-2^10.3^10.6^9/4^3.(-16)^19
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Ta có: \(\frac{-2^{10}\cdot3^{10}\cdot6^9}{4^3\cdot\left(-16\right)^{19}}\)
\(=\frac{-2^{10}\cdot3^{10}\cdot2^9\cdot3^9}{2^6\cdot\left(-1\right)\cdot16^{19}}=\frac{2^{19}\cdot3^{19}}{2^6\cdot\left(2^4\right)^{19}}\)
\(=\frac{2^{13}\cdot3^{19}}{2^{76}}=\frac{3^{19}}{2^{63}}\)
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\(\frac{4^5.9^4-10.6^9}{2^{10}.3^8+6^8.28}\)
\(=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.5.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.7}\)
\(=\frac{2^{10}.3^8-2^{10}.3^9.5}{2^{10}.3^8+2^{10}.3^8.7}\)
\(=\frac{2^{10}.3^8\left(1-3.5\right)}{2^{10}.3^8\left(1+7\right)}=\frac{-14}{8}=-\frac{7}{4}\)
Vậy : \(\frac{4^5.9^4-10.6^9}{2^{10}.3^8+6^8.28}=-\frac{7}{4}\)
Ta có: \(5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9\)
\(=5\cdot2^{30}\cdot3^{18}-2^2\cdot3^{20}\cdot2^{27}\)
\(=5\cdot2^{30}\cdot3^{18}-2^{29}\cdot3^{20}\)
\(=2^{29}\cdot3^{18}\left(5\cdot2-3^2\right)=2^{29}\cdot3^{18}\)
Ta có: \(5\cdot2^{10}\cdot6^{19}-7\cdot2^{29}\cdot27^6\)
\(=5\cdot2^{10}\cdot2^{19}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}\)
\(=5\cdot2^{29}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}\)
\(=2^{29}\cdot3^{18}\left(5\cdot3-7\right)=2^{32}\cdot3^{18}\)
Ta có: \(\frac{5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9}{5\cdot2^{10}\cdot6^{19}-7\cdot2^{29}\cdot27^6}\)
\(=\frac{2^{29}\cdot3^{18}}{2^{32}\cdot3^{18}}=\frac{1}{2^3}=\frac18\)
Trả lời:
\(10+11+12+13+14+15+16+17+18+19+20\)
\(=\left(10+20\right)+\left(11+19\right)+\left(12+18\right)+\left(13+17\right)+\left(14+16\right)+15\)
\(=30+30+30+30+30+15\)
\(=165\)
\(1+2+3+4+5+6+7+8+9\)
\(=\left(1+9\right)+\left(2+8\right)+\left(3+7\right)+\left(4+6\right)+5\)
\(=10+10+10+10+5\)
\(=45\)
10+11+12+13+14+15+16+17+18+19+20
(10+20)+(11+19)+(12+18)+(13+17)+(14+16)+15
30+30+30+30+30+15
165
Ta có: \(\frac{-2^{10}\cdot3^{10}\cdot6^9}{4^3\cdot\left(-16\right)^{19}}\)
\(=\frac{-2^{10}\cdot3^{10}\cdot2^9\cdot3^9}{2^6\cdot\left(-1\right)\cdot16^{19}}=\frac{2^{19}\cdot3^{19}}{2^6\cdot\left(2^4\right)^{19}}\)
\(=\frac{2^{13}\cdot3^{19}}{2^{76}}=\frac{3^{19}}{2^{63}}\)