tiểu học mà bảo toán lớp 8

bạn đã suy nghĩ chưa

2^0 x 2^9 : 8 

= 1 x 512 : 8 

= 64

nha bạn 

Bằng 64

64 nha bn

2^0.2^9:2^3

=2^9:2^3

=2^6=64

 k mik nha

a) x⁸ : x² = 16

x⁶ = 16 = ... ( chỗ này bn xem có số nào mũ 6 = 16 ko nha)

...

b) x³.x².x^-4 = 60

x^3+2-4 = 60

x^-1 = 60 = (1/60)^-1

=> x = 1/60

\(\left(5^2\times2^3-7^3\times2\right)\div2\times6-7\div2^5\)

\(=\left(25\times8-343\times2\right)\div2\times6-7\div32\)

\(=\left(200-686\right)\div2\times6-7\div32\)

\(=-486\div2\times6-7\div32\)

\(=-1458-0,21875\)

\(=-1458,21875\)

\(a=4^5.9^4-2.\dfrac{6^9}{2^{10}}.3^8+6^8.20\)

Đề là như vầy đúng ko bn?

$\textbf{A)}$

$\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}$

$=\dfrac{(2^2)^5(3^2)^4-2(2\cdot3)^9}{2^{10}\cdot3^8+2^2\cdot5(2\cdot3)^8}$

$=\dfrac{2^{10}3^8-2^{10}3^9}{2^{10}3^8+2^{10}\cdot5\cdot3^8}$

$=\dfrac{2^{10}3^8(1-3)}{2^{10}3^8(1+5)}$

$=\dfrac{-2}{6}$

$=-\dfrac{1}{3}.$

Ta có:

$H=\dfrac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}$

$=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}$

$=\dfrac{2^{12}\cdot3^{10}(1+5)}{2^{11}\cdot3^{11}(2\cdot3-1)}$

$=\dfrac{2^{12}\cdot3^{10}\cdot6}{2^{11}\cdot3^{11}\cdot5}$

$=\dfrac{2^2}{5}$

$=\dfrac45.$