2 ) 3( x + 1 ) = 96 - 42

3( x + 1 ) = 54

x + 1 = 54 : 3

x + 1 = 18

x = 18 - 1

x = 17

1 ) a và b tìm : + có bao nhiu số trog dãy số đó

                      + tìm TBC

                      + nhân 2 cái lại

đó là cách của tớ .

thanks bạn nhìu :)))

sao khó dữ vậy chị

em mới có lớp 1 thôi

1: \(A=2+2^2+2^3+2^4+...+2^{97}+2^{98}+2^{99}+2^{100}\)

\(=2\left(1+2+2^2+2^3\right)+...+2^{97}\left(1+2+2^2+2^3\right)\)

\(=15\left(2+2^5+...+2^{97}\right)\)

\(=30\left(1+2^4+...+2^{96}\right)⋮30\)

2:

\(B=3+3^2+3^3+...+3^{2022}\)

\(=\left(3+3^2\right)+\left(3^3+3^4\right)+...+\left(3^{2021}+3^{2022}\right)\)

\(=\left(3+3^2\right)+3^2\left(3+3^2\right)+...+3^{2020}\left(3+3^2\right)\)

\(=12\left(1+3^2+...+3^{2020}\right)⋮12\)

s: \(=125\cdot100-25\cdot192\)

\(=12500-4800\)

=7700

a, 68 + 42 x 5 - 625 : 25

  = 68 + 210    -  25

=    278  - 25

=     253

b, 15 x { 37 + 8 + 20 } + 15 x { 13 + 22 }

  = 15 x   65               + 15 x    35

  = 15 x { 65 + 35 }

  = 15 x  100

  =  1500

c, 125 x 56 x 3

   = 7000  x 3 

   =    21000

d, 249 - { 49 - 100 }

  = 249 - 49 + 100

  = 200  + 100

  =  300

e, 1/2 + 1/4 + 1/ 8 + 1/32 + 1/64 + 1/128

   = 1/1 - 1/2 + 1/2 - 1/4 + 1/4 - 1/8 + 1/8 - 1/32 + 1/32 - 1/64 + 1/64 - 1/128

   = 1/1 - 1/128

   =   127/128

A, \(68+42\times5-625:25\)

= 68 +210 - 25

= 278 - 25

= 253

B,\(15\times\left(37+8+20\right)+15\times\left(13+22\right)\)

= \(15\times\left(37+8+20+13+22\right)\)

=\(15\times100\)

= 1500

C,\(125\times56\times3\)

= \(125\times8\times7\times3\)

=  \(1000\times21\)

= 21000

D, 249 - { 49 - 100 }

= 249 - 49 -100

= 200 - 100

= 100

E, \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}\)(mình sửa lại đề chút xíu nha, nó cứ bị sai sai sao ấy)

= \(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+\frac{1}{16}-\frac{1}{32}+\frac{1}{32}-\frac{1}{64}+\frac{1}{64}-\frac{1}{128}\) 

= \(1-\frac{1}{128}\)

=\(\frac{128}{128}-\frac{1}{128}\)

= \(\frac{127}{128}\)

a: 29+131+237+763

=160+1000

=1160

b: 65+327+15+73

=65+15+327+73

=80+400

=480

c: \(12+54:8-8\)

=12+3-8

=15-8

=7

d: \(45\cdot58+45\cdot42\)

\(=45\cdot\left(58+42\right)\)

\(=45\cdot100=4500\)

e: \(35\cdot34+35\cdot26+40\cdot35\)

\(=35\cdot\left(34+26+40\right)\)

\(=35\cdot100=3500\)

f: \(65\cdot25+65\cdot45+30\cdot65\)

\(=65\cdot\left(25+45+30\right)\)

\(=65\cdot100=6500\)

g: \(750:\left\lbrace32-\left\lbrack2^2+\left(5\cdot3^2-42\right)\right\rbrack\right\rbrace+100\)

\(=\frac{750}{32-\left\lbrack4+5\cdot9-42\right\rbrack}+100=\frac{750}{32-4-45+42}+100\)

\(=\frac{750}{28-3}+100\)

=750:25+100

=30+100

=130

h: \(\left\lbrace630:\left\lbrack16+3\cdot\left(6+3\cdot4\right)\right\rbrack\right\rbrace-1\)

\(=\frac{630}{16+3\cdot\left(6+12\right)}-1=\frac{630}{16+3\cdot18}-1\)

\(=\frac{630}{70}-1\)

=9-1=8

i: \(5871:\left\lbrack928-\left(247-82\right)\cdot5\right\rbrack+2175^0\)

\(=\frac{5871}{928-165\cdot5}+1\)

\(=\frac{5871}{928-825}+1=\frac{5871}{103}+1=57+1=58\)

k: \(375:\left\lbrace32-\left\lbrack4+\left(5\cdot3^2-42\right)\right\rbrack\right\rbrace-14\)

\(=\frac{375}{32-\left\lbrack4+5\cdot9-42\right\rbrack}-14\)

\(=\frac{375}{32-\left\lbrack4+45-42\right\rbrack}-14=\frac{375}{32-\left(4+3\right)}-14=\frac{375}{32-7}-14\)

\(=\frac{375}{25}-14\)

=15-14

=1

Ta có 1² + 2² + 3² + …10² = 385

Suy ra ( 1² +2² + 3² +…+10² ) .3² = 385.3²

Do đó ta tính được A = 3² + 6² + 9² + …+30²  = 3465

A=\(\frac{3}{4}.\frac{8}{9}.\frac{15}{16}.........\frac{899}{900}\)

A=\(\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}..........\frac{29.31}{30.30}\)

A=\(\frac{1.2.3.......29}{2.3.4.......30}.\frac{3.4.5........31}{2.3.4.......30}\)

A=\(\frac{1}{30}.\frac{2}{31}=\frac{1}{465}\)