lẹ

gấp

Mày ra câu hỏi từ từ người ta trả lới cho chứ cứ hối người ta 😡

Ói , hoa mắt chóng mặt nhức đầu ,

sao giống có chữa quá z

tìm x,y nhé

bn nào làm trong 10phuts mk tick

a) 3x(x + 1) - 5y(x + 1)

= (x + 1)(3x - 5y)

b) 3x(x - 6) - 2(x - 6)

= (x - 6)(3x - 2)

c) 4y(x - 1) - (1 - x)

= 4y(x - 1) + (x - 1)

= (x - 1)(4y + 1)

d) (x - 3)³ + 3 - x

= (x - 3)³ - (x - 3)

= (x - 3)[(x - 3)² - 1]

= (x - 3)(x - 3 - 1)(x - 3 + 1)

= (x - 3)(x - 4)(x - 2)

e) 7x(x - y) - (y - x)

= 7x(x - y) + (x - y)

= (x - y)(7x + 1)

h) 3x³(2y - 3z) - 15x(2y - 3z)²

= (2y - 3z)[3x³ - 15x(2y - 3x)]

= 3x(2y - 3x)[x² - 5(2y - 3x)]

= 3x(2y - 3x)(x² - 10y + 3x)

= 3x(2y - 3x)(x² + 3x - 10y)

k) 3x(x + 2) + 5(-x - 2)

= 3x(x + 2) - 5(x + 2)

= (x + 2)(3x - 5)

l) 18x²(3 + x) + 3(x + 3)

= (x + 3)(18x² + 3)

= 3(x + 3)(6x² + 1)

m) 7x(x - y) - (y - x)

= 7x(x - y) + (x - y)

= (x - y)(7x + 1)

n) 10x(x - y) - 8y(y - x)

= 10x(x - y) + 8y(x - y)

= (x - y)(10x + 8y)

= 2(x - y)(5x + 4y)

bn vô danh giúp mik với ;-;

ũa thế không phải vô danh giúp có được khong?

a) \(\left(x^2-\dfrac{1}{3}\right)\left(x^4+\dfrac{1}{3}x^2+\dfrac{1}{9}\right)\) (sửa \(\dfrac{x}{2}\rightarrow x^2\))

\(=\left(x^2\right)^3-\left(\dfrac{1}{3}\right)^3\)

\(=x^6-\dfrac{1}{27}\)

b) \(\left(\dfrac{1}{3}x+2y\right)\left(\dfrac{1}{9}x^2-\dfrac{2}{3}xy+4y^2\right)\)

\(=\left(\dfrac{1}{3}x\right)^3+\left(2y\right)^3\)

\(=\dfrac{1}{27}x^3+8y^3\)

Lưu ý : Áp dụng hằng đẳng thức đáng nhớ \(a^3\pm b^3=...\)

Thank you

1: \(\frac{2x+6}{3x^2-x}:\frac{x^2+3x}{1-3x}\)

\(=\frac{2\left(x+3\right)}{x\left(3x-1\right)}\cdot\frac{-3x+1}{x\left(x+3\right)}\)

\(=\frac{2}{x}\cdot\frac{-\left(3x-1\right)}{x\left(3x-1\right)}=\frac{-2}{x^2}\)

2: \(\frac{x}{x-2y}+\frac{x}{x+2y}+\frac{4xy}{4y^2-x^2}\)

\(=\frac{x}{x-2y}+\frac{x}{x+2y}-\frac{4xy}{\left(x-2y\right)\left(x+2y\right)}\)

\(=\frac{x\left(x+2y\right)+x\left(x-2y\right)-4xy}{\left(x-2y\right)\left(x+2y\right)}=\frac{2x^2-4xy}{\left(x-2y\right)\left(x+2y\right)}\)

\(=\frac{2x\left(x-2y\right)}{\left(x-2y\right)\left(x+2y\right)}=\frac{2x}{x+2y}\)

3: \(\frac{1}{3x-2}-\frac{1}{3x+2}-\frac{3x-6}{4-9x^2}\)

\(=\frac{1}{3x-2}-\frac{1}{3x+2}+\frac{3x-6}{\left(3x-2\right)\left(3x+2\right)}\)

\(=\frac{3x+2-\left(3x-2\right)+3x-6}{\left(3x-2\right)\left(3x+2\right)}=\frac{3x+2-3x+2+3x-6}{\left(3x-2\right)\left(3x+2\right)}\)

\(=\frac{3x-2}{\left(3x-2\right)\left(3x+2\right)}=\frac{1}{3x+2}\)

4: \(\frac{x+3}{x+1}+\frac{2x-1}{x-1}+\frac{x+5}{x^2-1}\)

\(=\frac{x+3}{x+1}+\frac{2x-1}{x-1}+\frac{x+5}{\left(x-1\right)\left(x+1\right)}\)

\(=\frac{\left(x+3\right)\left(x-1\right)+\left(2x-1\right)\left(x+1\right)+x+5}{\left(x-1\right)\left(x+1\right)}\)

\(=\frac{x^2+2x-3+2x^2+2x-x-1+x+5}{\left(x-1\right)\left(x+1\right)}=\frac{3x^2+4x+1}{\left(x-1\right)\left(x+1\right)}\)

\(=\frac{\left(3x+1\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}=\frac{3x+1}{x-1}\)