Bài 1:tìm x,y thuộc N biết 3^x+4^y=5^x
Bài 2:so sánh (-32)^9 và (-18)^13
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Bài 1:
b: \(\frac{\frac37-\frac{3}{13}+\frac{3}{17}}{\frac57-\frac{5}{13}+\frac{5}{17}}\)
\(=\frac{3\left(\frac17-\frac{1}{13}+\frac{1}{17}\right)}{5\left(\frac17-\frac{1}{13}+\frac{1}{17}\right)}=\frac35\)
c: \(\frac{5^4\cdot4^4\cdot5^4}{5^{10}\cdot4^5}=\frac{5^8\cdot4^4}{5^{10}\cdot4^5}=\frac{1}{5^2\cdot4}=\frac{1}{100}\)
d: \(\left|x-2007\right|+\left|2y-2020\right|^{2021}=0\)
=>x-2007=0 và 2y-2020=0
=>x=2007 và 2y=2020
=>x=2007 và y=1010
Bài 2:
b: \(A=\frac{1}{2^2}+\frac{1}{2^4}+\cdots+\frac{1}{2^{100}}\)
=>\(4A=1+\frac{1}{2^2}+\cdots+\frac{1}{2^{98}}\)
=>4A-A=\(1+\frac{1}{2^2}+\cdots+\frac{1}{2^{98}}-\frac{1}{2^2}-\frac{1}{2^4}-\cdots-\frac{1}{2^{100}}\)
=>3A=\(1-\frac{1}{2^{100}}\)
=>3A<1
=>A<1/3
c: \(H=\left|x-3\right|+\left|4+x\right|\)
\(=\left|x+4\right|+\left|3-x\right|\ge\left|x+4+3-x\right|=7\forall x\)
Dấu '=' xảy ra khi (x-3)(x+4)<=0
=>-4<=x<=3
Câu 1:
a; x/7 = - 9/14
x = - 9/14 x 7
x = - 9/2
Vậy x = -9/2
b; - 16/36 = - y/4
-4/9 = - y/4
y = -4/9 x (-4)
y = 16/9
Vậy y = 16/9
Câu 1c:
-5/12 = x/60
x = -5/12 x 60
x = - 25
Vậy x = - 25
d: -4/8 = x/-10 = -7/y
-4/8 = x/-10
x = -4/8 x (-10)
x = 5
-4/8 = -7/y
y = - 7 : (-4/8)
y = 7 x 8/4
y = 14
Vậy (x; y) = (5; 14)
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