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\(1.\dfrac{-7}{18}+\dfrac{-5}{12}-\dfrac{-13}{18}\text{=}\left(\dfrac{-7}{18}-\dfrac{-13}{18}\right)+\dfrac{-5}{12}\text{=}\dfrac{1}{3}+\dfrac{-5}{12}\text{=}\dfrac{-1}{12}\)
\(2.\dfrac{-13}{17}+\dfrac{-13}{21}+\dfrac{-4}{17}\text{=}\left(\dfrac{-13}{17}+\dfrac{-4}{17}\right)+\dfrac{-13}{21}\text{=}-1+\dfrac{-13}{21}\text{=}\dfrac{-34}{21}\)
\(3.\dfrac{-13}{10}-\dfrac{-4}{13}+\dfrac{-11}{10}\text{=}\dfrac{-12}{5}-\dfrac{-4}{13}\text{=}\dfrac{-136}{65}\)
\(4.\dfrac{13}{17}\times\left(\dfrac{-4}{5}+\dfrac{-3}{4}\right)\text{=}\dfrac{13}{17}\times\dfrac{-31}{20}\text{=}\dfrac{-403}{340}\)
\(5.\left(\dfrac{-5}{12}\times\dfrac{-9}{20}\right)\times\dfrac{-7}{17}\text{=}\dfrac{3}{16}\times\dfrac{-7}{17}\text{=}\dfrac{-21}{272}\)
\(6.\dfrac{11}{23}\times\left(\dfrac{5}{9}+\dfrac{17}{9}-\dfrac{13}{9}\right)\text{=}\dfrac{11}{23}\times1\text{=}\dfrac{11}{23}\)
Bài làm
13 - 12 + 11 + 10 -9 +8 - 7 - 6 + 5 - 4 + 3 +2 -1
= 1 + 11+ 1 + 1 - 6 + 1 + 3 + 1
= 15 - 11
= 4
# Chúc bạn học tốt #
13-12+11+10-9+8-7-6+5-4+3+2-1
=(13-12)+(11-6)+(10-9)+(8-7)+(5-4)+(2-1)+3
=1+5+1+1+1+1+3
=13
mn vô đây xem thằng Phạm Việt Đức chửi tớ nek
Giúp tôi giải toán - Hỏi đáp, thảo luận về toán học - Học toán với OnlineMath
13-12+11+10-9+8-7-6+5-4+3+2-1
=13-(12+1) -(11+2)-(10+3)-(9+4)-(8+5) +(7+6)
=13-13-13-13-13-13+13
=0-0-0-0-0-0+13
=0+13
=13
= ( 13 -12 ) + 11 + ( 10 - 9 ) + ( 8 - 7-6 + 5 ) + ( 3 + 2 - 4 ) -1
= 1 + 11 + 1 + 0 + 1 - 1
= 13 + 0
= 13
13 - 12 + 11 + 10 - 9 + 8 - 7 - 6 + 5 - 4 + 3 + 2 - 1 = 9
14 + 13 -12 + 11 + 10 - 9 + 8 - 7 - 6 + 5 - 4 + 3 + 2 - 1 = 27
a: \(B=\frac12-\left\lbrack\frac38+\left(-\frac74\right)\right\rbrack\)
\(=\frac12-\frac38+\frac74\)
\(=\frac48-\frac38+\frac{14}{8}=\frac{15}{8}\)
b: \(-\frac{4}{12}-\left(-\frac{13}{39}-0,25\right)+0,75\)
\(=-\frac13+\frac13+0,25+0,75\)
=0,25+0,75
=1
c: \(\frac12-\frac13+\frac{1}{23}+\frac16\)
\(=\left(\frac12-\frac13+\frac16\right)+\frac{1}{23}\)
\(=\left(\frac16+\frac16\right)+\frac{1}{23}=\frac13+\frac{1}{23}=\frac{26}{69}\)
d: \(\left(-\frac{13}{7}-\frac49\right)-\left(-\frac{10}{7}-\frac49\right)\)
\(=-\frac{13}{7}-\frac49+\frac{10}{7}+\frac49\)
\(=-\frac{13}{7}+\frac{10}{7}=-\frac37\)
e: \(\left(\frac78-\frac52+\frac47\right)-\left(-\frac37+1-\frac{13}{8}\right)\)
\(=\frac78-\frac52+\frac47+\frac37-1+\frac{13}{8}\)
\(=\frac{20}{8}-\frac52=0\)
f: \(-\frac37+\left(3-\frac34\right)-\left(2,25-\frac{10}{7}\right)\)
\(=-\frac37+3-\frac34-2,25+\frac{10}{7}\)
\(=\frac77+0,75-\frac34\)
=1
g: \(\left(\frac53-\frac37+9\right)-\left(2+\frac57-\frac23\right)+\left(\frac87-\frac43-10\right)\)
\(=\frac53-\frac37+9-2-\frac57+\frac23+\frac87-\frac43-10\)
\(=\left(\frac53+\frac23-\frac43\right)+\left(-\frac37-\frac57+\frac87\right)+\left(9-2-10\right)\)
\(=\frac33+7-10=1-3=-2\)
\(\dfrac{4^{10}.9^6+3^{12}.8^5}{6^{13}.4-2^{16}.3^{12}}\)
\(=\dfrac{\left(2^2\right)^{10}.\left(3^2\right)^6+3^{12}.\left(2^3\right)^5}{\left(2.3\right)^{13}.2^2-2^{16}.3^{12}}\)
\(=\dfrac{2^{20}.3^{12}+3^{12}.2^{15}}{2^{13}.3^{13}.2^2-2^{16}.3^{12}}\)
\(=\dfrac{2^{20}.3^{12}+3^{12}.2^{15}}{2^{15}.3^{13}-2^{16}.3^{12}}\)
\(=\dfrac{2^{15}.3^{12}.\left(2^5+1\right)}{2^{15}.3^{13}.\left(3-2\right)}\)
\(=\dfrac{2^5+1}{3-2}\)
\(=\dfrac{32+1}{1}=33\)
a. -2015 + ( -21 + 75 + 2015 ) = 0 + ( -21 ) + 75 = 54
b. 13 - 12 + 11 + 10 - 9 + 8 - 7 - 6 + 5 - 4 + 3 + 2 -1 = 1 + 11 + 1 + (-5) + 1 + 3 + 1 = 13
a) 0. b) 5 8
c) 0 . d) 0 .