Ta có: \(\dfrac{6^5\cdot\left(-12\right)^6}{\left(-4\right)^9\cdot\left(-3\right)^{10}}\)

\(=-\dfrac{3^5\cdot2^5\cdot12^6}{4^9\cdot3^{10}}\)

\(=-\dfrac{2^5\cdot3^6\cdot4^6}{4^9\cdot3^5}\)

\(=-\dfrac{2^5\cdot3}{4^3}\)

\(=-\dfrac{2^5}{2^6}\cdot3=-\dfrac{3}{2}\)

 ta được  \(\dfrac{6^5.12^6}{4^8.\left(-4\right).3^{10}}\) \(=\dfrac{2^5.3^5.2^{12}.3^6}{2^{16}.\left(-4\right).3^{10}}\) \(=\dfrac{2^{17}.3^{11}}{2^{16}.\left(-4\right).3^{10}}=\dfrac{-6}{4}=\dfrac{-3}{2}\)

816 nha bạn

12 x 34 + 12 x 11 + 12 x 23 = 12 x ( 34 + 11 + 23 )

                                         = 12 x 68

                                         = 816

Tổng A có số số hạng là: (2019-1):2+1= 1010 số

Tổng A là: 1010.(2019+1):2=1020100

:))

số số hạng dãy trên là 

\(\left(2019-1\right):2+1=1010\)

tổng dãy trên là 

\(\left(2019+1\right).1010:2=1020100\)

vậy \(A=1+3+5+7+9+...+2017+2019=1020100\)

\(4-\frac{5}{12}\times\frac{9}{10}\)

\(=4-\frac{1}{2}\)

\(=\frac{7}{2}\)

~HT~

\(4-\frac{5}{12}\times\frac{9}{10}\rightarrow4-\frac{3}{8}\rightarrow\frac{32}{8}-\frac{2}{8}=\frac{30}{8}=\frac{15}{4}\)

Đề yêu cầu gì vậy em?

đây là so sánh hay quy đồng v 

\(\dfrac{3}{5}v\text{à}\dfrac{7}{3}\\ MSC:15\\ \dfrac{3}{5}=\dfrac{3\times3}{5\times3}=\dfrac{9}{15};\dfrac{7}{3}=\dfrac{7\times5}{5\times3}=\dfrac{35}{15}\\ 9< 35\\ \Rightarrow\dfrac{3}{5}< \dfrac{7}{5}\\ \dfrac{9}{10}v\text{à}\dfrac{5}{4}\\MSC:20\\ \dfrac{9\times2}{10\times2}=\dfrac{18}{20};\dfrac{5}{4}=\dfrac{5\times5}{4\times5}=\dfrac{25}{20}\\ 18< 25\\ \Rightarrow\dfrac{9}{10}< \dfrac{5}{4}\\ \dfrac{2}{7}v\text{à}\dfrac{5}{4}\\ MSC:28\\ \dfrac{2}{7}=\dfrac{2\times4}{7\times4}=\dfrac{8}{28};\dfrac{5}{4}=\dfrac{5\times7}{4\times7}=\dfrac{35}{28}\\ 8< 35\\ \dfrac{2}{7}< \dfrac{5}{4}\\ \dfrac{8}{9}v\text{à}\dfrac{11}{6}\\ MSC:18\\ \dfrac{8\times2}{9\times2}=\dfrac{16}{18};\dfrac{11}{6}=\dfrac{11\times3}{6\times3}=\dfrac{33}{18}\\ 16< 33\\ \Rightarrow\dfrac{8}{9}< \dfrac{11}{6}\)

\(\dfrac{4^6\cdot9^5+6^9\cdot120}{-8^4\cdot3^{12}-6^{11}}\)

\(=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}\)

\(=\dfrac{2^{12}\cdot3^{10}\cdot\left(1+5\right)}{2^{11}\cdot3^{11}\left(2\cdot3-1\right)}\)

\(=\dfrac{2\cdot6}{3\cdot5}=\dfrac{4}{5}\)

Bài `4`

`1, 2y(x+2)-3x-6`

`=2y(x+2) -(3x+6)`

`=2y(x+2) -3(x+2)`

`=(x+2)(2y-3)`

`2, 3(x+4) -x^2-4x`

`=3(x+4)-(x^2+4x)`

`=3(x+4) -x(x+4)`

`=(x+3)(3-x)`

`3, 2(x+5) -x^2-5x`

`=2(x+5)-(x^2+5x)`

`=2(x+5)-x(x+5)`

`=(x+5)(2-x)`

`4, x^2 +6x-3(x+6)`

`= (x^2+6x) -3(x+6)`

`=x(x+6)-3(x+6)`

`=(x+6)(x-3)`

`5, x(x+y) -5x-5y`

`=x(x+y) -(5x+5y)`

`=x(x+y)-5(x+y)`

`=(x+y)(x-5)`

`6,x(x-y)+2x-2y`

`=x(x-y)+2(x-y)`

`=(x-y)(x+2`

Bạn tách ra từng bài đi ạ. Làm all trong 1 câu nhiều lắm.