11/19 < 13/18

\(\frac{19}{18}\)> \(\frac{18}{17}\)

k mk nha!

\(\frac{19}{18}< \frac{18}{17}\)

-Ta có \(\frac{19}{18}=1+\frac{1}{18}\)
\(\frac{18}{17}=1+\frac{1}{17}\)
Vì \(\frac{1}{18}< \frac{1}{17}\)(=) \(1+\frac{1}{18}< 1+\frac{1}{17}\)(=) \(\frac{19}{18}< \frac{18}{17}\)

ta có \(\frac{19}{18}-1=\frac{1}{18},\frac{18}{17}-1=\frac{1}{17}.\)

\(\frac{1}{18}< \frac{1}{17}\)

=>\(\frac{19}{18}< \frac{18}{17}\)

xong r đó

a: \(\frac{23}{35}<\frac{23,1}{35}=0,66\)

\(0,66=\frac{20,46}{31}<\frac{21}{31}\)

Do đó: \(\frac{23}{35}<\frac{21}{31}\)

b: \(\frac{-17}{24}<\frac{-16}{24}=\frac{-2}{3}\)

\(\frac{-2}{3}=\frac{-13}{19,5}<\frac{-13}{28}\)

Do đó: \(-\frac{17}{24}<-\frac{13}{28}\)

c: \(\frac{9}{16}>\frac{8}{16}=\frac12;\frac12=\frac{12}{24}>\frac{11}{24}\)

Do đó: \(\frac{9}{16}>\frac{11}{24}\)

_{Làm ơn giúp mình với !}

1. 12/18 < 13/17
2. 16/51 < 31/90

3/9<4/10

11/29<13/18

ta thay : 19/18 - 1 = 1/18            ; 18/17 - 1 = 1 /17

ta co : 1/17 >1/18 nen 19/18 > 18/17

day la phuong phap phan hon, ban co the su dung phuong phap phan so trung gian de giai

Ta thấy : 19/18 - 1 = 1/18 

18/17 - 1 = 1/17 

Ta có : 1/18 < 1/17 nên 19/18 > 18/17

a) \(1-\frac{13}{17}=\frac{4}{17}\) và \(1-\frac{15}{19}=\frac{4}{19}\)

Vì 4/17 > 4/19 nên 13/17 < 15/19      

b) \(\frac{12}{48}=\frac{1}{4}\) và \(\frac{9}{36}=\frac{1}{4}\)

Vậy 12/48 = 9/36

13/17<15/19

12/48=9/36

**** tớ nhha

Cách 1: \(\frac37=\frac{3\times3}{7\times3}=\frac{9}{21}\)

mà \(\frac{9}{21}<\frac{9}{13}\left(21>13\right)\)

nên \(\frac37<\frac{9}{13}\)

Cách 2:

Ta có: \(\frac37<\frac{3.5}{7}=\frac12\)

\(\frac12=\frac{9}{18}<\frac{9}{13}\)

Do đó: \(\frac37<\frac{9}{13}\)