=3x+2^3\)

\(-5x-3x=2^5+2^3\)

\(-8x=40\)

\(x=-20\)

c)

\(-1-\left|x\right|=-9\)

\(\left|x\right|=8\)

\(\Rightarrow x=8\) hoặc \(x=-8\)

K MK NHÉ!