nữa hẻ 

giúp mình đi:)))

a: \(\frac{2x}{3}:\frac{5}{6x^2}=\frac{2x}{3}\cdot\frac{6x^2}{5}=\frac{12x^3}{15}=\frac{4x^3}{5}\)

b: \(16x^2y^2:\left(-\frac{18x^2y^5}{5}\right)\)

\(=16x^2y^2\cdot\frac{-5}{18x^2y^5}=\frac{-80x^2y^2}{18x^2y^5}=\frac{-40}{9y^3}\)

c: \(\frac{25x^3y^5}{3}:15xy^2=\frac{25x^3y^5}{3\cdot15xy^2}=\frac{25x^3y^5}{45xy^2}=\frac59x^2y^3\)

d: \(\frac{x^2-y^2}{6x^2y}:\frac{x+y}{3xy}=\frac{\left(x-y\right)\left(x+y\right)}{6x^2y}\cdot\frac{3xy}{x+y}=\frac{x-y}{2x}\)

e: \(\frac{a^2+ab}{b-a}:\frac{a+b}{2a^2-2b^2}\)

\(=\frac{a\left(a+b\right)}{b-a}\cdot\frac{2\left(a^2-b^2\right)}{a+b}=\frac{a\cdot2\cdot\left(a-b\right)\left(a+b\right)}{b-a}=-2a\left(a+b\right)\)

f: \(\frac{x+y}{y-x}:\frac{x^2+xy}{3x^2-3y^2}\)

\(=\frac{-\left(x+y\right)}{x-y}\cdot\frac{3\left(x^2-y^2\right)}{x\left(x+y\right)}=\frac{-3\left(x-y\right)\left(x+y\right)}{x\left(x-y\right)}=\frac{-3\cdot\left(x+y\right)}{x}\)

g: \(\frac{1-4x^2}{x^2+4x}:\frac{2-4x}{3x}=\frac{\left(1-2x\right)\left(1+2x\right)}{x\left(x+4\right)}\cdot\frac{3x}{2\left(1-2x\right)}=\frac{3\left(1+2x\right)}{2\left(x+4\right)}\)

h: \(\frac{5x-15}{4x+4}:\frac{x^2-9}{x^2+2x+1}\)

\(=\frac{5\left(x-3\right)}{4\left(x+1\right)}\cdot\frac{\left(x+1\right)^2}{\left(x-3\right)\left(x+3\right)}=\frac{5\left(x+1\right)}{4\left(x+3\right)}\)

i: \(\frac{6x+48}{7x-7}:\frac{x^2-64}{x^2-2x+1}\)

\(=\frac{6\left(x+8\right)}{7\left(x-1\right)}\cdot\frac{\left(x-1\right)^2}{\left(x-8\right)\left(x+8\right)}=\frac{6\left(x-1\right)}{7\left(x-8\right)}\)

k: \(\frac{4x-24}{5x+5}:\frac{x^2-36}{x^2+2x+1}\)

\(=\frac{4\left(x-6\right)}{5\left(x+1\right)}\cdot\frac{\left(x+1\right)^2}{\left(x-6\right)\left(x+6\right)}=\frac{4\left(x+1\right)}{5\left(x+6\right)}\)

l: \(\frac{3x+21}{5x+5}:\frac{x^2-49}{x^2+2x+1}\)

\(=\frac{3\left(x+7\right)}{5\left(x+1\right)}\cdot\frac{\left(x+1\right)^2}{\left(x-7\right)\left(x+7\right)}=\frac{3\left(x+1\right)}{5\left(x-7\right)}\)

m: \(\frac{3-3x}{\left(1+x\right)^2}:\frac{6x^2-6}{x+1}\)

\(=\frac{-3\left(x-1\right)}{\left(x+1\right)^2}\cdot\frac{x+1}{6\left(x-1\right)\left(x+1\right)}=\frac{-3}{6\left(x+1\right)^2}=\frac{-1}{2\left(x+1\right)^2}\)

