tim y
( 1/ 24x25 + 1/ 25x26 + ..... + 1/ 29x30 ) x 120 + y : 1/3 = -4
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\(\left(\frac{1}{25.26}+\frac{1}{26.27}+...+\frac{1}{29.30}\right)\cdot150+1,03\div\left[1,03\cdot\left(y-1\right)\right]\text{ }=22\)
\(\Rightarrow\left(\frac{1}{25}-\frac{1}{26}+\frac{1}{26}-\frac{1}{27}+...+\frac{1}{29}-\frac{1}{30}\right)\cdot150+1,03\div\left[1,03\cdot\left(y-1\right)\right]=22\)
\(\Rightarrow\left(\frac{1}{25}-\frac{1}{30}\right)\cdot150+1,03\div\left[1,03\cdot\left(y-1\right)\right]=22\)
\(\Rightarrow\frac{1}{150}\cdot150+1,03\div\left[1,03\left(y-1\right)\right]=22\)
\(\Rightarrow1+1,03\div\left[1,03\left(y-1\right)\right]=22\)
\(\Rightarrow1,03\left(y-1\right)=1,03\div\left(22-1\right)\)
\(\Rightarrow1,03y-1,03=1,03\div21\)
\(\Rightarrow1,03y=\frac{103}{2100}+1,03\)
\(\Rightarrow1,03y=\frac{1133}{1050}\)
\(\Rightarrow y=\frac{1133}{1050}\div\frac{103}{100}=\frac{1133}{1050}\cdot\frac{100}{103}=\frac{22}{21}\)
Vậy y = \(\frac{22}{21}\)
Dấu " . " là dấu nhân nhé
\(\left(\frac{1}{25\times26}+\cdot\cdot\cdot+\frac{1}{29\times30}\right)\times150+1\frac{3}{100}:[1\frac{3}{100}\times(y-1)]=22\)
\(\Rightarrow\left(\frac{1}{25}-\frac{1}{26}+\cdot\cdot\cdot+\frac{1}{29}-\frac{1}{30}\right)\times150:\left(y+1\right)=22\)
\(\Rightarrow\left(\frac{1}{25}-\frac{1}{30}\right)\times150:\left(y+1\right)=22\)
\(\Rightarrow\frac{1}{150}\times150:\left(y+1\right)=22\)
\(\Rightarrow1:\left(y+1\right)=22\)
\(\Rightarrow y+1=\frac{1}{22}\)
\(\Rightarrow y=\frac{1}{22}-1=\frac{-21}{22}\)
( 1/25 - 1/30 ) x 150 + 1,03 : 1,03 x ( x - 1 ) = 3 ( 1/150 x 150 + 1 x ( x - 1 ) = 3 1 + ( x - 1 ) = 3 x - 1 = 3 - 1 = 2 x = 1 + 2 x = 3
[ 1/ 25 x 26 + 1/26x27+....+ 1/29x30] x 150 + 103; 1,03 x ( x -1 ) =22
[ 1/25x26 + 1/26x27 + 1/27x28 + 1/28x29 + 1/29x30] x 150 + 103;1,03 x (x-1)=22
[ 1/650 + 1/702 + 1/756 + 1/812 + 1/870] x 150 + 103 ; 1,03 x (x-1) =22
1) ( y-25):4 - 120 = 0 2) 120 - ( x+25 )x4 = 0
( y-25 ):4 = 0+120 (x+25) x4 =120-0
( y-25):4 =120 (x+25) x4 =120
( y-25)=120x4 (x+25)=120:4
y-25=480 x+25=30
y=480+25 x=30-25
y=505 x=5
k mk nha
\(\dfrac{1}{1\times2}+\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+....+\dfrac{1}{24\times25}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{24}-\dfrac{1}{25}\)
\(=1-\dfrac{1}{25}\)
\(=\dfrac{24}{25}\)
a: \(\frac{52}{17}>\frac{51}{17}=3\)
\(3=\frac{121}{41}>\frac{120}{41}\)
Do đó: \(\frac{52}{17}>\frac{120}{41}\)
b: \(\frac34+\frac14:\left(\frac{7}{12}-\frac16\right)\)
\(=\frac34+\frac14:\left(\frac{7}{12}-\frac{2}{12}\right)\)
\(=\frac34+\frac14:\frac{5}{12}\)
\(=\frac34+\frac14\times\frac{12}{5}=\frac34+\frac35=\frac{15}{20}+\frac{12}{20}=\frac{27}{20}\)
c: \(372,463\cdot998+744,926\)
\(=372,463\cdot998+372,463\cdot2\)
\(=372,463\times\left(998+2\right)=372,463\times1000=372463\)
d: Số số hạng trong dãy số 2;4;6;...;100 là:
\(\left(100-2\right):2+1=98:2+1=49+1=50\) (số)
\(2-4+6-8+10-12+\cdots+98-100+102\)
\(=\left(2-4\right)+\left(6-8\right)+\cdots+\left(98-100\right)+102\)
=(-2)+(-2)+...+(-2)+102
\(=-2\cdot\frac{50}{2}+102=-50+102=52\)
e: (y+112)-113=79
=>y+112-113=79
=>y-1=79
=>y=79+1=80
f: \(\frac34-y=\frac12\)
=>\(y=\frac34-\frac12=\frac14\)
g: \(\left(\frac45-2\times y\right)+\frac16=\frac56\)
=>\(\frac45-2\times y=\frac56-\frac16=\frac46=\frac23\)
=>\(2\times y=\frac45-\frac23=\frac{12}{15}-\frac{10}{15}=\frac{2}{15}\)
=>\(y=\frac{2}{15}:2=\frac{1}{15}\)
h: (y+1)+(y+2)+...+(y+50)=1750
=>50y+(1+2+...+50)=1750
=>\(50y+50\times\frac{51}{2}=1750\)
=>50y+1275=1750
=>50y=1750-1275=475
=>\(y=\frac{475}{50}=9,5\)
(1/24x25 + 1/25x26 + ... + 1/29x30) x 120 + y : 1/3 = -4
(1/24 - 1/25 + 1/25 - 1/26 + ... + 1/29 - 1/30) x 120 + y x 3 = -4
(1/24 - 1/30) x 120 + y x 3 = -4
1/120 x 120 + y x 3 = -4
=> 1 + y x 3 = -4
=> y x 3 = -4 - 1
=> y x 3 = -5
=> y = -5/3
Vậy x = -5/3
Ủng hộ mk nha ^_-
(1/24x25 + 1/25x26 + ... + 1/29x30) x 120 + y : 1/3 = -4
(1/24 - 1/25 + 1/25 - 1/26 + ... + 1/29 - 1/30) x 120 + y x 3 = -4
(1/24 - 1/30) x 120 + y x 3 = -4
1/120 x 120 + y x 3 = -4
=> 1 + y x 3 = -4
=> y x 3 = -4 - 1
=> y x 3 = -5
=> y = -5/3
Vậy x = -5/3
T_I_C_K mk nha