S_xq\(=2\times2\times\left(4+3\right)=2\times2\times7=28\left(m^2\right)\)

S_tp=\(28+2\times4\times3=28+24=52\left(m^2\right)\)

\(V=4\times3\times2=24\left(m^3\right)\)

A

A

Câu 5: C

Câu 6: B

Thanks nhìu!🥰

\(\Leftrightarrow\left(x^2-x\right)^2-x^2+x-30=0\)

\(\Leftrightarrow\left(x^2-x\right)^2-\left(x^2-x\right)-30=0\)

\(\Leftrightarrow\left(x^2-x-6\right)\left(x^2-x+5\right)=0\)

\(\Leftrightarrow x^2-x-6=0\)

=>(x-3)(x+2)=0

=>x=3 hoặc x=-2

`(x^2 -x)^2 +x=x^2 +30`

`<=>(x^2 -x)^2 -(x^2 -x)-30=0`

Đặt `t=x^2 -x`

`t^2 -t-30=0`

`<=>t^2 -6t+5t-30=0`

`<=>t(t-6)+5(t-6)=0`

`<=>(t-6)(t+5)=0`

`<=>[(t-6=0),(t+5=0):}`

`<=>[(x^2 -x-6=0),(x^2 -x+5=0):}`

`<=>x^2 -x-6=0`

`<=>x^2 -3x+2x-6=0`

`<=>x(x-3)+2(x-3)=0`

`<=>(x-3)(x+2)=0`

`<=>[(x-3=0),(x+2=0):}`

`<=>[(x=3),(x=-2):}`

Vậy `S={-2;3}`

Một đống như z ai làm đc :v

là số 4 

12 nhé

thanks you bạn nhìu =)

a: \(\frac13-2\frac56+\frac{12}{9}\)

\(=\frac13+\frac43-\frac{17}{6}\)

\(=\frac53-\frac{17}{6}=\frac{10}{6}-\frac{17}{6}=-\frac76\)

b: \(\frac12\cdot\frac56+\frac23\cdot\frac34\)

\(=\frac{5}{12}+\frac{6}{12}=\frac{5+6}{12}=\frac{11}{12}\)

c: \(\left(-\frac37+\frac14\right):\frac{15}{28}\)

\(=\left(-\frac{12}{28}+\frac{7}{28}\right)\cdot\frac{28}{15}\)

\(=-\frac{5}{15}=-\frac13\)

d: \(\frac23-\left(-\frac15\right)-\frac{4}{15}\)

\(=\frac23+\frac15-\frac{4}{15}\)

\(=\frac{10}{15}+\frac{3}{15}-\frac{4}{15}=\frac{9}{15}=\frac35\)

e: \(-\frac{3}{16}\cdot\frac{8}{15}+\frac{-3}{16}\cdot\frac{7}{15}-\frac{5}{16}\)

\(=-\frac{3}{16}\left(\frac{8}{15}+\frac{7}{15}\right)-\frac{5}{16}\)

\(=-\frac{3}{16}-\frac{5}{16}=-\frac{8}{16}=-\frac12\)

f: \(-\frac{20}{23}+\frac23-\frac{3}{23}+\frac25+\frac{7}{15}\)

\(=\left(-\frac{20}{23}-\frac{3}{23}\right)+\frac{10}{15}+\frac{6}{15}+\frac{7}{15}\)

\(=-\frac{23}{23}+\frac{23}{15}=-1+\frac{23}{15}=\frac{8}{15}\)

g: \(\frac57\cdot\frac{5}{11}+\frac57\cdot\frac{2}{11}-\frac57\cdot\frac{14}{11}\)

\(=\frac57\left(\frac{5}{11}+\frac{2}{11}-\frac{14}{11}\right)\)

\(=\frac57\cdot\left(-\frac{7}{11}\right)=-\frac{5}{11}\)

h: \(-\frac57\cdot\frac{3}{13}-\frac57\cdot\frac{10}{13}+1\frac57\)

\(=-\frac57\left(\frac{3}{13}+\frac{10}{13}\right)+1+\frac57\)

\(=-\frac57+1+\frac57=1\)

i: \(\frac74\cdot\frac{29}{5}-\frac75\cdot\frac94+3\frac{2}{13}\)

\(=\frac74\cdot\left(\frac{29}{5}-\frac95\right)+3+\frac{2}{13}\)

\(=\frac74\cdot4+3+\frac{2}{13}=10+\frac{2}{13}=\frac{132}{13}\)

63869252 bạn nhé