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25 tháng 1 2021

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25 tháng 1 2021

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25 tháng 9

Bài 1:

b: \(\frac{\frac37-\frac{3}{13}+\frac{3}{17}}{\frac57-\frac{5}{13}+\frac{5}{17}}\)

\(=\frac{3\left(\frac17-\frac{1}{13}+\frac{1}{17}\right)}{5\left(\frac17-\frac{1}{13}+\frac{1}{17}\right)}=\frac35\)

c: \(\frac{5^4\cdot4^4\cdot5^4}{5^{10}\cdot4^5}=\frac{5^8\cdot4^4}{5^{10}\cdot4^5}=\frac{1}{5^2\cdot4}=\frac{1}{100}\)

d: \(\left|x-2007\right|+\left|2y-2020\right|^{2021}=0\)

=>x-2007=0 và 2y-2020=0

=>x=2007 và 2y=2020

=>x=2007 và y=1010

Bài 2:

b: \(A=\frac{1}{2^2}+\frac{1}{2^4}+\cdots+\frac{1}{2^{100}}\)

=>\(4A=1+\frac{1}{2^2}+\cdots+\frac{1}{2^{98}}\)

=>4A-A=\(1+\frac{1}{2^2}+\cdots+\frac{1}{2^{98}}-\frac{1}{2^2}-\frac{1}{2^4}-\cdots-\frac{1}{2^{100}}\)

=>3A=\(1-\frac{1}{2^{100}}\)

=>3A<1

=>A<1/3

c: \(H=\left|x-3\right|+\left|4+x\right|\)

\(=\left|x+4\right|+\left|3-x\right|\ge\left|x+4+3-x\right|=7\forall x\)

Dấu '=' xảy ra khi (x-3)(x+4)<=0

=>-4<=x<=3

27 tháng 2

Câu 1:

a; x/7 = - 9/14

x = - 9/14 x 7

x = - 9/2

Vậy x = -9/2

b; - 16/36 = - y/4

-4/9 = - y/4

y = -4/9 x (-4)

y = 16/9

Vậy y = 16/9


27 tháng 2

Câu 1c:

-5/12 = x/60

x = -5/12 x 60

x = - 25

Vậy x = - 25

d: -4/8 = x/-10 = -7/y

-4/8 = x/-10

x = -4/8 x (-10)

x = 5

-4/8 = -7/y

y = - 7 : (-4/8)

y = 7 x 8/4

y = 14

Vậy (x; y) = (5; 14)