\(a,=x^2+x+4x+4=\left(x+1\right)\left(x+4\right)\\ b,=x^2+2x-3x-6=\left(x-3\right)\left(x+2\right)\\ c,=x^2-2x-3x+6=\left(x-2\right)\left(x-3\right)\\ d,=3\left(x^2-2x+5x-10\right)=3\left(x-2\right)\left(x+5\right)\\ e,=-3x^2+6x-x+2=\left(x-2\right)\left(1-3x\right)\\ f,=x^2-x-6x+6=\left(x-1\right)\left(x-6\right)\\ h,=4\left(x^2-3x-6x+18\right)=4\left(x-3\right)\left(x-6\right)\\ i,=3\left(3x^2-3x-8x+5\right)=3\left(x-1\right)\left(3x-8\right)\\ k,=-\left(2x^2+x+4x+2\right)=-\left(2x+1\right)\left(x+2\right)\\ l,=x^2-2xy-5xy+10y^2=\left(x-2y\right)\left(x-5y\right)\\ m,=x^2-xy-2xy+2y^2=\left(x-y\right)\left(x-2y\right)\\ n,=x^2+xy-3xy-3y^2=\left(x+y\right)\left(x-3y\right)\)

Bào quan riboxom trong chất tế bào có chức năng gì? 

Question 2: David has volunteered for 2 years

Question 3: I think collecting stamps is interesting

chị đc giáo viên nào like nhìu nhất zậy

mình làm câu 2, 3 rồi nhé

https://hoc24.vn/cau-hoi/anh-chi-giup-em-tieng-anh-7-cau-1-va-2-voi-a-chieu-e-thi-aem-cam-on-anh-chi-rat-nhieu-a.3054793966970

câu 1: Lan had a high fever, so she stayed home from school yesterday

Anh cj giúp e vs ạ

\(d,=\dfrac{3y}{5x\left(x-y\right)}\\ e,=\dfrac{5x\left(x+2\right)\left(2-x\right)}{4\left(x-2\right)\left(x+2\right)}=\dfrac{-5x}{4}\\ f,=\dfrac{3\left(x-6\right)\left(x+6\right)}{2\left(x+5\right)\left(6-x\right)}=\dfrac{-3\left(x+6\right)}{2\left(x+5\right)}\\ g,=\dfrac{3xy\left(x-3y\right)\left(x+3y\right)}{2x^2y^2\left(x-3y\right)}=\dfrac{3\left(x+3y\right)}{2xy}\\ h,=\dfrac{45x^2y\left(x-y\right)\left(x+y\right)}{10xy\left(y-x\right)}=\dfrac{-9x\left(x+y\right)}{2}\\ i,=\dfrac{12\left(a-b\right)\left(a+b\right)\left(a^2+ab+b^2\right)}{3\left(a+b\right)\left(a-b\right)^2}=\dfrac{4\left(a^2+ab+b^2\right)}{a-b}\)

e: \(=\dfrac{5\left(x+2\right)}{4\left(x-2\right)}\cdot\dfrac{-2\left(x-2\right)}{x+2}=\dfrac{-10}{4}=-\dfrac{5}{2}\)

5.8/7;10/9;4/5;3/5;1/2
6.x=2
7.=

Em hãy học tốt để lên lớp 6 nhé, lớp 6 có nhiều thử thách lắm :D

\(\left(x-1\right)-7=4\left(-1-x\right)\\ -7x+7=-4-4x\\ -7x-7+4+4x=0\\ -3x-3=0\\ -3\left(x-1\right)=0\\ x-1=0\\ x=1\)

\(\dfrac{x-2}{4}=\dfrac{-1-x}{-7}\)

\(\dfrac{-7\left(x-2\right)}{-28}=\dfrac{4\left(-1-x\right)}{-28}\)

\(-7\left(x-2\right)=4\left(-1-x\right)\)

\(-7x+14=-4-4x\)

\(-7x+4x=-4-14\)

\(-3x=-18\)

\(x=\dfrac{-18}{-3}\)

\(x=6\)