7 x 17 x 125 = (8 x 125) x 17 = 1000 x 17 = 17000

4 x 37 x 25 = (25 x 4 ) x 7 = 100 x 7 = 700

43 x 27 + 93 x 43 + 57 x 81 + 69 x 57 = 43 x (27 + 93) + 57 x (81 +69) = 43 x 120 + 57 x 120 + 57x30 = 120 x (43 + 57) + 1710 = 12000 + 1710 = 13710 

Bài 10:

a: x-5=-1

=>x=-1+5

=>x=4

b: x+30=-4

=>x=-4-30

=>x=-34

c: x-(-24)=3

=>x+24=3

=>x=3-24

=>x=-21

d: 22-(-x)=12

=>22+x=12

=>x=12-22

=>x=-10

e: (x+5)+(x-9)=x+2

=>x+5+x-9=x+2

=>2x-4=x+2

=>2x-x=4+2

=>x=6

f: (27-x)+(15+x)=x-24

=>x-24=27-x+15+x=42

=>x=42+24

=>x=66

Bài 9:

a: 15-(4-x)=6

=>4-x=15-6=9

=>x=4-9=-5

b: -30+(25-x)=-1

=>-30+25-x=-1

=>-5-x=-1

=>x+5=1

=>x=1-5

=>x=-4

c: x-(12-25)=-8

=>x-(-13)=-8

=>x+13=-8

=>x=-8-13

=>x=-21

d: (x-29)-(17-38)=-9

=>x-29-(-21)=-9

=>x-29+21=-9

=>x-8=-9

=>x=-9+8

=>x=-1

Bài 8:

a: (17-229)+(17-25+229)

=17-229+17-25+229

=34-25

=9

b: (125-679+145)-(125-679)

=125-679+145-125+679

=145

/hoi-dap/question/68702.html

bn vào đây tham khảo nha

Vì :

x⋮12,25,30  ( x ∈  N )

=> x ∈  BCNN ( 12 ; 25 ; 30 )

Ta có : 12 = 3.2²

             25 = 5²

             30 = 2.3.5

=> BCNN ( 12 ; 25 ; 30 ) = 3.2².5²= 300

=> B ( 12 ; 25 ; 30 ) = { 0 ; 300 ; 600 ; 900 ....} 

Vì : 0 < x < 800

=> x = 600 .

1a) 25 .8 - 12.5 + 272 :17 - 8

= 200 -  60 + 16 - 8

= 140+16-8

= 156 - 8

= 148

b) 125: 25 +14 - 142 : 71

= 5 + 14 - 2 

= 19 - 2 = 17

c) 13. 17 - 256: 16 + 14 : 7 - 1

= 221 - 16 + 2 - 1 

= 205 + 2 - 1 

= 207 - 1 = 206

d) 15 . 24 - 14 . 5 (145 : 5 - 27)

= 360 - 70 (29- 27)

= 360 - 70 . 2

= 360 - 140

= 220

2a) 37 + x = 55

               x= 55 - 37

               x = 18

b) x- 31 = 24

     x       = 24 + 31

     x        = 55

c) 21 (x-11) = 21

        x - 11   = 21 : 21

          x        = 1 +11

           x       = 12

d ) 9. (x - 29)= 0

           x - 29 = 0 :9

             x       = 29

e) (x - 1954) . 5 = 50

         x - 1954   = 50 : 5

          x             = 1964

f ) 30 . 60 - x = 30

        1800 - x   = 30

             x        = 1800 - 30

             x        = 1770

Viết mỏi tay quá huhuh

Cảm ơn nghen

Đáp án C

 1) 9-25=(7-x)-(25+7)

(7-x)-(25+7)=9-25

(7-x)-(25+7)=-16

(7-x)-32=-16

7-x=-16+32

7-x=16

x=7-16

x=-9

2) (27-514) -(486-73)+x=7

 (27-514) -(486-73)+x=7

-487-413+x=7

-1011+x=7

x=7-(-1011)

x=7+1011

x=1018

3) 25+5+37-25+6-29-x=37

 25+5+37-25+6-29-x=37

67-25+6-29-x=37

42+6-29-x=37

48-29-x=37

19-x=37

x=19-37

x=-18

4) 14+(-12)+x =10-/-15/+ /-3/

14+(-12)+x =10-15+3

14+(-12)+x =-5+3

14+(-12)+x =-2

2+x=-2

x=-2-2

x=-4

1) - 9

2) 1018 

3) -18 

4) -4

tick nha

Giải

Bài 1

\(1,a,-40-37-\left(-29\right)\\ =-40-37+29\\ =-77+29=-48\\ b,27+\left(-36\right)-\left(-45\right)=27-36+45\\ =-9+45\\ =36\\ c,-125-\left[\left(-18\right)-125\right]\\ =-125+18+125\\ =\left(-125+125\right)+18\\ =18\\ d,140+\left[\left(-184\right)-140\right]\\ =140-184-140\\ =\left(140-140\right)-184\\ =0-184\\ =-184\)

Bài 2 

\(a,x-\left(-15\right)=-8\\ =>x+15=-8\\ =>x=-8-15\\ =>x=-23\\ b,-40-x=-35\\ =>x=\left(-40\right)-\left(-35\right)\\ =>x=-40+35\\ =>x=-5\\ c,x+\left(-50\right)=-27\\ =>x-50=-27\\ =>x=-27+50\\ =>x=23\)

1, Thực hiện phép tính:

\(a,-40+\left(-37\right)-\left(-29\right)=-77-\left(-29\right)=-48\)

\(b,27+\left(-36\right)-\left(-45\right)=-9-\left(-45\right)=36\)

\(c,-125-\left[\left(-18\right)-125\right]=-125-\left(-143\right)=18\)

\(d,140+\left[\left(-184\right)-140\right]=140+\left(-324\right)=-184\)

2, Tìm x biết:

\(a,x-\left(-15\right)=-8\)

\(x=-8+\left(-15\right)\)

\(x=-23\)

\(b,-40-x=-35\)

\(x=-40-\left(-35\right)\)

\(x=-5\)

\(c,x+\left(-50\right)=-27\)

\(x=-27-\left(-50\right)\)

\(x=23\)

\(\dfrac{37\cdot5^4}{25^2}=\dfrac{37\cdot5^4}{5^4}=37\\ \dfrac{2^4\cdot2^6\cdot3^8\cdot9^2}{4^4\cdot3^{11}}=\dfrac{2^{10}\cdot3^8\cdot3^4}{2^8\cdot3^{11}}=2^2\cdot3=12\\ \dfrac{3\cdot9^4\cdot9^3}{3^2\cdot9}=\dfrac{3\cdot3^8\cdot3^6}{3^2\cdot3^2}=3^{11}\\ \dfrac{125\cdot5\cdot64-25^3\cdot10\cdot4}{5^7\cdot8}=\dfrac{5^3\cdot5\cdot2^6-5^6\cdot2\cdot5\cdot2^2}{5^7\cdot2^3}=\dfrac{5^4\cdot2^3\left(2^3-5^3\right)}{5^7\cdot2^3}=\dfrac{8-125}{5^3}=\dfrac{-117}{125}\)

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