Tìm số nguyên x biết:
a)
b)
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a,-4/7=x/21
-12/21 = x/21
x= -12
b,(x-3)/15=1/-5
x - 3 = -1/5 * 15
x - 3 = -3
x = 0
c,.(3x+8)/-12=-5/30
=> 3x + 8 = 2
=> 3x=-6
=>x=-2
B3 a) x=4 b) x=-7 c) x=5 d) x=4
B2 a) -3+ -2+ -1+0+1+2+3+4=4
b) -6+ -5+ -4+ -3+ -2+ -1+0+1+2+3+4=-11
c) -18+-17+-16+-15+-14+-13+-12+-11+-10+-9+-8+-7+-6+-5+-4+3+-2+-1+0+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19=19
a) 4 . x + 15 = - 5
⇒ 4 . x = - 5 – 15
⇒ 4 . x = - 20
⇒ x = - 20 : 4
⇒ x = - 5.
Vậy x = - 5.
b) (- 270) : x – 20 = 70.
⇒ (- 270) : x = 70 + 20
⇒ (- 270) : x = 90
⇒ x = (- 270) : 90
⇒ x = - 3
Vậy x = - 3
a: Sửa đề: -x+20=-(-25)-8
=>-x+20=25-8
=>20-x=17
=>x=20-17
=>x=3
b: x+(-45)=-62+17
=>x-45=-45
=>x=-45+45
=>x=0
Bài 4:
a: |x-2|=0
=>x-2=0
=>x=2
b: |x+3|=1
=>\(\left[\begin{array}{l}x+3=1\\ x+3=-1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=1-3=-2\\ x=-1-3=-4\end{array}\right.\)
c: \(-3\left|4-x\right|=-9\)
=>|4-x|=3
=>|x-4|=3
=>\(\left[\begin{array}{l}x-4=3\\ x-4=-3\end{array}\right.\Rightarrow\left[\begin{array}{l}x=7\\ x=1\end{array}\right.\)
d: |2x+1|=-2
mà -2<0<=|2x+1|
nên x∈∅
Bài 5:
a: \(\left(x+3\right)^2=36\)
=>\(\left[\begin{array}{l}x+3=6\\ x+3=-6\end{array}\right.\Rightarrow\left[\begin{array}{l}x=6-3=3\\ x=-6-3=-9\end{array}\right.\)
b: \(\left(x+5\right)^2=100\)
=>\(\left[\begin{array}{l}x+5=10\\ x+5=-10\end{array}\right.\Rightarrow\left[\begin{array}{l}x=10-5=5\\ x=-10-5=-15\end{array}\right.\)
c: \(\left(2x-4\right)^2=0\)
=>2x-4=0
=>2x=4
=>x=2
d: \(\left(x-1\right)^3=27\)
=>x-1=3
=>x=4
a: =>19/23>19/x>19/29
=>\(x\in\left\{24;25;26;27;28\right\}\)
b: =>88/132<88/x<88/128
=>132>x>128
=>\(x\in\left\{131;130;129\right\}\)
c: =>\(\left\{{}\begin{matrix}\dfrac{4}{x}-\dfrac{x}{8}< 0\\\dfrac{x}{8}-\dfrac{5}{x}< 0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{32-x^2}{8x}< 0\\\dfrac{x^2-40}{8x}< 0\end{matrix}\right.\)
=>32<x^2<40
=>x=6
a) 2 5 + − 3 7 = x 70 ⇔ − 1 35 = x 70 ⇔ − 2 70 = x 70 ⇔ x = − 2
b) 5 6 + − 19 30 = 1 x ⇔ 6 30 = 1 x ⇔ 1 5 = 1 x ⇔ x = 5