bằng 1

Ta có:

$A=\dfrac{1+(1+2)+(1+2+3)+\cdots+(1+2+\cdots+98)}{1\times98+2\times97+3\times96+\cdots+98\times1}$

Tử số:

$1+(1+2)+(1+2+3)+\cdots+(1+2+\cdots+98)$

$=1+2+2^2+?$

Cách dễ nhất là viết:

$1+2+\cdots+k=\dfrac{k(k+1)}2$

Nên tử số:

$=\dfrac{1\cdot2}{2}+\dfrac{2\cdot3}{2}+\cdots+\dfrac{98\cdot99}{2}$

$=\dfrac{1}{2}(1\cdot2+2\cdot3+\cdots+98\cdot99)$

$=\dfrac{1}{2}\cdot\dfrac{98\cdot99\cdot100}{3}$

$=161700$

Mẫu số:

$1\cdot98+2\cdot97+3\cdot96+\cdots+98\cdot1$

$=1(99-1)+2(99-2)+\cdots+98(99-98)$

$=99(1+2+\cdots+98)-(1^2+2^2+\cdots+98^2)$

$=99\cdot\dfrac{98\cdot99}{2}-\dfrac{98\cdot99\cdot197}{6}$

$=161700$

Do đó:

$A=\dfrac{161700}{161700}=1$

Vậy $A=1$.

Ta có: \(\left\lbrace\left\lbrack\left(x^3-17\right)^2-98\right\rbrack^3-6\right\rbrace^5=32\)

=>\(\left\lbrack\left(x^3-17\right)^2-98\right\rbrack^3-6=2\)

=>\(\left\lbrack\left(x^3-17\right)^2-98\right\rbrack^3=2+6=8=2^3\)

=>\(\left(x^3-17\right)^2-98=2\)

=>\(\left(x^3-17\right)^2=100\)

=>\(\left[\begin{array}{l}x^3-17=10\\ x^3-17=-10\end{array}\right.\Rightarrow\left[\begin{array}{l}x^3=27\\ x^3=7\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3\left(nhận\right)\\ x=\sqrt[3]{7}\left(loại\right)\end{array}\right.\)

số cần tìm là :

73/ 98 - 1/6 = 85/147

Đ / S : ...... 

Nhớ K mik nha

tại sao bạn ra được là 85/147

Trẻ trâu hỏi cái loz

Con mẹ mày à

♪ chia ra thôi ♪...đợi...a chia ko hết à?

= \(\dfrac{760284}{89}\)

= \(\dfrac{4578}{5}\)

= 1234

a: \(\frac{52}{17}>\frac{51}{17}=3\)

\(3=\frac{121}{41}>\frac{120}{41}\)

Do đó: \(\frac{52}{17}>\frac{120}{41}\)

b: \(\frac34+\frac14:\left(\frac{7}{12}-\frac16\right)\)

\(=\frac34+\frac14:\left(\frac{7}{12}-\frac{2}{12}\right)\)

\(=\frac34+\frac14:\frac{5}{12}\)

\(=\frac34+\frac14\times\frac{12}{5}=\frac34+\frac35=\frac{15}{20}+\frac{12}{20}=\frac{27}{20}\)

c: \(372,463\cdot998+744,926\)

\(=372,463\cdot998+372,463\cdot2\)

\(=372,463\times\left(998+2\right)=372,463\times1000=372463\)

d: Số số hạng trong dãy số 2;4;6;...;100 là:

\(\left(100-2\right):2+1=98:2+1=49+1=50\) (số)

\(2-4+6-8+10-12+\cdots+98-100+102\)

\(=\left(2-4\right)+\left(6-8\right)+\cdots+\left(98-100\right)+102\)

=(-2)+(-2)+...+(-2)+102

\(=-2\cdot\frac{50}{2}+102=-50+102=52\)

e: (y+112)-113=79

=>y+112-113=79

=>y-1=79

=>y=79+1=80

f: \(\frac34-y=\frac12\)

=>\(y=\frac34-\frac12=\frac14\)

g: \(\left(\frac45-2\times y\right)+\frac16=\frac56\)

=>\(\frac45-2\times y=\frac56-\frac16=\frac46=\frac23\)

=>\(2\times y=\frac45-\frac23=\frac{12}{15}-\frac{10}{15}=\frac{2}{15}\)

=>\(y=\frac{2}{15}:2=\frac{1}{15}\)

h: (y+1)+(y+2)+...+(y+50)=1750

=>50y+(1+2+...+50)=1750

=>\(50y+50\times\frac{51}{2}=1750\)

=>50y+1275=1750

=>50y=1750-1275=475

=>\(y=\frac{475}{50}=9,5\)