\(a,\frac{2}{3}=\frac{x}{54}\)

\(\Rightarrow2.54=3x\)

\(\Rightarrow3x=108\)

\(\Rightarrow x=108:3=36\)

\(b,\frac{10}{x}=\frac{15}{6}\)

\(\Rightarrow10.6=15x\)

\(\Rightarrow15x=60\)

\(\Rightarrow x=60:15=4\)

\(c,\frac{2}{3}< \frac{x}{6}< 1\)

\(\Rightarrow\frac{4}{6}< \frac{x}{6}< \frac{6}{6}\)

\(\Rightarrow4< x< 6\)

\(\Rightarrow x=5\)

\(d,1< \frac{6}{x}< 2\)

\(\Rightarrow\frac{6}{6}< \frac{6}{x}< \frac{6}{3}\)

\(\Rightarrow6< x< 3\)

\(\Rightarrow x=5;4\)

a)x=54.2:3=36

b)x=10.6:15=4

c)x = 5

d)x=4 hoặc x=5

a) 2/3=36/54  => x=36

b)15/6=10/3  =>x=3

\(a,\frac{2}{3}=\frac{x}{54}\Rightarrow x=\frac{2\times54}{3}\Rightarrow x=36\)

\(b,\frac{10}{x}=\frac{15}{6}\Rightarrow x=\frac{10\times6}{15}\Rightarrow x=4\)

\(c,\frac{2}{3}< \frac{x}{6}< 1\Rightarrow\frac{2}{3}\times6< x< 1\times6\Rightarrow4< x< 6\)

CMR A = 1/5 + 1/6 + 1/7 + ... + 1/17 < 2

A = 1/5 + 1/6 + 1/7 + ... + 1/17

Vì 1/6 < 1/7 < 1/8 < 1/9 < 1/5 và 1/10 < 1/11 < 1/12 < 1/13 < 1/14 <1/15 < 1/16 < 1/17 < 1/8 nên:

A = (1/5 + 1/6 + 1/7 + 1/8 + 1/9) + (1/10 + 1/11 + 1/12 + 1/13 + 1/14+ 1/15 + 1/16 + 1/17)

A < (1/5 + 1/5 + 1/5 + 1/5 + 1/5) + (1/8 + 1/8 + 1/8 + 1/8 + 1/8+1/8 + 1/8 + 1/8)

A < 1 + 1

A < 2

Vậy: A < 2 (đpcm)

Bạn ơi hình như là sai đề bạn ạ

sai ở đâu vậy

$A=\frac{1}{2}.\frac{3}{4}.\frac{5}{6}...\frac{99}{100}$

$\Rightarrow A<\frac{2}{3}.\frac{4}{5}.\frac{6}{7}...\frac{100}{101}$

$\Rightarrow A^2<\frac{2}{3}.\frac{4}{5}.\frac{6}{7}...\frac{100}{101}.\frac{1}{2}.\frac{3}{4}.\frac{5}{\mathrm{...}}$

thanks

$A=\frac{1}{2}.\frac{3}{4}.\frac{5}{6}...\frac{99}{100}$

$\Rightarrow A<\frac{2}{3}.\frac{4}{5}.\frac{6}{7}...\frac{100}{101}$

$\Rightarrow A^2<\frac{2}{3}.\frac{4}{5}.\frac{6}{7}...\frac{100}{101}.\frac{1}{2}.\frac{3}{4}.\frac{5}{\mathrm{...}}$