Tìm x: biết 81x . 27 2x = (-9)4
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
7: \(\left(xy+4\right)^2-\left(2x+2y\right)^2\)
=(xy+4-2x-2y)(xy+4+2x+2y)
=[x(y-2)-2(y-2)][x(y+2)+2(y+2)]
=(x-2)(y-2)(x+2)(y+2)
8: \(81x^2-64y^2=\left(9x\right)^2-\left(8y\right)^2\)
=(9x-8y)(9x+8y)
9: \(\left(a^2+b^2+5\right)^2-4\left(ab+2\right)^2\)
\(=\left(a^2+b^2+5\right)^2-\left(2ab+4\right)^2\)
\(=\left(a^2+b^2+5-2ab-4\right)\left(a^2+b^2+5+2ab+4\right)\)
\(=\left\lbrack\left(a-b\right)^2+1\right\rbrack\left\lbrack\left(a+b\right)^2+9\right\rbrack\)
10: \(\left(x-1\right)^2-\left(x+1\right)^2\)
=(x-1-x-1)(x-1+x+1)
=2x*(-2)=-4x
11: \(8x^3-\frac18=\left(2x\right)^3-\left(\frac12\right)^3=\left(2x-\frac12\right)\left(4x^2+2x\cdot\frac12+\frac14\right)\)
\(=\left(2x-\frac12\right)\left(4x^2+x+\frac14\right)\)
12: \(\frac{1}{25}x^2-64y^2=\left(\frac15x\right)^2-\left(8y\right)^2=\left(\frac15x-8y\right)\left(\frac15x+8y\right)\)
13: \(x^3+\frac{1}{27}=x^3+\left(\frac13\right)^3=\left(x+\frac13\right)\left(x^2-\frac13x+\frac19\right)\)
a) \(x+546=46\\ x=46-546\\ x=-500\)
b) \(2x-19\times3=27\\ 2x-57=27\\ 2x=27+57\\ 2x=84\\ x=84:2\\ x=42\)
c) \(x+12=23+3\times3^4\\ x+12=23+3\times81\\ x=23+243-12\\ x=254\)
d) \(x-12=3-3\times2^4\\ x-12=3-3\times16\\ x=3-48+12\\ x=-33\)
e) \(\left(27-x\right)\left(x+9\right)=0\\ \Rightarrow\left[{}\begin{matrix}27-x=0\\x+9=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=27\\x=-9\end{matrix}\right.\)
f) \(\left(-x\right)\left(x-43\right)=0\\ \Rightarrow\left[{}\begin{matrix}-x=0\\x-43=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=43\end{matrix}\right.\)
a) x = 1; x = - 1 3 b) x = 2.
c) x = 3; x = -2. d) x = -3; x = 0; x = 2.

Đặt A = (1/81)^x nhân 27^(2x)
Đặt B = (-9)^4
(1/81)^x = (1/9^2)^x = (1/9)^2x
=> A = (1/9 nhân 27)^ 2x
= 3^(2x)
B: (-9)^4 = 9^4 = (3^2)^4 = 3^8
A=B <=> 3^(2x) = 3^8 <=> 2x = 8 <=> x = 4
tk cho tớ nha