\(\dfrac{1}{6}+\dfrac{1}{12}\)

Bài toán khó

Bài 2:

\(\frac{13}{36}=\frac{1+5+7}{36}=\frac{1}{36}+\frac{5}{36}+\frac{7}{36}\)

\(\frac{31}{60}=\frac{1+23+7}{60}=\frac{1}{60}+\frac{23}{60}+\frac{7}{60}\)

Bài 1:

\(\frac{25}{27}=\frac{1+3+9+3+9}{27}=\frac{1}{27}+\frac19+\frac13+\frac19+\frac13\)

\(\frac{15}{16}=\frac{8+7}{16}=\frac12+\frac{7}{16}=\frac12+\frac{4+3}{16}=\frac12+\frac14+\frac{3}{16}\)

\(=\frac12+\frac14+\frac{2+1}{16}=\frac12+\frac14+\frac18+\frac{1}{16}\)

\(\frac{11}{36}=\frac{1}{6}+\frac{1}{9}+\frac{1}{36}\)

Ta có:
11/36 = (1 + 4 + 6)/36
            = 1/36+  4/36 + 6/36
            = 1/36 + 1/9 + 1/6

(._.)

Đáp án :

= \(\frac{1}{36}+\frac{1}{9}+\frac{1}{6}\)

# Hok tốt !

\(\frac14\) = \(\frac15+\frac{1}{20}\)

\(\frac14=\frac{1}{12}+\frac16\)

\(\dfrac{13}{35}=\dfrac{1}{7}+\dfrac{1}{5}+\dfrac{1}{35}\)

\(\dfrac{13}{35}=\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{35}\)

\(\frac{13}{36}=\frac{1+3+9}{36}=\frac{1}{36}+\frac{1}{12}+\frac{1}{4}\)\(\frac{13}{36}=\frac{1+3+9}{36}=\frac{1}{36}+\frac{1}{12}+\frac{1}{4}\)

13/36 = 1/9 + 1/4

\(\frac{13}{16}=\frac{1}{2}+\frac{1}{4}+\frac{1}{16}\)