Tìm x:
x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=45
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\(\Leftrightarrow x^3+2x^2-3x-x^3-3x^2=-4\)
\(\Leftrightarrow x^2+3x-4=0\)
=>(x+4)(x-1)=0
=>x=-4 hoặc x=1
\(x=\dfrac{4}{5}\times\dfrac{4}{3}\)
\(x=\dfrac{16}{15}\)
-----------------------
\(x=\dfrac{5}{9}\times\dfrac{3}{8}\)
\(x=\dfrac{5}{24}\)
x * 2 + x * 3 + x * 4 + x = 2130
x * (2 + 3 + 4 + 1) = 2130
x * 10 = 2130
x = 2130 : 10 = 213
Bài 1:
a: \(\frac{x^2+x+4}{2}+\frac{x^2+x+7}{3}=\frac{x^2+x+13}{5}+\frac{x^2+x+16}{6}\)
=>\(\left(\frac{x^2+x+4}{2}-3\right)+\left(\frac{x^2+x+7}{3}-3\right)=\left(\frac{x^2+x+13}{5}-3\right)+\left(\frac{x^2+x+16}{6}-3\right)\)
=>\(\frac{x^2+x-2}{2}+\frac{x^2+x-2}{3}=\frac{x^2+x-2}{5}+\frac{x^2+x-2}{6}\)
=>\(\left(x^2+x-2\right)\left(\frac12+\frac13-\frac15-\frac16\right)=0\)
=>\(x^2+x-2=0\)
=>(x+2)(x-1)=0
=>\(\left[\begin{array}{l}x+2=0\\ x-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=-2\\ x=1\end{array}\right.\)
b: \(\frac{2}{x^2+4x+3}+\frac{5}{x^2+11x+24}+\frac{2}{x^2+18x+80}=\frac{9}{25}\)
=>\(\frac{2}{\left(x+1\right)\left(x+3\right)}+\frac{5}{\left(x+3\right)\left(x+8\right)}+\frac{2}{\left(x+8\right)\left(x+10\right)}=\frac{9}{25}\)
=>\(\frac{1}{x+1}-\frac{1}{x+3}+\frac{1}{x+3}-\frac{1}{x+8}+\frac{1}{x+8}-\frac{1}{x+10}=\frac{9}{25}\)
=>\(\frac{1}{x+1}-\frac{1}{x+10}=\frac{9}{25}\)
=>\(\frac{x+10-x-1}{\left(x+1\right)\left(x+10\right)}=\frac{9}{25}\)
=>\(\frac{9}{\left(x+1\right)\left(x+10\right)}=\frac{9}{25}\)
=>(x+1)(x+10)=25
=>\(x^2+11x+10-25=0\)
=>\(x^2+11x-14=0\)
=>\(x^2+11x+\frac{121}{4}=44,25\)
=>\(\left(x+\frac{11}{2}\right)^2=\frac{177}{4}\)
=>\(x+\frac{11}{2}=\pm\sqrt{\frac{177}{2}}\)
=>\(x=-\frac{11}{2}\pm\frac{\sqrt{177}}{2}\)
x *6+ ( 1 + 2 + 3 + 4 + 5 ) = 45
x*6=45-15=30
x=30:6=5
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