(19x+13^2):5=49
(x+7)^2=121
(-35).(x+39)=-210
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a) 34/29x13/17-10/27=26/29-10/27=412/783
b) 2+4/7:2/5=2+10/7=24/7
c) 968x49+35460:985=47432+36=47468
2/3 + 3/4=17/12
9/4 + 3/5=57/20
5/24 + 1/4=11/24
3/15 - 5/35=2/35 18/27 - 2/6=1/3 37/12 - 3=1/12
11/9 x 3/22=1/6 7/13 x 13/7=1 4 x6/7=24/7
2/5 : 3/10=4/3 3/8 : 9/4=1/6 8/21 : 4/7=2/3
\(a,\Rightarrow12x-91=101\\ \Rightarrow12x=192\\ \Rightarrow x=16\\ b,\Rightarrow x:23+45=133\\ \Rightarrow x:23=88\\ \Rightarrow x=\dfrac{88}{23}\\ c,\Rightarrow\left(6x-39\right):7=3\\ \Rightarrow6x-39=21\\ \Rightarrow6x=60\\ \Rightarrow x=10\\ d,\Rightarrow3x-24=\dfrac{148}{73}\\ \Rightarrow3x=\dfrac{1900}{73}\\ \Rightarrow x=\dfrac{1900}{219}\\ e,\Rightarrow\left[{}\begin{matrix}x=0\\x=10\end{matrix}\right.\\ f,\Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\\ d,\left(9-x\right)^3=64=4^3\\ \Rightarrow9-x=4\\ \Rightarrow x=5\\ h,\Rightarrow x=27\\ i,\Rightarrow6x=312\cdot12=624\cdot6\\ \Rightarrow x=624\\ j,\Rightarrow\left(19x+104\right):14=25-42=-17\\ \Rightarrow19x+104=-238\\ \Rightarrow19x=-342\\ \Rightarrow x=-18\)
1: =-2/9(15/17+2/17)=-2/9
2: \(=\dfrac{-6}{3}+\dfrac{-21}{90}\)
=-2-7/30=-67/30
3: \(=\dfrac{3}{4}\cdot\dfrac{7}{5}+\dfrac{9}{7}\cdot\dfrac{3}{2}\)
=21/20+27/14=417/140
4: =-25/13(5/19+14/19)=-25/13
5: =-7/5-45/21=-7/5-15/7=-124/35
1: =-2/9(15/17+2/17)=-2/9
2: =−63+−2190=−63+−2190
=-2-7/30=-67/30
3: =34⋅75+97⋅32=34⋅75+97⋅32
=21/20+27/14=417/140
4: =-25/13(5/19+14/19)=-25/13
5: =-7/5-45/21=-7/5-15/7=-124/35
a) `123 - 27 + 27 + 13 - 123`
`= (123 - 123) + (27 - 27) + 13`
`= 0 + 0 + 13`
`= 13`
`---`
b) `175 + 25 + 13 + 15 - 175 - 25`
`= (175-175)+(25-25)+25+13`
`=0+0+25+13`
`=28`
`---`
c) \(53\times39+47\times39+53\times21+47\times21\)
\(=\text{[}\left(53+47\right)\times39]+\left[\left(53+47\right)\times21\right]\)
\(=\left(100\times39\right)+\left(100\times21\right)\)
\(=3900+2100\)
`=6000`
`---`
d) \(49\times35+49\times16-49\times61\)
`=` \(49\times\left(35+16-61\right)\)
`=` \(49\times\left(-10\right)\)
`=-490`
\(\dfrac{2}{49}\) x 121 : \(\dfrac{22}{7}\)
= \(\dfrac{2}{49}\) x 121 x \(\dfrac{7}{22}\)
= \(\dfrac{2}{7\times7}\) \(\times\)\(\dfrac{11\times11\times7}{11\times2}\)
= \(\dfrac{11}{7}\)
a: \(\frac{4^5\cdot10\cdot5^6+25^5\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)
\(=\frac{2^{10}\cdot2\cdot5\cdot5^6+5^{10}\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}=\frac{2^8\cdot5^7\left(2^3+3^3\right)}{2^5\cdot5^4\left(2^3+3^3\right)}\)
\(=2^3\cdot5^3=10^3=1000\)
b: \(149-\left(35:x+3\right)\cdot17=13\)
=>\(\left(35:x+3\right)\cdot17=149-13=136\)
=>35:x+3=136:17=8
=>35:x=8-3=5
=>\(x=\frac{35}{5}=7\)
c: \(121:11-\left(4x+5:3\right)=4\)
=>11-(4x+5/3)=4
=>4x+5/3=11-4=7
=>\(4x=7-\frac53=\frac{21}{3}-\frac53=\frac{16}{3}\)
=>\(x=\frac{16}{3}:4=\frac43\)
d: \(720:\left\lbrack41-\left(2x-5\right)\right\rbrack=40\)
=>\(41-\left(2x-5\right)=\frac{720}{40}=18\)
=>2x-5=41-18=23
=>2x=28
=>\(x=\frac{28}{2}=14\)
e: Sửa đề: (x+1)+(x+2)+(x+3)+...+(x+100)=5700
=>100x+(1+2+3+...+100)=5700
=>\(100x+100\cdot\frac{101}{2}=5700\)
=>x+50,5=57
=>x=57-50,5
=>x=6,5
b: \(\Leftrightarrow\left[{}\begin{matrix}x+7=11\\x+7=-11\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-18\end{matrix}\right.\)
\(\left(19x+13^2\right):5=49\\ \left(19x+169\right):5=49\\ 19x+169=49.5\\ 19x+169=245\\ 19x=245-169\\ 19x=76\\ x=76:19\\ x=4\)