\(\frac{23.13+23}{14.47-14}\)
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Cho A = \(\frac{5}{4.3}\) + \(\frac{14}{3.23}\) + \(\frac{16}{23.13}\) + \(\frac{7}{13.46}\) . Tìm A
13.75 + 23.13 - 120
= 13.(75 + 23) - 120
= 13.98 - 120
= 1274 - 120
= 1154
\(\frac{2}{3}+\left(\frac{5}{14}+\frac{-25}{23}\right)-\left(\frac{-2}{23}-\frac{9}{14}\right)\) \(=\frac{2}{3}+\frac{5}{14}+\frac{-25}{23}+\frac{2}{23}+\frac{9}{14}\) \(=\frac{2}{3}+\left(\frac{5}{14}+\frac{9}{14}\right)+\left(\frac{-25}{23}+\frac{2}{23}\right)\) \(=\frac{2}{3}+1-1\) =\(\frac{2}{3}\)
1) \(\frac{2}{3}+\left(\frac{5}{14}+\frac{-25}{23}\right)-\left(\frac{-2}{23}-\frac{9}{14}\right)\)
= \(\frac{2}{3}+\frac{5}{14}+\frac{-25}{23}-\frac{-2}{23}+\frac{9}{14}\)
= \(\frac{-25}{23}+\frac{2}{23}+\left(\frac{5}{14}+\frac{9}{14}\right)+\frac{2}{3}\)
= \(-\frac{23}{23}+\frac{14}{14}+\frac{2}{3}\)
= \(-1+1+\frac{2}{3}\)
= 0 + \(\frac{2}{3}\)
= \(\frac{2}{3}\)
\(9\frac{8}{23}-\left(5\frac{7}{12}+14\frac{8}{23}\right)\)
\(< =>\frac{215}{23}-\left(\frac{67}{12}+\frac{330}{23}\right)\)
\(< =>\frac{215}{23}-\frac{5501}{276}\)
\(< =>\frac{-127}{12}\)
chuc ban hoc tot nhe >.<
\(A=\frac{1135}{23}-\left(\frac{167}{32}+\frac{330}{23}\right)=\frac{1135}{23}-\frac{330}{23}+\frac{167}{32}=35+\frac{167}{32}=\frac{1287}{32}\)
\(\frac{23.13+23}{14.47-14}=\frac{23.14}{14.46}=1128\)