Tính tổng các số nguyên x bt nhé mik viết thiêu

Ý 1)

\(x\in\left\{-18;\pm17;\pm16;\pm15;....;0\right\}\)

Tổng các số nguyên x: \(S1=-18+\left(-17+17\right)+\left(-16+16\right)+....+\left(-2+2\right)+\left(-1+1\right)+0\\ =-18+0+0+...+0+0+0=-18\)

Ý 2)

\(x\in\left\{27;\pm26;\pm25;\pm24;....;0\right\}\)

Tổng các số nguyên x: 

\(S2=27+\left(-26+26\right)+\left(-25+25\right)+\left(-24+24\right)+...+\left(-2+2\right)+\left(-1+1\right)+0\\ =27+0+0+0+....+0+0+0=27\)

Bài 4:

a: |x-2|=0

=>x-2=0

=>x=2

b: |x+3|=1

=>\(\left[\begin{array}{l}x+3=1\\ x+3=-1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=1-3=-2\\ x=-1-3=-4\end{array}\right.\)

c: \(-3\left|4-x\right|=-9\)

=>|4-x|=3

=>|x-4|=3

=>\(\left[\begin{array}{l}x-4=3\\ x-4=-3\end{array}\right.\Rightarrow\left[\begin{array}{l}x=7\\ x=1\end{array}\right.\)

d: |2x+1|=-2

mà -2<0<=|2x+1|

nên x∈∅

Bài 5:

a: \(\left(x+3\right)^2=36\)

=>\(\left[\begin{array}{l}x+3=6\\ x+3=-6\end{array}\right.\Rightarrow\left[\begin{array}{l}x=6-3=3\\ x=-6-3=-9\end{array}\right.\)

b: \(\left(x+5\right)^2=100\)

=>\(\left[\begin{array}{l}x+5=10\\ x+5=-10\end{array}\right.\Rightarrow\left[\begin{array}{l}x=10-5=5\\ x=-10-5=-15\end{array}\right.\)

c: \(\left(2x-4\right)^2=0\)

=>2x-4=0

=>2x=4

=>x=2

d: \(\left(x-1\right)^3=27\)

=>x-1=3

=>x=4

\(a,\Leftrightarrow x^2-2x-x^2+5x=6\\ \Leftrightarrow3x=6\\ \Leftrightarrow x=2\)

\(b,\Leftrightarrow x^2-6x+9-x+9=0\\ \Leftrightarrow x^2-7x+18=0\\ \Leftrightarrow\left(x^2-7x+\dfrac{49}{4}\right)+\dfrac{23}{4}=0\\ \Leftrightarrow\left(x-\dfrac{7}{2}\right)^2+\dfrac{23}{4}=0\left(vôlí\right)\)

b: =>12-x=-7

hay x=19

toán lớp 7 em lớp 5 

câu trả lời của em là  

\(\frac{5}{27}\)

Ta có:

      \(27^x=3^{x+2}\)

\(\Rightarrow3^{3x}=3^{x+2}\)

\(\Rightarrow3x=x+2\)

\(\Rightarrow3x-x=2\)

\(\Rightarrow2x=2\)

\(\Rightarrow x=1\)

Học Tốt!!!

Bài 2

a) x=5

b)x=1