y*[26+327]=327*7+26*7
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36 x 532 + 64 x 532
=(36+64)x532
= 100x532
=53 200
245 x 327 - 245 x 26 - 245
=245x327-245x26-245x1
=245x(327-26-1)
=245x300
=73 500
(x+1/5)^2 =26/25-17/25
<=> (x +1/5)^2 =(3/5)^2
<=> x+1/5=3/5
=> x= 2/5
1.
(x + 1/5)² = 26/25 - 17/25
(x + 1/5)² = 9/25
Rút căn hai vế :
|(x + 1/5)| = 3/5
x = -4/5
hoặc
x = 2/5
2.
(x + 2) / 327 + (x + 3) / 326 + (x + 4) / 325 + (x + 5) / 324 + (x + 349) / 5 = 0
<=> (x + 2) / 327 +1+ (x + 3) / 326 +1+ (x + 4) / 325 +1+ (x + 5) / 324 +1+ (x + 349) / 5 -4 = 0
<=> (x+ 329)/327 + (x+ 329)/326 + (x+ 329)/325 + (x+ 329)//324 + (x+ 329)/5 =0
<=> (x+ 329).(1/327 + 1/ 326 + 1/325 + 1/324 +1/5) =0
Do (1/327 + 1/ 326 + 1/325 + 1/324 +1/5) >0 nên x+ 329 =0 => x= -329
Câu 1 chưa chắc đã đúng ( quên hết kiến thức lớp 6 rùi ) hihi
aaaaaaaa . chết rồi . cho mình sủa câu thứ nhất :
(x+1/5)2 + 17/25=26/25
( x + 1/5 ) 2 = 26/25 - 17/25
( x + 1/5 ) 2 = 3/52
x + 1/5 = 3/5
x = 2/5.
\(a,97\times327+327\times3\)
\(=327\times\left(97+3\right)\)
\(=327\times100\)
\(=32700\)
\(b,\frac{1}{7}\times\frac{4}{23}+\frac{1}{7}\times\frac{25}{23}+\frac{1}{7}\times\frac{17}{23}+5\times\frac{1}{7}\)
\(=\frac{1}{7}\times\left(\frac{4}{23}+\frac{25}{23}+\frac{17}{23}+5\right)\)
\(=\frac{1}{7}\times7\)
\(=1\)
a) 97 x 327 + 327 x 3
= (97 + 3) x 327
= 100 x 327 = 32700
b) \(\frac{1}{7}\times\frac{4}{23}+\frac{1}{7}\times\frac{25}{23}+\frac{1}{7}\times\frac{17}{23}+5\times\frac{1}{7}\)
\(=\frac{1}{7}\times\left(\frac{4}{23}+\frac{25}{23}+\frac{17}{23}+5\right)\)
\(=\frac{1}{7}\times7=\frac{7}{7}=1\)
a: 29+131+237+763
=160+1000
=1160
b: 65+327+15+73
=65+15+327+73
=80+400
=480
c: \(12+54:8-8\)
=12+3-8
=15-8
=7
d: \(45\cdot58+45\cdot42\)
\(=45\cdot\left(58+42\right)\)
\(=45\cdot100=4500\)
e: \(35\cdot34+35\cdot26+40\cdot35\)
\(=35\cdot\left(34+26+40\right)\)
\(=35\cdot100=3500\)
f: \(65\cdot25+65\cdot45+30\cdot65\)
\(=65\cdot\left(25+45+30\right)\)
\(=65\cdot100=6500\)
g: \(750:\left\lbrace32-\left\lbrack2^2+\left(5\cdot3^2-42\right)\right\rbrack\right\rbrace+100\)
\(=\frac{750}{32-\left\lbrack4+5\cdot9-42\right\rbrack}+100=\frac{750}{32-4-45+42}+100\)
\(=\frac{750}{28-3}+100\)
=750:25+100
=30+100
=130
h: \(\left\lbrace630:\left\lbrack16+3\cdot\left(6+3\cdot4\right)\right\rbrack\right\rbrace-1\)
\(=\frac{630}{16+3\cdot\left(6+12\right)}-1=\frac{630}{16+3\cdot18}-1\)
\(=\frac{630}{70}-1\)
=9-1=8
i: \(5871:\left\lbrack928-\left(247-82\right)\cdot5\right\rbrack+2175^0\)
\(=\frac{5871}{928-165\cdot5}+1\)
\(=\frac{5871}{928-825}+1=\frac{5871}{103}+1=57+1=58\)
k: \(375:\left\lbrace32-\left\lbrack4+\left(5\cdot3^2-42\right)\right\rbrack\right\rbrace-14\)
\(=\frac{375}{32-\left\lbrack4+5\cdot9-42\right\rbrack}-14\)
\(=\frac{375}{32-\left\lbrack4+45-42\right\rbrack}-14=\frac{375}{32-\left(4+3\right)}-14=\frac{375}{32-7}-14\)
\(=\frac{375}{25}-14\)
=15-14
=1
y x ( 26 + 327 ) = 327 x 7 + 26 x 7
y x 353 = ( 327 + 26 ) x 7
y x 353 = 353 x 7
y x 353 = 2472
y = 2471 : 353
y = 7