mn giúp em vớii😢
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
ex 4.
1 seeing
2 to pay
3 sneezing
4 to clean up
5 to work
6 cutting
7 to iron - ironing
8 driving
9 to have
10 to invite
11 being
12 to find
13 holding - drinking
14 to repair
15 explaining
ex 5.
2. Pamela continued dancing for an hour.
3. I'd rather sit in the front row.
4. Richard expects to do well.
5. What do you intend to do for the summer?
6. I hate clearing up my room.
7. Helen agreed to go to the party with me.
8. My boss refused to let me leave early.
9. I really look forward to hearing from you soon.
10. What do you want to do this evening?
11. The manager promised to speak to you about this.
12. Fiona succeeded in persuading her father to change his mind.
13. Where do you feel like going this evening?
14. The detective happened to discover the secret.
15. It was very late, but she went on tidying up the kitchen.
ex6.
1. The room will be cleaned today.
2. The car might be stolen.
3. That tree had to be cut down.
4. The old houses are going to be demolished.
5. The picture can't be restored.
6. An appointment must be made in advance.
7. I don't want to be made a fool.
8. The garden has to be looked after.
9. He wants to be served.
10. He is going to be interviewed next week.
Bài 8:
a: QUa O, kẻ tia OM nằm giữa hai tia OB và OC sao cho OM//Bx
OM//Bx
=>\(\hat{xBO}+\hat{BOM}=180^0\) (hai góc trong cùng phía)
=>\(\hat{BOM}=180^0-170^0=10^0\)
Ta có: tia OM nằm giữa hai tia OB và OC
=>\(\hat{BOM}+\hat{COM}=\hat{BOC}\)
=>\(\hat{COM}=80^0-10^0=70^0\)
Ta có: \(\hat{COM}+\hat{OCy}=70^0+110^0=180^0\)
mà hai góc này là hai góc ở vị trí trong cùng phía
nên OM//Cy
Ta có: OM//Bx
OM//Cy
Do đó: Bx//Cy
b: Qua K, kẻ tia KC nằm giữa hai tia KM và KN sao cho KC//Mn
KC//Mn
=>\(\hat{MKC}=\hat{KMn}\) (hai góc so le trong)
=>\(\hat{MKC}=50^0\)
Ta có: tia KC nằm giữa hai tia KM và KN
=>\(\hat{MKC}+\hat{NKC}=\hat{MKN}\)
=>\(\hat{NKC}=80^0-50^0=30^0\)
Gọi tia đối của tia Nm là tia Na
Ta có: \(\hat{NKC}+\hat{KNa}=180^0\)
mà hai góc này là hai góc ở vị trí trong cùng phía
nên KC//Nm
Ta có: KC//Mn
KC//Nm
Do đó: Mn//Nm
c: Qua M, kẻ tia MA nằm giữa hai tia MD và MT sao cho MA//Dm
Gọi Dx tia đối của tia Dm
MA//Dx
=>\(\hat{DMA}+\hat{MDx}=180^0\) (hai góc trong cùng phía)
=>\(\hat{DMA}=180^0-160^0=20^0\)
Ta có: tia MA nằm giữa hai tia MD và MT
=>\(\hat{DMA}+\hat{TMA}=\hat{DMT}\)
=>\(\hat{TMA}=100^0-20^0=80^0\)
Ta có: \(\hat{TMA}=\hat{MTy}\left(=80^0\right)\)
mà hai góc này là hai góc ở vị trí so le trong
nên MA//Cy
Ta có: MA//Cy
MA//Dm
Do đó: Dm//Cy
d: Qua K, kẻ tia KA nằm giữa hai tia KH và KN sao cho KA//Hv
KA//Hv
=>\(\hat{HKA}+\hat{H}=180^0\) (hai góc trong cùng phía)
=>\(\hat{HKA}=180^0-150^0=30^0\)
Ta có: tia KA nằm giữa hai tia KH và KN
=>\(\hat{HKA}+\hat{NKA}=\hat{HKN}\)
=>\(\hat{NKA}=110^0-30^0=80^0\)
Ta có: \(\hat{NKA}=\hat{N}\left(=80^0\right)\)
mà hai góc này là hai góc ở vị trí so le trong
nên KA//Nm
mà KA//Hv
nên Hv//Nm
a: Ta có: NA=2NC
=>\(S_{PNA}=2\times S_{PNC};S_{MNA}=2\times S_{MNC}\)
=>\(S_{PNA}-S_{MNA}=2\times\left(S_{PNC}-S_{MNC}\right)\)
=>\(S_{PMA}=2\times S_{PMC}\)
Ta có: MB=1/3MC
=>\(S_{PMB}=\frac13\times S_{PMC}\)
=>\(\frac{S_{PBM}}{S_{PAM}}=\frac13:2=\frac16\)
=>\(\frac{PB}{PA}=\frac16\)
=>\(\frac{PB}{BA}=\frac15\)
=>\(\frac{PB}{15}=\frac15\)
=>BP=3(cm)
AP=AB+BP
=3+15=18(cm)
b:
BM+MC=BC
=>BC=3MB+MB=4BM
=>\(BM=\frac14\times BC\)
=>\(S_{ABM}=\frac14\times S_{ABC}\)
Vì \(\frac{BP}{BA}=\frac{3}{15}=\frac15\)
nên \(S_{PBM}=\frac15\times S_{BAM}=\frac15\times\frac14\times S_{ABC}=\frac{1}{20}\times S_{ABC}\)
\(S_{PMA}=S_{ABM}+S_{PBM}=\frac14\times S_{ABC}+\frac{1}{20}\times S_{ABC}=\frac{3}{10}\times S_{ABC}\)
Vì \(\frac{CM}{CB}=\frac34\)
nên \(S_{AMC}=\frac34\times S_{ABC}\)
Ta có: AN+NC=AC
=>AC=2NC+NC=3NC
=>\(AN=\frac23AC\)
=>\(S_{AMN}=\frac23\times S_{AMC}=\frac23\times\frac34\times S_{ABC}=\frac12\times S_{ABC}\)
=>\(\frac{S_{AMP}}{S_{AMN}}=\frac{3}{10}:\frac12=\frac{3}{10}\times2=\frac35\)
=>\(\frac{MP}{MN}=\frac35\)










Câu 1: C