Đáp án là D

Ta có: x - (90 - 198) = |-78|

     ⇔ x - 90 + 198 = 78

     ⇔ x = 78 + 90 - 198

     ⇔ x = -30

a) (x - 78) . 26 = 40

=>x-78 = 40 : 26 = 20/13

=> x = 78 + 20/13

=> x = 1034/13

b) 39 . (x-5) =39

=>x-5=39:39=1

=>x=1+5=6

c) 30- ( 52 - x) =90

=>30-52+x=90

=>-22+x=90

=>x=90-(-22)

=>x=112

d) (x-12) : 5 =2

=>x-12=2.5=10

=>x=10+12=22

a, (x-78).26=40

=> (x-78)=40:26

=> x-78=40/26

=> x=40/26+78

=> x=1034/13

b, 39.(x-5)=39

=> x-5=39:39

=> x-5=1

=> x=1+5

=> x=6

c, 30-(52-x)=90

=> 52-x=30-90

=> 52-x=-60

=> x=52-(-60)

=> x=112

d, (x-12):5=2

=> x-12=2.5

=> x-12=10

=> x=10+12

=> x=22

B

B

\(Ư\left(30\right)=\left\{1;2;3;5;6;10;15;30\right\}\\ \Rightarrow x=5\left(B\right)\\ B\left(8\right)=\left\{0;8;16;24;32;...\right\}\\ \Rightarrow x=24\left(B\right)\)

a) x ϵ {21; 24; 27; 30; 33; 36; 39; 42; 45; 48; 51}.

b) x ϵ {10;15;30}.      

c) x ϵ {54;57;60;63;66;69;72;75;78}.

d) x ϵ {1;2;3;5;6}. 

a) 467 + x = 877 – 162

467 + x = 715

x = 715 – 467

x = 248

b) x – 214 = 61 + 345

x – 214 = 406

x = 406 + 214

x = 620

c) x : 5 = 10 × 2

x : 5 = 20

x = 20 × 5

x = 100

d) x × 4 = 30 – 10

x × 4 = 20

x = 20 : 4

x = 5

Bài 3:

a: \(S=1+5^2+5^4+\cdots+5^{200}\)

=>25S=\(5^2+5^4+5^6+\cdots+5^{202}\)

=>25S-S=\(5^2+5^4+\cdots+5^{202}-1-5^2-\cdots-5^{200}\)

=>24S=\(5^{202}-1\)

=>\(S=\frac{5^{202}-1}{24}\)

b: \(4^{30}=\left(2^2\right)^{30}=2^{60}=2^{30}\cdot2^{30}=8^{10}\cdot4^{15}\)

\(3\cdot24^{10}=3\cdot3^{10}\cdot8^{10}=8^{10}\cdot3^{11}\)

mà \(4^{15}>3^{11}\)

nên \(4^{30}>3\cdot24^{10}\)

=>\(2^{30}+3^{30}+4^{30}>3\cdot24^{10}\)

Bài 2:

a: |2x-3|>5

=>\(\left[\begin{array}{l}2x-3>5\\ 2x-3<-5\end{array}\right.\Rightarrow\left[\begin{array}{l}2x>8\\ 2x<-2\end{array}\right.\Rightarrow\left[\begin{array}{l}x>4\\ x<-1\end{array}\right.\)

c: |3x-1|<=7

=>-7<=3x-1<=7

=>-6<=3x<=8

=>\(-2\le x\le\frac83\)

d: \(\left|3x-5\right|+\left|2x+3\right|=7\) (1)

TH1: \(x<-\frac32\)

=>2x+3<0; 3x-5<0

(1) sẽ trở thành: -2x-3-3x+5=7

=>-5x+2=7

=>-5x=5

=>x=-1(loại)

TH2: -3/2<=x<5/3

=>2x+3>=0; 3x-5<0

(1) sẽ trở thành: 2x+3-3x+5=7

=>-x+8=7

=>-x=-1

=>x=-1(nhận)

TH3: x>=5/3

=>2x+3>0; 3x-5>=0

(1) sẽ trở thành: 2x+3+3x-5=7

=>5x-2=7

=>5x=9

=>x=9/5(nhận)