Ta có: \(\frac{-2^{10}\cdot3^{10}\cdot6^9}{4^3\cdot\left(-16\right)^{19}}\)

\(=\frac{-2^{10}\cdot3^{10}\cdot2^9\cdot3^9}{2^6\cdot\left(-1\right)\cdot16^{19}}=\frac{2^{19}\cdot3^{19}}{2^6\cdot\left(2^4\right)^{19}}\)

\(=\frac{2^{13}\cdot3^{19}}{2^{76}}=\frac{3^{19}}{2^{63}}\)

xin lỗi các bạn mình ko bết viết phân số nên viết thế này mọi người thông cảm và giải hộ mình nhé! CẢM ƠN MỌI NGƯỜI

\(\frac{4^5.9^4-10.6^9}{2^{10}.3^8+6^8.28}\)

\(=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.5.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.7}\)

\(=\frac{2^{10}.3^8-2^{10}.3^9.5}{2^{10}.3^8+2^{10}.3^8.7}\)

\(=\frac{2^{10}.3^8\left(1-3.5\right)}{2^{10}.3^8\left(1+7\right)}=\frac{-14}{8}=-\frac{7}{4}\)

Vậy : \(\frac{4^5.9^4-10.6^9}{2^{10}.3^8+6^8.28}=-\frac{7}{4}\)

Ta có: \(5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9\)

\(=5\cdot2^{30}\cdot3^{18}-2^2\cdot3^{20}\cdot2^{27}\)

\(=5\cdot2^{30}\cdot3^{18}-2^{29}\cdot3^{20}\)

\(=2^{29}\cdot3^{18}\left(5\cdot2-3^2\right)=2^{29}\cdot3^{18}\)

Ta có: \(5\cdot2^{10}\cdot6^{19}-7\cdot2^{29}\cdot27^6\)

\(=5\cdot2^{10}\cdot2^{19}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}\)

\(=5\cdot2^{29}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}\)

\(=2^{29}\cdot3^{18}\left(5\cdot3-7\right)=2^{32}\cdot3^{18}\)

Ta có: \(\frac{5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9}{5\cdot2^{10}\cdot6^{19}-7\cdot2^{29}\cdot27^6}\)

\(=\frac{2^{29}\cdot3^{18}}{2^{32}\cdot3^{18}}=\frac{1}{2^3}=\frac18\)

\(\frac{4^9.9^4-10.6^9}{2^{10}.3^8+6^8-28}=\frac{2^{18}.3^8-2.5.2^9.3^9}{2^{10}.3^8+2^8.6^8-2^2.7}\)

Nhóm các tích trên tử và mẫu sao cho bằng nhau rồi tính.

=0 

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