k: \(147\left(19-137\right)-137\left(19-147\right)\)

\(=147\cdot19-147\cdot137-137\cdot19+137\cdot147\)

\(=147\cdot19-137\cdot19\)

\(=19\left(147-137\right)=19\cdot10=190\)

m: \(254\left(195-454\right)-454\left(195-254\right)\)

\(=254\cdot195-254\cdot454-454\cdot195+454\cdot254\)

\(=195\cdot254-195\cdot454\)

\(=195\left(254-454\right)\)

\(=-200\cdot195=-39000\)

n: \(\left(-197\right)\left(24-187\right)-187\cdot\left(197-24\right)\)

\(=-197\cdot24+197\cdot187-187\cdot197+187\cdot24\)

\(=-197\cdot24+187\cdot24\)

\(=24\left(-197+187\right)=24\cdot\left(-10\right)=-240\)

o: \(\left(-248\right)\cdot\left(19-148\right)-148\left(248-19\right)\)

\(=-248\cdot19+248\cdot148-148\cdot248+148\cdot19\)

\(=-19\cdot248+148\cdot19\)

\(=-19\left(248-148\right)\)

\(=-19\cdot100=-1900\)

p: \(\left(-964\right)\left(25+864\right)-864\left(25-964\right)\)

\(=-964\cdot25-964\cdot864-864\cdot25+864\cdot964\)

\(=-964\cdot25-864\cdot25\)

\(=25\cdot\left(-964-864\right)\)

\(=25\left(-1828\right)=-45700\)

q: \(\left(-437\right)\left(17-487\right)-487\cdot\left(437-17\right)\)

\(=-437\cdot17+437\cdot487-487\cdot437+487\cdot17\)

\(=-437\cdot17+487\cdot17\)

\(=17\left(487-437\right)=17\cdot50=850\)

Giúp e mấy bài đó đi mn ạ

what is her mother going to prepare for her bỉthdat party

there are three sticks of butter in the cupboard

website mạng xã hội là : 
B. Facebook.com 

B

Bài 3:

\(a,\) Gọi \(\left(d\right):y=ax+b\) là đt cần tìm

\(\Leftrightarrow\left\{{}\begin{matrix}a=2\\0a+b=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}a=2\\b=1\end{matrix}\right.\Leftrightarrow\left(d\right):y=2x+1\)

\(b,\) PT hoành độ giao điểm:

\(-x^2=2x+1\Leftrightarrow\left(x+1\right)^2=0\Leftrightarrow x=-1\Leftrightarrow y=-1\Leftrightarrow A\left(-1;-1\right)\)

Vậy \(A\left(-1;-1\right)\) là tọa độ giao điểm (P) và (d)

Bài 4:

PT có 2 nghiệm \(\Leftrightarrow\Delta'=16-3m\ge0\Leftrightarrow m\le\dfrac{16}{3}\)

Áp dụng Viét: \(\left\{{}\begin{matrix}x_1+x_2=\dfrac{8}{3}\\x_1x_2=\dfrac{m}{3}\end{matrix}\right.\)

Mà \(x_1^2+x_2^2=\dfrac{82}{9}\Leftrightarrow\left(x_1+x_2\right)^2-2x_1x_2=\dfrac{82}{9}\)

\(\Leftrightarrow\dfrac{64}{9}-\dfrac{2m}{3}=\dfrac{82}{9}\\ \Leftrightarrow\dfrac{2m}{3}=-2\Leftrightarrow m=-3\left(tm\right)\)

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