C

1 cooking 

2 listening

3 reading

4 playing

5 cycling

1 People collect a lot of things such as stamps, milk bottle labels, comic books as well as car toys

2 She is 20 years old

3 She is a hairdresser

4 It is collecting candy shells

5 Her friends and relatives

B

1 F

2 F

3 F

4 F

5 T

Câu 27: B

Câu 28: B

Câu 29: A

Câu 30: D

Câu 31: A
Câu 32: B

\(\Leftrightarrow\left(x-100\right)\left(\dfrac{1}{10}+\dfrac{1}{12}+\dfrac{1}{14}+\dfrac{1}{16}+\dfrac{1}{17}\right)=0\)

\(\Leftrightarrow x=100\) vì \(\left(\dfrac{1}{10}+\dfrac{1}{12}+\dfrac{1}{14}+\dfrac{1}{16}+\dfrac{1}{17}\right)\ne0\)

\(\Leftrightarrow S=\left\{100\right\}\)

Bài 1:

a: \(\left(5-\frac23+\frac37\right):\left(24\frac{4}{21}-25\frac{8}{21}\right)\)

\(=\left(\frac{105}{21}-\frac{14}{21}+\frac{9}{21}\right):\left(24+\frac{4}{21}-25-\frac{8}{21}\right)\)

\(=\frac{100}{21}:\left(-1-\frac{4}{21}\right)=\frac{100}{21}:\frac{-25}{21}=\frac{100}{-25}=-4\)

b: \(\left(2\frac46-\frac{7}{15}\right):\left(\frac23-\frac25\right)^2\)

\(=\left(2+\frac23-\frac{7}{15}\right):\left(\frac{10}{15}-\frac{6}{15}\right)^2\)

\(=\left(2+\frac{10}{15}-\frac{7}{15}\right):\left(\frac{4}{15}\right)^2=\left(2+\frac{3}{15}\right):\frac{16}{225}=\frac{11}{5}\cdot\frac{225}{16}\)

\(=\frac{11}{16}\cdot45=\frac{495}{16}\)

c: \(\left(\frac{13}{18}-\frac{1}{72}\right):\frac{1}{18}-\left(\frac49-\frac{25}{16}\right)\cdot\frac92\)

\(=\left(\frac{52}{72}-\frac{1}{72}\right)\cdot18-\left(\frac{64}{144}-\frac{100}{144}\right)\cdot\frac92\)

\(=\frac{51}{72}\cdot18+\frac{36}{144}\cdot\frac92=\frac{51}{4}+\frac14\cdot\frac92=\frac{111}{8}\)

d: \(\frac35:\left(-\frac{1}{15}-\frac16\right)+\frac35:\left(-\frac13-1\frac{1}{15}\right)\)

\(=\frac35:\left(-\frac{2}{30}-\frac{5}{30}\right)+\frac35:\left(-\frac{5}{15}-\frac{16}{15}\right)\)

\(=\frac35:\frac{-7}{30}+\frac35:\frac{-21}{15}=\frac35\cdot\frac{-30}{7}+\frac35\cdot\frac{-5}{7}=\frac35\left(-\frac{30}{7}-\frac57\right)\)

\(=\frac35\cdot\left(-5\right)=-3\)

e: \(4\left(-\frac12\right)^3-2\left(-\frac12\right)^2+3\cdot\left(-\frac12\right)+\left(-1\right)^{2002}\)

\(=4\cdot\frac{-1}{8}-2\cdot\frac14-\frac32+1\)

\(=-\frac12-\frac12-\frac32+1=-\frac32\)

f: \(\frac{2^4\cdot2^6}{\left(2^5\right)^2}-\frac{2^5\cdot15^3}{6^3\cdot10^2}\)

\(=\frac{2^{10}}{2^{10}}-\frac{2^5\cdot5^3\cdot3^3}{2^3\cdot5^3\cdot2^2\cdot5^2}=1-\frac{3^3}{5^2}=1-\frac{27}{25}=-\frac{2}{25}\)

Bài 3:

a: |x-5|=8

=>\(\left[\begin{array}{l}x-5=8\\ x-5=-8\end{array}\right.\Rightarrow\left[\begin{array}{l}x=13\\ x=-5\end{array}\right.\)

b: \(\left|1-\frac23x\right|+\frac34-5\frac12=0\)

=>\(\left|\frac23x-1\right|+\frac34-\frac{11}{2}=0\)

=>\(\left|\frac23x-1\right|+\frac34-\frac{22}{4}=0\)

=>\(\left|\frac23x-1\right|=\frac{19}{4}\)

=>\(\left[\begin{array}{l}\frac23x-1=\frac{19}{4}\\ \frac23x-1=-\frac{19}{4}\end{array}\right.\Rightarrow\left[\begin{array}{l}\frac23x=\frac{19}{4}+1=\frac{23}{4}\\ \frac23x=-\frac{19}{4}+1=-\frac{15}{4}\end{array}\right.\)

=>\(\left[\begin{array}{l}x=\frac{23}{4}:\frac23=\frac{23}{4}\cdot\frac32=\frac{69}{8}\\ x=-\frac{15}{4}:\frac23=-\frac{15}{4}\cdot\frac32=\frac{-45}{8}\end{array}\right.\)

c: |9-7x|+7=26

=>|7x-9|=26-7=19

=>\(\left[\begin{array}{l}7x-9=19\\ 7x-9=-19\end{array}\right.\Rightarrow\left[\begin{array}{l}7x=19+9=28\\ 7x=-19+9=-10\end{array}\right.\Rightarrow\left[\begin{array}{l}x=4\\ x=-\frac{10}{7}\end{array}\right.\)

where do you think people will live ?

Where do you think people will live?

\(-151-\left(3x+1\right)=\left(-2\right).\left(-77\right)\)

\(-151-\left(3x+1\right)=154\)

\(3x+1=-151-154\)

\(3x+1=-305\)

\(3x=-305-1\)

\(3x=-306\)

\(x=\left(-306\right):3\)

\(x=-102\)

\(Vậy:x=-102\)

\(-151-\left(3x+1\right)=\left(-2\right)\cdot\left(-77\right)\)

=>-151-(3x+1)=154

=>3x+1=-151-154=-305

=>3x=-306

=>\(x=-\frac{306}{3}=-102\)

Bài 3: 

Ta có: a//b

nên \(x+y=180\)

mà \(2x-3y=0\)

nên \(\left\{{}\begin{matrix}x+y=180\\2x-3y=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x+2y=180\\2x-3y=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}5y=180\\x+y=180\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=36\\x=144\end{matrix}\right.\)