a: \(a\in\left\{240;480\right\}\)

a: =4-10

=-6

a, \(\dfrac{\sqrt{80}}{\sqrt{5}}\)-\(\sqrt{5}\).\(\sqrt{20}\)= \(\sqrt{16}\)-10=-6

b, (\(\sqrt{28}\)-\(\sqrt{12}\)-\(\sqrt{7}\))\(\sqrt{7}\)+2\(\sqrt{21}\)=\(\sqrt{196}\)-\(\sqrt{84}\)-7+2 \(\sqrt{21}\)=14-7=7

c, \(\sqrt[3]{2}\).\(\sqrt[3]{32}\)+\(\sqrt{2}\).\(\sqrt{32}\)=\(\sqrt[3]{64}\)+\(\sqrt{64}\)=4+8=12

d, \(2\sqrt{8\sqrt{3}}\)-\(\sqrt{2\sqrt{3}}\)-\(\sqrt{9\sqrt{12}}\)=\(4\sqrt{12}\)-\(\sqrt{12}\)-\(3\sqrt{12}\)=0

b: \(=\sqrt{5}-2-\sqrt{5}=-2\)

4: Chiều rộng của sân là 42:4=10,5(m)

=>Chiều dài của sân cũng là 10,5(m)

Diện tích cái sân là:

\(10,5\times10,5=110,25\left(m^2\right)\)

3:

a: \(137dam^2=1ha37dam^2\)

b: 6km93m=6,093km

c: 2,03 tấn=2 tấn 30kg

d: \(958dm^2=9m^258dm^2\)

Ta có : 

\(S=\left(1+\frac{1}{3}+..+\frac{1}{2011}+\frac{1}{2013}\right)-\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{2012}\right)\)

\(=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2012}+\frac{1}{2013}\right)-2\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{2012}\right)\)

\(=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2012}+\frac{1}{2013}\right)-\left(1+\frac{1}{2}+...+\frac{1}{1006}\right)\)

\(=\frac{1}{1007}+\frac{1}{1008}+...+\frac{1}{2013}=P\)

\(\Rightarrow\left(s-p\right)^{2013}=0^{2013}=0\)

Thanks bạn nhiều nhé!! Tặng bạn 1 tk :>

Physical Education :)))

Physical Education nha bạn