cái này tính cái gì thế

ko hiểu

M=1−31​+1−151​+1−351​+1−631​+...+1−99991​

\(� = \left(\right. 1 + 1 + 1 + . . . + 1 \left.\right) - \left(\right. \frac{1}{3} + \frac{1}{15} + \frac{1}{35} + \frac{1}{63} + . . . + \frac{1}{9999} \left.\right)\)

\(� = \left(\right. 1 + 1 + 1 + . . . + 1 \left.\right) - \left(\right. \frac{1}{1.3} + \frac{1}{3.5} + \frac{1}{5.7} + \frac{1}{7.9} + . . . + \frac{1}{99.101} \left.\right)\)(Có (99 - 1): 2+ 1 = 50 số 1)

\(� = 50 - \frac{1}{2} . \left(\right. \frac{2}{1.3} + \frac{2}{3.5} + \frac{2}{5.7} + \frac{2}{7.9} + . . . + \frac{2}{99.101} \left.\right)\)

\(� = 50 - \left(\right. 1 - \frac{1}{3} + \frac{1}{3} - \frac{1}{5} + \frac{1}{5} - \frac{1}{7} + \frac{1}{7} - \frac{1}{9} + . . . + \frac{1}{99} - \frac{1}{101} \left.\right)\)

\(� = 50 - \left(\right. 1 - \frac{1}{101} \left.\right) = 50 - \frac{100}{101} = \frac{5050 - 100}{101} = \frac{4950}{101}\)

Bài 7:

a) = 35 + 75 + 345 - 35 - 75

    = 345

b) = 2002 - 75 + 15 + 79 - 15

    = 2006

c) = - 515 + 80 - 91 - 2003 - 80 + 91

    = -2518

Bài 8:

a) = (4573 + 4573) + (46 - 16) + (35 - 5)

    = 9146 + 30 + 30

    = 9206

b) = (32 + 38) + (34+36) - (12+18) - (14+16) - 10

    = 70 + 70 - 30 - 30 - 10

    = 70

BÀI 7

a) (37+75)+(345-35-75)

=345

b) (2002-75+15)-(-79+15)

=2002

c) -(515-80+91)-(2003+80-91)

=-2518

BÀI 8 

a)4573+46+4573+35-16-5

=(4573+4573)+(46-10)+(35-5)

=9146+30+30

=9206

b) có 2 cách

bạn có thể làm theo cáchVũ Như Mai hoặc theo cách của mình

=32+34+36+38-10-12-14-16-18

=(32-12)+(34-14)+(36-16)+(38-18)-10

=20+20+20+20-10

=80-10=70

\(\left|x+1\right|và\left|x+2\right|\ge0\)

\(\Rightarrow\orbr{\begin{cases}\left(x+1\right)+\left(x+2\right)=3\\\left(x+1\right)+\left(x+2\right)=-3\end{cases}}\)

\(\orbr{\begin{cases}2x+3=3\\2x+3=-3\end{cases}}\)

\(\orbr{\begin{cases}2x=0\\2x=-6\end{cases}}\)

\(\orbr{\begin{cases}x=0\\x=-3\end{cases}}\)

\(\left|x+1\right|+\left|x+2\right|=3\)

Xét \(x+1\ge0;x+2\ge0\Leftrightarrow x\ge-1;x\ge-2\Rightarrow x\ge-1\) ta có : \(\hept{\begin{cases}\left|x+1\right|=x+1\\\left|x+2\right|=x+2\end{cases}}\)

\(\Rightarrow\left|x+1\right|+\left|x+2\right|=3\Leftrightarrow x+1+x+2=3\Leftrightarrow2x+3=3\Rightarrow x=0\)(TM)

Xét \(x+1\le0;x+2\ge0\Leftrightarrow-2\le x\le-1\) ta có : \(\hept{\begin{cases}\left|x+1\right|=-x-1\\\left|x+2\right|=x+2\end{cases}}\)

\(\Rightarrow\left|x+1\right|+\left|x+2\right|=3\Leftrightarrow-x-1+x+2=3\Leftrightarrow1=3\) (loại)

Xét \(x+1\le0;x+2\le0\Leftrightarrow x\le-1;x\le-2\Leftrightarrow x\le-2\) ta có : \(\hept{\begin{cases}\left|x+1\right|=-x-1\\\left|x+2\right|=-x-2\end{cases}}\)

\(\Rightarrow\left|x+1\right|+\left|x+2\right|=-x-1-x-2=-2x-3=3\Rightarrow x=-3\)(TM)

Vậy \(x=\left\{-3;0\right\}\)

a) 2575+37-2576-29=(2575+2576)-29+37=-1-29+37=-30+37=7

b)34+35+36+37-14-15-16-17=(34-14)+(35-15)+(36-16)+(37-17)=20+20+20+20=80

X

a,2575+37-2576-29=37+[(2575-2576)-29]=37+(-30)=7

b,34+35+36+37-14-15-16-17=(34-14)+(35-15)+(36-16)+(37-17)=20+20+20+20=80