\(M=\frac{\left(a^{\frac{1}{3}}+b^{\frac{1}{3}}\right)^2}{\sqrt[3]{ab}}:\left(2+\sqrt[3]{\frac{a}{b}}+\sqrt[3]{\frac{b}{a}}\right)=\frac{\left(a^{\frac{1}{3}}+b^{\frac{1}{3}}\right)^2}{\sqrt[3]{ab}}:\frac{2\sqrt[3]{ab}+\left(\sqrt[3]{a}\right)^2+\left(\sqrt[3]{a}\right)^2}{\sqrt[3]{ab}}\)

    \(=\frac{\left(\sqrt[3]{a}+\sqrt[3]{b}\right)^2}{\sqrt[3]{ab}}-\frac{\sqrt[3]{ab}}{\left(\sqrt[3]{a}+\sqrt[3]{b}\right)^2}=1\)

\(M=lg\left|\log_{\frac{1}{a^3}}\sqrt[5]{a\sqrt{a}}\right|=lg\left|\log_{\frac{1}{a^3}}\sqrt[5]{a.a^{\frac{1}{2}}}\right|=lg\left|\log_{\frac{1}{a^3}}\left(a^{\frac{3}{2}}\right)^{\frac{1}{5}}\right|=lg\left|\log_{a^{-3}}a^{\frac{3}{10}}\right|=lg\left|-\frac{1}{10}=lg\frac{1}{10}=-1\right|\)

mờ quá bạn

:v

\(T=\left(\sqrt[7]{\frac{a}{b}\sqrt[5]{\frac{b}{a}}}\right)^{\frac{35}{4}}=\left\{\left[\left(\frac{b}{a}\right)^{-1}\left(\frac{b}{a}\right)^{\frac{1}{5}}\right]^{\frac{1}{7}}\right\}^{\frac{35}{4}}=\left[\left(\frac{b}{a}\right)^{-\frac{4}{5}}\right]=\frac{a}{b}\)

\(T=\left(\sqrt[7]{\frac{a}{b}\sqrt[5]{\frac{b}{a}}}\right)^{\frac{35}{4}}=\sqrt[4]{\left(\sqrt[7]{\frac{a}{b}\sqrt[5]{\frac{b}{a}}}\right)^{35}}=\sqrt[4]{\left(\frac{a}{b}\sqrt[5]{\frac{b}{a}}\right)^5}\)

\(=\sqrt[4]{\left(\frac{a}{b}\right)^5.\frac{b}{a}}=\sqrt[4]{\left(\frac{a}{b}\right)^4}=\frac{a}{b}\)

B xem lại đề bài thử nhé

bài này mình cũng dò lại đề rồi mình chép đúng đấy mà không làm được nên mới nhờ giải

\(A=\frac{\sqrt{2}+\sqrt{3}+\sqrt{6}+\sqrt{8}+4}{\sqrt{2}+\sqrt{3}+\sqrt{4}}=\frac{\left(\sqrt{2}+\sqrt{3}+\sqrt{4}\right)+\left(\sqrt{4}+\sqrt{6}+\sqrt{8}\right)}{\sqrt{2}+\sqrt{3}+\sqrt{4}}=\frac{\left(1+\sqrt{2}\right)\left(\sqrt{2}+\sqrt{3}+\sqrt{4}\right)}{\sqrt{2}+\sqrt{3}+\sqrt{4}}=1+\sqrt{2}\)